Problem 60
Question
Calculate the concentration of an aqueous HBr solution that has \(\mathrm{pH}=4.25 .\) HBr is a strong acid.
Step-by-Step Solution
Verified Answer
The concentration of the aqueous HBr solution with a given pH of 4.25 can be found using the formula \([H^+] = 10^{-pH}\). By substituting the pH value into the formula, we find that the concentration of the HBr solution is approximately \(5.623 \times 10^{-5} \,M\).
1Step 1: Understanding the pH formula
The pH of a solution is calculated using the formula:
pH \( = -\log_{10} [H^+] \)
Here, pH is the measure of the acidity of a solution, and \([H^+]\) represents the concentration of \(H^+\) ions in the solution.
Since the given solution is HBr (a strong acid), it will dissociate completely into \(H^+\) and \(Br^-\) ions:
HBr \( \rightarrow H^+ + Br^- \)
The concentration of \(H^+\) ions will be equal to the concentration of HBr.
2Step 2: Solve for the concentration of \(H^+\) ions
We are given the pH value of 4.25 and we need to find the concentration of \(H^+\) ions in the solution. We can use the pH formula and solve for the \([H^+]\) concentration:
\( 4.25 = -\log_{10} [H^+] \)
3Step 3: Rearranging the pH formula
To find \([H^+]\), we need to rearrange the pH formula:
\([H^+] = 10^{-pH} \)
4Step 4: Substituting the given pH value in the formula
Now substitute the given pH value (4.25) into the formula to find the \([H^+]\) concentration:
\[ [H^+] = 10^{-4.25} \]
5Step 5: Calculating the concentration of \(H^+\) ions
Using a calculator, find the concentration of \(H^+\) ions:
\([H^+] \approx 5.623 \times 10^{-5} \,M \)
6Step 6: Finding the concentration of HBr
Since the concentration of \(H^+\) ions is equal to the concentration of HBr in the solution (because HBr is a strong acid and dissociates completely), the concentration of the HBr solution is:
\[ [HBr] = [H^+] = 5.623 \times 10^{-5} \,M \]
So the concentration of the HBr solution is approximately \(5.623 \times 10^{-5} \,M\).
Key Concepts
pH calculationstrong acidschemical dissociation
pH calculation
The concept of pH is vital in understanding the acidity or basicity of a solution. pH is a logarithmic scale that measures the concentration of hydrogen ions (\([H^+]\)) in a solution. The formula to calculate pH is:\[pH = -\log_{10} [H^+]\]This equation indicates that a lower pH value corresponds to a higher concentration of \([H^+]\) ions, meaning the solution is more acidic. Conversely, a higher pH value indicates a lower \([H^+]\) concentration, making the solution more basic. When solving for \([H^+]\) given a specific pH value, rearrange the equation to:\[[H^+] = 10^{-\mathrm{pH}}\]This rearrangement helps you find the concentration of hydrogen ions when the pH is known. If the pH is 4.25, the concentration of \([H^+]\) ions can be calculated using this formula. Understanding pH calculations is essential in various fields, such as chemistry, biology, and environmental science.
strong acids
Strong acids are a category of acids that completely dissociate in water, releasing all of their hydrogen ions (\(H^+\)) into the solution. This complete dissociation is the key characteristic that defines a strong acid, and it results in a high concentration of \(H^+\) ions compared to weak acids that partially dissociate.Some common examples of strong acids include:
- Hydrochloric acid (\(HCl\))
- Hydrobromic acid (\(HBr\))
- Sulfuric acid (\(H_2SO_4\))
- Nitric acid (\(HNO_3\))
chemical dissociation
Chemical dissociation refers to the process where molecules break apart into smaller constituents, such as ions. In the case of acids, dissociation typically involves the breaking of the bond between hydrogen and another element, resulting in the release of hydrogen ions (\(H^+\)).For example, an acid like hydrobromic acid (\(HBr\)) dissociates in water:\[HBr \rightarrow H^+ + Br^-\]In this dissociation reaction, HBr splits into hydrogen ions (\(H^+\)) and bromide ions (\(Br^-\)). The extent of dissociation depends on whether the acid is strong or weak:
- **Strong acids** dissociate completely, meaning 100% of the acid molecules split into ions.
- **Weak acids** dissociate partially, meaning only a fraction of the acid molecules split to produce ions.
Other exercises in this chapter
Problem 58
Calculate the \(\mathrm{pH}\) of each of the following solutions containing a strong acid in water. a. \(2.0 \times 10^{-2} M \mathrm{HNO}_{3}\) b. \(4.0 \mathr
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Calculate the concentration of an aqueous HI solution that has \(\mathrm{pH}=2.50 .\) HI is a strong acid.
View solution Problem 61
How would you prepare \(1600 \mathrm{mL}\) of a \(\mathrm{pH}=1.50\) solution using concentrated (12 \(M\) ) HCl?
View solution Problem 62
A solution is prepared by adding 50.0 mL concentrated hydrochloric acid and \(20.0 \mathrm{mL}\) concentrated nitric acid to 300 mL water. More water is added u
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