Problem 6
Question
We have seen that ions in aqueous solution are stabilized by the attractions between the ions and the water molecules. Why then do some pairs of ions in solution form precipitates? [Section 4.2]
Step-by-Step Solution
Verified Answer
In aqueous solutions, ions are stabilized by their interactions with water molecules through solvation. However, some pairs of ions in solution form precipitates because their attractive forces with each other are stronger than the stabilizing interactions with water molecules. These precipitates are formed when the solubility equilibrium is reached, and the ion product exceeds the solubility product constant (Ksp) for the substance involved. This indicates that the interactions between the ions overcome the stabilizing effect of water molecules.
1Step 1: Introduction to solvation and stabilization
In aqueous solutions, ions (either positively charged cations or negatively charged anions) are surrounded by water molecules. These water molecules are attracted to the ions due to their polar nature. This interaction is called "solvation" and it stabilizes ions in the solution.
2Step 2: Formation of precipitates
Despite the stabilization imparted by water molecules, some pairs of ions in the solution might form precipitates. This is because the ions in the solution can interact with each other as well, forming products with very low solubility. Precipitation happens when the attractive forces between the ions in the pair are stronger than the stabilizing interaction with the water molecules.
3Step 3: Examples of precipitation reactions
An example of this interaction causing precipitation is the reaction between a soluble silver salt (e.g., silver nitrate, AgNO3) and a soluble chloride salt (e.g., sodium chloride, NaCl), leading to the formation of silver chloride (AgCl), a highly insoluble precipitate:
\[ AgNO_3 + NaCl \rightarrow AgCl_{(s)} + NaNO_3 \]
In this case, the strong attraction between the Ag+ and Cl- ions is stronger than the interactions between these ions and the water molecules, which leads to the formation of AgCl precipitate.
4Step 4: An understanding of solubility equilibrium
It is important to remember that the solubilities of different compounds vary, and this plays a significant role in the formation of the precipitate. Precipitation reactions are governed by the solubility equilibrium and the solubility product constant (Ksp), which is specific for each substance. If the ion product of a solution exceeds the Ksp value for the substance, the excess ions will form insoluble precipitates. This indicates that the attractive forces between the ions in the solution overcome the stabilizing interactions with water molecules.
Other exercises in this chapter
Problem 4
The concept of chemical equilibrium is very important. Which one of the following statements is the most correct way to think about equilibrium? (a) If a system
View solution Problem 5
You are presented with a white solid and told that due to careless labeling it is not clear if the substance is barium chloride, lead chloride, or zinc chloride
View solution Problem 7
Which of the following ions will always be a spectator ion in a precipitation reaction? (a) \(\mathrm{Cl}^{-}\), (b) \(\mathrm{NO}_{3}^{-}\), (c) \(\mathrm{NH}_
View solution Problem 8
The labels have fallen off three bottles containing powdered samples of metals; one contains zinc, one lead, and the other platinum. You have three solutions at
View solution