Problem 6
Question
Use the Law of Cosines to solve the triangle. $$ a=7, b=9, c=4 $$
Step-by-Step Solution
Verified Answer
The triangle's angles are approximately: \( A = 48.2^\circ \), \( B = 106.3^\circ \), \( C = 25.5^\circ \).
1Step 1: Understanding the Problem
We are given a triangle with side lengths: \( a = 7 \), \( b = 9 \), and \( c = 4 \). We need to find the measures of the triangle’s angles using the Law of Cosines.
2Step 2: Applying Law of Cosines to Find Angle A
To find angle \( A \), we use the Law of Cosines formula: \[ \cos A = \frac{{b^2 + c^2 - a^2}}{{2bc}} \]Substitute the given values: \[ \cos A = \frac{{9^2 + 4^2 - 7^2}}{{2 \times 9 \times 4}} \] Calculate this to find \( \cos A \).
3Step 3: Calculating \( \cos A \)
Substitute and simplify:\[ \cos A = \frac{{81 + 16 - 49}}{{72}} = \frac{48}{72} = \frac{2}{3} \]Use the inverse cosine to find \( A \): \( A = \cos^{-1} \left( \frac{2}{3} \right) \).
4Step 4: Applying Law of Cosines to Find Angle B
To find angle \( B \), use:\[ \cos B = \frac{{a^2 + c^2 - b^2}}{{2ac}}\]Substitute the given values:\[ \cos B = \frac{{7^2 + 4^2 - 9^2}}{{2 \times 7 \times 4}}\]Calculate to find \( \cos B \).
5Step 5: Calculating \( \cos B \)
Substitute and simplify:\[ \cos B = \frac{{49 + 16 - 81}}{{56}} = \frac{-16}{56} = -\frac{2}{7} \]Use the inverse cosine to find \( B \): \( B = \cos^{-1} \left( -\frac{2}{7} \right) \).
6Step 6: Applying Law of Cosines to Find Angle C
Solve for angle \( C \) using the formula:\[ \cos C = \frac{{a^2 + b^2 - c^2}}{{2ab}}\]Substitute in the values:\[ \cos C = \frac{{7^2 + 9^2 - 4^2}}{{2 \times 7 \times 9}}\]Calculate to find \( \cos C \).
7Step 7: Calculating \( \cos C \)
Substitute and simplify:\[ \cos C = \frac{{49 + 81 - 16}}{{126}} = \frac{114}{126} = \frac{19}{21} \]Use the inverse cosine to find \( C \): \( C = \cos^{-1} \left( \frac{19}{21} \right) \).
Key Concepts
triangle solvingtrigonometryangle calculation
triangle solving
When solving a triangle, we're tasked with finding unknown sides and angles given certain known values. In our case, we have a triangle where all three side lengths are known: \( a = 7 \), \( b = 9 \), and \( c = 4 \). The process involves determining the measures of all three angles using these side lengths.
This specific problem is an example of solving using the Law of Cosines. It's particularly useful when you know all the sides or two sides and the included angle. It allows you to find the unknown parts of the triangle in an efficient manner.
This specific problem is an example of solving using the Law of Cosines. It's particularly useful when you know all the sides or two sides and the included angle. It allows you to find the unknown parts of the triangle in an efficient manner.
- Always start by identifying known quantities.
- Apply relevant formulas, like the Law of Cosines, to find missing angles.
- Ensure calculations are precise to get accurate angle measurements.
trigonometry
Trigonometry provides the mathematical framework to analyze triangles, particularly right-angled and oblique triangles. The Law of Cosines is a critical trigonometric tool that extends understanding beyond right triangles. It relates the sides of a triangle to the cosine of one of its angles, helping to solve any type of triangle.
The Law of Cosines is expressed as: \[ c^2 = a^2 + b^2 - 2ab \, \cos C\]Alternatively, for angle calculations:
The Law of Cosines is expressed as: \[ c^2 = a^2 + b^2 - 2ab \, \cos C\]Alternatively, for angle calculations:
- To find \( \cos A \): \( \cos A = \frac{{b^2 + c^2 - a^2}}{{2bc}} \)
- To find \( \cos B \): \( \cos B = \frac{{a^2 + c^2 - b^2}}{{2ac}} \)
- To find \( \cos C \): \( \cos C = \frac{{a^2 + b^2 - c^2}}{{2ab}} \)
angle calculation
Calculating angles is crucial in triangle problems, particularly when you have all sides known. After using the Law of Cosines to get expressions for \( \cos A \), \( \cos B \), and \( \cos C \), you use inverse trigonometric functions to find the actual angle measures.
- For \( A \), substitute \( \cos A = \frac{2}{3} \) into \( A = \cos^{-1} \left( \frac{2}{3} \right) \).
- For \( B \), substitute \( \cos B = -\frac{2}{7} \) into \( B = \cos^{-1} \left( -\frac{2}{7} \right) \).
- For \( C \), substitute \( \cos C = \frac{19}{21} \) into \( C = \cos^{-1} \left( \frac{19}{21} \right) \).
Other exercises in this chapter
Problem 5
Use the Law of Sines to solve the triangle. $$ \alpha=80^{\circ}, \beta=20^{\circ}, b=7 $$
View solution Problem 6
Sketch the given vector. Find the magnitude and the smallest positive direction angle of each vector. $$ \mathbf{i}-\mathbf{j} $$
View solution Problem 6
Use the Law of Sines to solve the triangle. $$ \alpha=80^{\circ}, \beta=20^{\circ}, b=7 $$
View solution Problem 7
Sketch the given vector. Find the magnitude and the smallest positive direction angle of each vector. $$ -10 \mathbf{i}+10 \mathbf{j} $$
View solution