Problem 60
Question
Determine whether each statement makes sense or does not make sense, and explain your reasoning. Partial fraction decomposition involves finding a single rational expression for a given sum or difference of rational expressions.
Step-by-Step Solution
Verified Answer
The statement does not make sense because partial fraction decomposition involves breaking down a single complex fraction into the sum or difference of simpler fractions, not the other way around.
1Step 1: Understanding the Statement
Read and understand the given statement. Partial fraction decomposition involves finding a single rational expression for a given sum or difference of rational expressions.
2Step 2: Analysing the statement
Compare the concept defined in the statement with your knowledge of partial fraction decomposition. Recognize that the defining process is incorrectly described.
3Step 3: Reasoning and Conclusion
Since partial fraction decomposition usually involves breaking down a single complex fraction into the sum or difference of simpler fractions, the given statement does not make sense. The process is incorrectly defined here.
Key Concepts
Rational ExpressionsAlgebraic TechniquesComplex Fractions
Rational Expressions
A rational expression is essentially a fraction in which both the numerator (the top part) and the denominator (the bottom part) are polynomials. For example, \( \frac{x^2 - 1}{x - 1} \) is a rational expression because \( x^2 - 1 \) and \( x - 1 \) are both polynomials.
When dealing with rational expressions, simplification can often involve factoring polynomials and reducing common factors. However, some rational expressions are too complex to be simplified easily, and that's where partial fraction decomposition comes in.
\( \frac{x}{(x+2)(x-1)} \) might look intimidating at first, but it is just another rational expression that can be expressed as a sum of simpler fractions through partial fraction decomposition. One common misconception, as seen in the original exercise, is that partial fractions involve combining simple fractions into a complex one; however, it’s actually the reverse process.
When dealing with rational expressions, simplification can often involve factoring polynomials and reducing common factors. However, some rational expressions are too complex to be simplified easily, and that's where partial fraction decomposition comes in.
\( \frac{x}{(x+2)(x-1)} \) might look intimidating at first, but it is just another rational expression that can be expressed as a sum of simpler fractions through partial fraction decomposition. One common misconception, as seen in the original exercise, is that partial fractions involve combining simple fractions into a complex one; however, it’s actually the reverse process.
Algebraic Techniques
Algebraic techniques are the toolkit for manipulating equations and expressions in mathematics. They include a range of methods, like distributing, combining like terms, factoring, and rationalizing denominators, among others.
When it comes to partial fraction decomposition, one employs these algebraic techniques with the aim of breaking down complex rational expressions into simpler ones.
When it comes to partial fraction decomposition, one employs these algebraic techniques with the aim of breaking down complex rational expressions into simpler ones.
Factorization
As a foundational technique, factorization allows us to write a polynomial as a product of its factors, which is a critical step in partial fraction decomposition. Consider \( x^2 - 1 = (x + 1)(x - 1) \). Once we factor the denominator of a complex fraction, we can investigate the potential simpler fractions that combine to form it.Equating Coefficients
Another technique is equating coefficients, where we solve for the unknowns in the simpler fractions by matching coefficients from both sides of an equation. It's a bit like solving a puzzle where each piece must fit perfectly to complete the overall picture.Complex Fractions
Complex fractions, not to be confused with complex numbers, are fractions where both the numerator and the denominator contain fractions themselves or are polynomials of a degree higher than one. An example of a complex fraction is \( \frac{\frac{1}{x} + \frac{1}{x+1}}{1 - \frac{2}{x}} \).
These complex constructs can be quite daunting to simplify due to their multi-layered nature. The goal of working with complex fractions, in general, is to simplify them so that they're more manageable and understandable.
Simplification often involves finding a common denominator for all the fractional parts and then combining them before performing any necessary algebraic operations. Partial fraction decomposition takes a complex fraction and breaks it down into simpler rational expressions that are easier to integrate or differentiate, which is particularly useful in calculus. The initial belief that partial fraction decomposition aims to create a single rational expression from simpler ones is, therefore, a misunderstanding.
These complex constructs can be quite daunting to simplify due to their multi-layered nature. The goal of working with complex fractions, in general, is to simplify them so that they're more manageable and understandable.
Simplification often involves finding a common denominator for all the fractional parts and then combining them before performing any necessary algebraic operations. Partial fraction decomposition takes a complex fraction and breaks it down into simpler rational expressions that are easier to integrate or differentiate, which is particularly useful in calculus. The initial belief that partial fraction decomposition aims to create a single rational expression from simpler ones is, therefore, a misunderstanding.
Other exercises in this chapter
Problem 58
Find the length and width of a rectangle whose perimeter is 40 feet and whose area is 96 square feet.
View solution Problem 59
In Exercises 27–62, graph the solution set of each system of inequalities or indicate that the system has no solution. $$\left\\{\begin{array}{l} x \geq 0 \\ y
View solution Problem 60
In Exercises 27–62, graph the solution set of each system of inequalities or indicate that the system has no solution. $$\left\\{\begin{array}{l} x \geq 0 \\ y
View solution Problem 61
Describe a number of business ventures. For each exercise, a. Write the cost function, \(C\). b. Write the revenue function, \(R\). c. Determine the break-even
View solution