Problem 6
Question
What is the polar equation of the horizontal line \(y=5 ?\)
Step-by-Step Solution
Verified Answer
Answer: The polar equation for the horizontal line y=5 is \(r = \frac{5}{\sin{\theta}}\).
1Step 1: Write down the given Cartesian equation
The given horizontal line is \(y=5\).
2Step 2: Express y in terms of polar coordinates
Since \(y = r\sin{\theta}\), we can substitute this into the given equation: \(r\sin{\theta} = 5\).
3Step 3: Solve for r
We can solve for r by dividing both sides by \(\sin{\theta}\): \(r = \frac{5}{\sin{\theta}}\).
4Step 4: Write the final polar equation
The polar equation for the given horizontal line \(y=5\) is: \(r = \frac{5}{\sin{\theta}}\).
Other exercises in this chapter
Problem 5
Find parametric equations for the parabola \(y=x^{2}.\)
View solution Problem 6
What is the equation of the standard parabola with its vertex at the origin that opens downward?
View solution Problem 6
Find the slope of the line tangent to the following polar curves at the given points. At the points where the curve intersects the origin (when this occurs), fi
View solution Problem 6
Describe the similarities and differences between the parametric equations \(x=t, y=t^{2}\) and \(x=-t, y=t^{2},\) where \(t \geq 0\) in each case.
View solution