Problem 60
Question
(a) find \(f \circ g, g \circ f,\) and the domain of \(f \circ g .\) (b) Use a graphing utility to graph \(f \circ g\) and \(g \circ f .\) Determine whether \(f \circ g=g \circ f.\) $$f(x)=|x|, \quad g(x)=-x^{2}+1$$
Step-by-Step Solution
Verified Answer
The composition \(f(g(x)) = |-x^{2} + 1|\), \(g(f(x)) = - |x|^{2} + 1\), and the domain of \(f \circ g\) is all real numbers. By plotting the graphs, \(f \circ g\) is not equal to \(g \circ f\). They have different shapes, thus they are not equal.
1Step 1: Find \(f \circ g\)
The composition \(f \circ g\) means applying function \(f\) to \(g(x)\). Here, \(f(g(x)) = f(-x^{2} + 1) = |-x^{2} + 1|\.
2Step 2: Find \(g \circ f\)
The composition \(g \circ f\) means applying function \(g\) to \(f(x)\). Here, \(g(f(x)) = g(|x|) = - |x|^{2} + 1\.
3Step 3: Find the domain of \(f \circ g\)
The domain of a function is the set of all values for which the function is defined. Here, \(f \circ g\) is defined for all real numbers because the domain of \(f(x) = |x|\) is all real numbers and the domain of \(g(x) = -x^{2} + 1\) is also all real numbers. So, the domain of \(f \circ g\) is all real numbers.
4Step 4: Graph \(f \circ g\) and \(g \circ f\)
Use any graphing utility (like GeoGebra, Desmos, or a graphing calculator) to graph the curves of \(f \circ g = |-x^{2} + 1|\) and \(g \circ f = - |x|^{2} + 1\).
5Step 5: Compare \(f \circ g\) and \(g \circ f\)
Now compare the graphs of \(f \circ g\) and \(g \circ f\). If both graphs are the same, then \(f \circ g = g \circ f\). If not, they are not equal.
Key Concepts
Absolute ValueQuadratic FunctionDomain of a Function
Absolute Value
The absolute value of a number is a way to describe how far the number is from zero on the number line, symbolized by vertical bars like \( |x| \) for a number \( x \). It essentially gives us the magnitude of a number without considering its sign. For any real number, if the number is positive or zero, its absolute value is the same as the number itself. However, if the number is negative, it is made positive. Here are the basics of absolute value:
- If \( x \) is positive or zero, \( |x| = x \).
- If \( x \) is negative, \( |x| = -x \).
Quadratic Function
A quadratic function is expressed in the form \( ax^2 + bx + c = 0 \), where \( a, b, \) and \( c \) are constants, and \( a \) is not equal to zero. The graph of a quadratic function is a parabola, which can open upwards or downwards depending on the sign of the leading coefficient \( a \).In this exercise, we have \( g(x) = -x^2 + 1 \). Due to the negative sign in front of the \( x^2 \) term, \( g(x)\) opens downwards with a vertex at \( (0, 1) \), making this parabola upside-down. Here are some quick properties of quadratic functions:
- A positive \( a \) results in a parabola opening upwards.
- A negative \( a \) flips it to open downwards.
- The vertex form of a quadratic can give us the maximum or minimum point of the function easily.
Domain of a Function
The domain of a function is the complete set of possible input values (or \( x \) values) for which the function is defined. For a basic understanding, any real number can be input into the function if it does not make the function undefined (e.g., dividing by zero or taking the square root of a negative number in real numbers).In our exercise, \( f \) with \( f(x) = |x| \) and \( g \) with \( g(x) = -x^2 + 1 \) are examined for their domain. Both functions here do not have any restrictions like division by zero or square roots of negative numbers, which are common culprits for undefined conditions. Specifically:
- The absolute value function \( f(x) = |x| \) is defined for all real numbers since any real number can be made non-negative.
- The quadratic function \( g(x) = -x^2 + 1 \) is a basic polynomial, also defined for all real numbers.
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