Problem 6
Question
Write the quadratic equation in general form. $$ 12-3(x+7)^{2}=0 $$
Step-by-Step Solution
Verified Answer
The quadratic equation in general form is \(x^2 + 14x + 45 = 0\).
1Step 1: Expansion
Expand \( (x+7)^{2}\). This expansion will give \(x^2+14x+49\).
2Step 2: Distribute the negative
Distribute the -3 in front of \((x+7)^2\). This gives \(-3x^2-42x-147\).
3Step 3: Rearrange equation
Rearrange \(12 - 3(x+7)^2 = 0\) into the general quadratic form. Now we have \(-3x^2-42x-135=0\).
4Step 4: Simplify equation
Simplify equation by dividing every term by -3. This gives: \(x^2 + 14x + 45 =0\).
Key Concepts
AlgebraPolynomial ExpansionQuadratic FormulaEquation Simplification
Algebra
Algebra is a fundamental branch of mathematics that involves using symbols and letters to represent numbers and operations. It forms the basis for expressing and solving equations. When dealing with algebra, it's important to understand how to manipulate these symbols to find unknown values.
For example, in the equation \( 12 - 3(x+7)^{2} = 0 \), we suspect that it represents a standard mathematical relationship, and algebra helps us explore this relationship.
We apply algebraic operations systematically to transform the equation into a more familiar form, making it easier to identify solutions.
For example, in the equation \( 12 - 3(x+7)^{2} = 0 \), we suspect that it represents a standard mathematical relationship, and algebra helps us explore this relationship.
We apply algebraic operations systematically to transform the equation into a more familiar form, making it easier to identify solutions.
Polynomial Expansion
Polynomial expansion is a technique used to express a mathematical expression in its simplest form. In our exercise, we begin by expanding the term \((x+7)^{2}\).
Expansion means to multiply the terms inside the parentheses by themselves. So, \((x+7)(x+7)\) becomes:
Expansion means to multiply the terms inside the parentheses by themselves. So, \((x+7)(x+7)\) becomes:
- \(x^2\) – from \(x\times x\)
- \(7x\) – from \(x\times 7\)
- Another \(7x\) – from \(7\times x\)
- \(49\) – from \(7\times 7\)
Quadratic Formula
The quadratic formula is a tool for finding the solutions to quadratic equations. A quadratic equation is generally expressed in the form \(ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are constants.
The quadratic formula is given by: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] This formula offers a straightforward way to determine the values of \(x\) that satisfy the equation by merely substituting the equation’s coefficients into the formula.
Understanding this formula is crucial because it guarantees solutions for any quadratic equation, even when factoring isn’t feasible.
The quadratic formula is given by: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] This formula offers a straightforward way to determine the values of \(x\) that satisfy the equation by merely substituting the equation’s coefficients into the formula.
Understanding this formula is crucial because it guarantees solutions for any quadratic equation, even when factoring isn’t feasible.
Equation Simplification
Equation simplification aims to make an equation as straightforward as possible. In the exercise, after expanding and rearranging the terms, we found ourselves with the equation \(-3x^2-42x-135=0\).
To simplify, each term of the equation is divided by \(-3\). Simplifying reduces \(-3x^2-42x-135\) to \(x^2+14x+45\).
This process is crucial for making equations easier to understand and solve, as it brings the equation to its most fundamental form, often revealing insights or solutions that are less apparent in more complex forms.
To simplify, each term of the equation is divided by \(-3\). Simplifying reduces \(-3x^2-42x-135\) to \(x^2+14x+45\).
This process is crucial for making equations easier to understand and solve, as it brings the equation to its most fundamental form, often revealing insights or solutions that are less apparent in more complex forms.
Other exercises in this chapter
Problem 6
Find the real solution(s) of the polynomial equation. Check your solutions. \(x^{6}-64=0\)
View solution Problem 6
Use the discriminant to determine the number of real solutions of the quadratic equation. \(3-6 x=-3 x^{2}\)
View solution Problem 6
Write an algebraic expression for the verbal expression. Discount The sale price of an item that is discounted by \(20 \%\) of its list price \(L\)
View solution Problem 6
Determine whether the equation is an identity or a conditional equation. $$ 3(x+4)=3 x+4 $$
View solution