Problem 60
Question
Factor each four-term polynomial by grouping. If this is not possible, write "not factorable by grouping." $$ x^{3}+4 x^{2}+3 x+12 $$
Step-by-Step Solution
Verified Answer
The polynomial factors as \((x^{2}+3)(x+4)\).
1Step 1: Group Terms
To factor by grouping, divide the polynomial into two groups. For the expression \( x^{3} + 4x^{2} + 3x + 12 \), group the terms as follows: \( (x^{3} + 4x^{2}) + (3x + 12) \).
2Step 2: Factor Each Group
Now, factor out the greatest common factor (GCF) from each grouped term: - For \( x^{3} + 4x^{2} \), the GCF is \( x^{2} \). Factoring gives \( x^{2}(x + 4) \).- For \( 3x + 12 \), the GCF is \( 3 \). Factoring gives \( 3(x + 4) \).
3Step 3: Combine Common Factors
Notice that both groups have a common binomial factor \( (x + 4) \). Factor this out: \( x^{2}(x + 4) + 3(x + 4) = (x^{2} + 3)(x + 4) \).
4Step 4: Write Final Factored Form
The polynomial \( x^{3} + 4x^{2} + 3x + 12 \) is fully factored and the factored form is \( (x^{2} + 3)(x + 4) \).
Key Concepts
Factoring by GroupingGreatest Common Factor (GCF)Binomial Factors
Factoring by Grouping
Factoring by grouping is a strategic method used to factor polynomials, particularly useful when dealing with four-term polynomials. The goal is to pair the terms into groups that can each be factored separately before combining them to simplify the expression. This method relies on recognizing patterns and ensuring groups share similar characteristics that allow for simplification.
Here's how to approach factoring by grouping:
Here's how to approach factoring by grouping:
- Identify appropriate pairs of terms: Start by dividing the polynomial into two pairs. For example, in the polynomial \(x^{3} + 4x^{2} + 3x + 12\), you may group it as \((x^{3} + 4x^{2}) + (3x + 12)\).
- Factor each group: In each identified group, factor out the greatest common factor (GCF).
- Combine like terms: After factoring each group, look for any common binomial factors, then factor them out to simplify further.
Greatest Common Factor (GCF)
The Greatest Common Factor (GCF) is an essential concept when it comes to factoring, as it is the largest factor that divides all terms in a group without leaving a remainder.
To find and factor the GCF:
To find and factor the GCF:
- List out factors: Identify the smallest factors and their powers for each term in a group.
- Select the highest shared factor: Choose the factor that appears in all terms with the lowest power.
- Factor it out: Extract this factor to simplify the group, as seen in the grouping \(x^{3} + 4x^{2}\), where \(x^{2}\) is the GCF, resulting in \(x^{2}(x + 4)\).
Binomial Factors
Binomial factors are expressions consisting of two terms that appear repeatedly across different groups within a polynomial expression. Identifying and extracting binomial factors is a key step in simplifying and factoring polynomials by grouping.
In the example \((x^{3} + 4x^{2}) + (3x + 12)\), after factoring out the GCF from each group, we obtain \(x^{2}(x + 4) + 3(x + 4)\). Here, \((x + 4)\) is a common binomial factor.
Steps to recognize and factor out binomial factors:
In the example \((x^{3} + 4x^{2}) + (3x + 12)\), after factoring out the GCF from each group, we obtain \(x^{2}(x + 4) + 3(x + 4)\). Here, \((x + 4)\) is a common binomial factor.
Steps to recognize and factor out binomial factors:
- After extracting GCF, observe if a binomial appears in each factored group.
- If found, factor out this common term as seen here, resulting in \((x^{2} + 3)(x + 4)\).
Other exercises in this chapter
Problem 59
Solve each equation. $$ x^{2}+14 x+49=0 $$
View solution Problem 60
Factor. $$ 8-z^{3} $$
View solution Problem 60
Factor each trinomial completely. Some of these trinomials contain a greatest common factor (other than 1). Don't forget to factor out the GCF first. $$ 3 x^{6}
View solution Problem 60
Factor each trinomial completely. See Examples 1 through 7. \(24 y^{2} x+7 y x-5 x\)
View solution