Problem 60
Question
55–62 ? Find an equation of the circle that satisfies the given conditions. Endpoints of a diameter are \(P(-1,3)\) and \(Q(7,-5)\)
Step-by-Step Solution
Verified Answer
The equation of the circle is \((x - 3)^2 + (y + 1)^2 = 32\).
1Step 1: Find the Midpoint
The midpoint of a diameter of a circle is the center of the circle. To find the midpoint between points \(P(-1, 3)\) and \(Q(7, -5)\), use the midpoint formula: \( \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \). This gives: \( \left( \frac{-1 + 7}{2}, \frac{3 - 5}{2} \right) = (3, -1) \). So, the center of the circle is \((3, -1)\).
2Step 2: Calculate the Radius
The radius of the circle is half the length of the diameter. Calculate the length of the diameter using the distance formula: \( \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \). Substituting \((-1, 3)\) and \((7, -5)\), we get \( \sqrt{(7 - (-1))^2 + (-5 - 3)^2} = \sqrt{8^2 + (-8)^2} = \sqrt{64 + 64} = \sqrt{128} = 8 \sqrt{2} \). The radius is thus \(\frac{8\sqrt{2}}{2} = 4\sqrt{2}\).
3Step 3: Write the Equation of the Circle
The equation of a circle with center \( (h, k) \) and radius \( r \) is \((x - h)^2 + (y - k)^2 = r^2\). With center \((3, -1)\) and radius \(4\sqrt{2}\), the equation becomes: \((x - 3)^2 + (y + 1)^2 = (4\sqrt{2})^2 = 32\).
Key Concepts
Midpoint FormulaDistance FormulaRadius CalculationCenter of Circle
Midpoint Formula
The midpoint formula is a nifty tool used to find the exact center between two points on a plane. In this case, we have the endpoints of a circle's diameter, which are points \( P(-1, 3) \) and \( Q(7, -5) \). The midpoint is crucial because it also represents the center of the circle.
When applying the midpoint formula, you calculate the average of the \( x \)-coordinates and the \( y \)-coordinates separately. The formula is as follows:
When applying the midpoint formula, you calculate the average of the \( x \)-coordinates and the \( y \)-coordinates separately. The formula is as follows:
- Midpoint \((x, y) = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)\)
- \( \left( \frac{-1 + 7}{2}, \frac{3 - 5}{2} \right) = (3, -1) \)
Distance Formula
To find the length of the circle's diameter, we use the distance formula. This calculation is essential to determine how long the straight line segment connecting points \( P \) and \( Q \) is. The distance gives us the diameter of the circle.
The distance formula is expressed as:
The distance formula is expressed as:
- \[ \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]
- \[ \sqrt{(7 - (-1))^2 + (-5 - 3)^2} = \sqrt{64 + 64} = \sqrt{128} = 8\sqrt{2} \]
Radius Calculation
The radius of the circle is half the length of its diameter. This value is needed to complete the equation of the circle.
From the distance formula, we previously found the diameter to be \( 8\sqrt{2} \). Therefore, the radius \( r \) is:
From the distance formula, we previously found the diameter to be \( 8\sqrt{2} \). Therefore, the radius \( r \) is:
- \( r = \frac{8\sqrt{2}}{2} = 4\sqrt{2} \)
Center of Circle
The center of the circle is derived using the midpoint formula, as explained earlier. This central point \( (h, k) \) is critical because it's part of the circle's standard equation format.Using our previously found midpoint, the center of this circle is \( (3, -1) \). This point allows us to place the circle in a coordinated plane and aligns with the formation of the circle's equation.
The general formula for the equation of a circle is:
The general formula for the equation of a circle is:
- \[ (x - h)^2 + (y - k)^2 = r^2 \]
- \( (x - 3)^2 + (y + 1)^2 = 32 \)
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Problem 60
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