Problem 60
Question
BIO Changing Your Center of Mass. To keep the calculations fairly simple, but still reasonable, we shall model a human leg that is 92.0 \(\mathrm{cm}\) long (measured from the hip joint) by assuming that the upper leg and the lower leg (which includes the foot) have equal lengths and that each of them is uniform. For a 70.0 -kg person, the mass of the upper leg would be \(8.60 \mathrm{kg},\) while that of the lower leg (including the foot) would be 5.25 \(\mathrm{kg} .\) Find the location of the center of mass of this leg, relative to the hip joint, if it is (a) stretched out horizontally and (b) bent at the knee to form a right angle with the upper leg remaining horizontal.
Step-by-Step Solution
Verified Answer
(a) 40.4 cm from the hip joint; (b) 31.7 cm from the hip joint.
1Step 1: Understanding the Problem
We have two scenarios: a horizontally stretched leg and a bent leg forming a right angle at the knee. We will calculate the center of mass for both scenarios using the given masses and distances.
2Step 2: Calculate Center of Mass in Horizontal Position
In the horizontal position, the upper leg and lower leg are aligned horizontally. The center of mass of the upper leg, which is a uniform rod of mass 8.60 kg and length 46.0 cm (half of the total leg length), is located at its midpoint, 23.0 cm from the hip joint. Similarly, the center of mass of the lower leg (mass 5.25 kg) is also at its midpoint, 23.0 cm beyond the end of the upper leg, or 69.0 cm from the hip (23.0 cm + 46.0 cm). Calculate the center of mass by using the formula:\[X_{cm} = \frac{(m_1 \cdot x_1) + (m_2 \cdot x_2)}{m_1 + m_2}\]where \(m_1\) and \(m_2\) are the masses of the upper and lower legs, and \(x_1\) and \(x_2\) are their respective distances from the hip joint.
3Step 3: Substitution in Formula for Horizontal Position
Substitute the values: \(m_1 = 8.60\, \text{kg}, x_1 = 23.0\, \text{cm}, m_2 = 5.25\, \text{kg}, x_2 = 69.0\, \text{cm}\) into the formula:\[X_{cm} = \frac{(8.60 \times 23.0) + (5.25 \times 69.0)}{8.60 + 5.25}\]
4Step 4: Calculate Center of Mass in Bent Position
In the bent position, the upper leg remains horizontal, but the lower leg is vertical. The center of mass of the upper leg is still at 23 cm from the hip joint. The center of mass of the lower leg (still located at its midpoint) is now vertically below the knee joint, which is 46.0 cm from the hip joint horizontally. Therefore, the x-distance of the lower leg's center of mass remains 46.0 cm, and the y-distance is half of the lower leg's length, 23.0 cm. The overall center of mass is determined by considering these coordinates. For simplicity, we need only the x-component:\[X_{cm} = \frac{(m_1 \cdot 23.0) + (m_2 \cdot 46.0)}{m_1 + m_2}\]
5Step 5: Calculation and Conclusion
Calculate the values from the formulas given in Steps 3 and 4. For the horizontal leg, substitute and solve:\[X_{cm} = \frac{197.8 + 362.25}{13.85} = \frac{560.05}{13.85} \approx 40.4\, \text{cm}\]For the bent leg:\[X_{cm} = \frac{197.8 + 241.5}{13.85} = \frac{439.3}{13.85} \approx 31.7\, \text{cm}\]
6Step 6: Verification and Error Checking
Review each calculation and ensure the correct values were used in each step. Address any potential rounding errors or calculation mistakes. Ensure understanding that these calculations provide the x-component of the center of mass, which is relevant for horizontal displacements.
Key Concepts
Human AnatomyPhysics of MotionMechanics
Human Anatomy
In human anatomy, understanding the body's structure is crucial when analyzing balance and movement. The human leg is fascinating because it not only supports the body during standing but also provides movement capabilities like walking and running. When studying the mechanics of the leg, such as in this exercise, we often simplify its structure for ease of calculation.
- The upper leg, or femur, extends from the hip to the knee. In this example, it is simplified to be 46 cm long, which is half the 92 cm total leg length.
- The lower leg encompasses the tibia and fibula down to the foot. It's similarly modeled with a length of 46 cm.
- Each segment's mass is critical for calculating the center of mass, with the upper leg being 8.60 kg and the lower leg, including the foot, 5.25 kg.
Physics of Motion
The physics of motion is about understanding how objects move and interact with forces. Calculating the center of mass is particularly important in biomechanics to predict how the body achieves motion.
For a leg stretched out horizontally:
For a leg stretched out horizontally:
- The center of mass (COM) must be calculated by considering both mass and distance.
- The formula used is \[X_{cm} = \frac{(m_1 \cdot x_1) + (m_2 \cdot x_2)}{m_1 + m_2}\]
- This formula gives us a single point that represents the entire leg's average position of mass.
- We have to consider the leg's change in orientation.
- The upper leg remains horizontal, but the lower leg is vertical, shifting the COM.
- Yet, we only need the x-component for horizontal displacements.
Mechanics
Mechanics, as a branch of physics, deals with forces and motion, including the calculation of the center of mass. This concept is essential for analyzing how the leg moves during different positions.
Applying the formulas:
Applying the formulas:
- For the horizontal leg position, the resultant COM was found at approximately 40.4 cm from the hip joint.
- For the bent leg, the center of mass shifted closer, to about 31.7 cm from the hip joint.
- This balance between the upper and lower sections shows how varying leg positions affect the overall mass distribution.
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