Problem 6
Question
Write the first four terms of each sequence whose general term is given. $$a_{n}-\left(-\frac{1}{3}\right)^{n}$$
Step-by-Step Solution
Verified Answer
The first four terms of the sequence are \( \frac{1}{3}, \frac{1}{9}, -\frac{1}{27}, \frac{1}{81}\).
1Step 1: Understand the General Term
The general term \(-\frac{1}{3}^n\) defines any term of the sequence. Here, 'n' is the term number. To find the term of the sequence, 'n' in the general term is replaced by the term number.
2Step 2: Substitution for the First Term
To find the first term of the sequence, replace 'n' in the general term by 1. Hence, \(a_1=-\frac{1}{3}^1 = \frac{1}{3}\).
3Step 3: Substitution for the Second Term
To find the second term of the sequence, replace 'n' in the general term by 2. Hence, \(a_2 = -\frac{1}{3}^2 = \frac{1}{9}\).
4Step 4: Substitution for the Third Term
To find the third term of the sequence, replace 'n' in the general term by 3. Hence, \(a_3 = -\frac{1}{3}^3 = -\frac{1}{27}\).
5Step 5: Substitution for the Fourth Term
To find the fourth term of the sequence, replace 'n' in the general term with 4. Hence, \(a_4 = -\frac{1}{3}^4 = \frac{1}{81}\).
Key Concepts
Understanding the General TermSubstitution to Find Sequence TermsFinding and Understanding Sequence Terms
Understanding the General Term
A sequence is often defined by a **general term** that represents each term in a sequence based on its position. In our example, the general term is given by the formula \( a_n = -\left(\frac{1}{3}\right)^n \). Here, \( n \) stands for the term's position in the sequence. Knowing the general term is key because it helps you find any term in your sequence by simply plugging in the number of the term into this formula.
- For instance, \( n=1 \) would give you the first term.
- When \( n=2 \), you find the second term, and so on.
Substitution to Find Sequence Terms
**Substitution** is the next step after understanding your general term. This process involves replacing \( n \) in your general term with different integers to find specific sequence terms. For our sequence, you substitute \( n \) with values like 1, 2, 3, etc.
Here's how it typically works:
Here's how it typically works:
- Substitute \( n=1 \) in the general term \( a_n = -\left(\frac{1}{3}\right)^n \) to find the first term: \( a_1 = -\left(\frac{1}{3}\right)^1 = \frac{1}{3} \).
- Continue by substituting \( n=2 \) for the second term: \( a_2 = -\left(\frac{1}{3}\right)^2 = \frac{1}{9} \).
- Keep substituting for more terms (\( n=3, 4, ... \)). For instance, \( a_3 = -\left(\frac{1}{3}\right)^3 = -\frac{1}{27} \).
Finding and Understanding Sequence Terms
Once you substitute the values of \( n \) to the general term, you uncover the **sequence terms**. These are the individual terms of your sequence, and each term has unique characteristics. For example, the terms we calculated from the general term \( a_n = -\left(\frac{1}{3}\right)^n \) are as follows:
- The first term is \( a_1 = \frac{1}{3} \).
- The second term is \( a_2 = \frac{1}{9} \).
- The third term is \( a_3 = -\frac{1}{27} \).
- The fourth term is \( a_4 = \frac{1}{81} \).
Other exercises in this chapter
Problem 6
Write the first five terms of each geometric sequence. $$a_{n}=-3 a_{n-1}, \quad a_{1}=10$$
View solution Problem 6
In Exercises \(1-14\), write the first six terms of cach arithmetic sequence $$a_{1}=200, d=-60$$
View solution Problem 7
Use the formula for \(_{n} P_{t}\) to evaluate each expression. $$ _{8}P_{0} $$
View solution Problem 7
In Exercises 1-8, evaluate the given binomial coefficient. $$\left(\begin{array}{c}100 \\\2\end{array}\right)$$
View solution