Problem 6
Question
Use (a) the Trapezoidal Rule and (b) Simpson's Rule to approximate the integral. Compare your results with the exact value of the integral. $$ \int_{0}^{1} e^{-x} d x ; \quad n=6 $$
Step-by-Step Solution
Verified Answer
We find the interval width, \(\Delta x = \frac{1}{6}\), and approximate the integral \(\int_{0}^{1} e^{-x} dx\) using the Trapezoidal Rule and Simpson's Rule:
a) Trapezoidal Rule: \(\int_{0}^{1} e^{-x} dx \approx 0.631102\)
b) Simpson's Rule: \(\int_{0}^{1} e^{-x} dx \approx 0.632120\)
The exact value of the integral is approximately \(0.632121\). Comparing the approximations, we can see that Simpson's Rule provides a closer approximation to the exact value than the Trapezoidal Rule in this case.
1Step 1: Calculate interval width (Δx)
Divide the interval [0, 1] into six equal parts. The interval width is given by:
$$
\Delta x = \frac{(b - a)}{n} = \frac{1-0}{6} = \frac{1}{6}
$$
2Step 2: Use the Trapezoidal Rule
Apply the Trapezoidal Rule formula:
$$
\int_{a}^{b} f(x) dx \approx \frac{\Delta x}{2} \left[f(x_0) + 2 \sum_{i=1}^{n-1} f(x_i) + f(x_n)\right]
$$
Compute the function values:
$$
f(x) = e^{-x}
$$
Then, approximate the integral using the Trapezoidal Rule:
\[
\begin{aligned}
\int_{0}^{1} e^{-x} dx &\approx \frac{1}{12} \left[e^{-0} + 2(e^{-\frac{1}{6}} + e^{-\frac{2}{6}} + e^{-\frac{3}{6}} + e^{-\frac{4}{6}} + e^{-\frac{5}{6}}) + e^{-1}\right] \\
&\approx 0.631102
\end{aligned}
\]
3Step 3: Use Simpson's Rule
Apply Simpson's Rule formula:
$$
\int_{a}^{b} f(x) dx \approx \frac{\Delta x}{3} \left[f(x_0) + 4\sum_{i=1}^{n/2} f(x_{2i-1}) + 2\sum_{i=1}^{n/2-1} f(x_{2i}) + f(x_n)\right]
$$
Then, approximate the integral using Simpson's Rule:
\[
\begin{aligned}
\int_{0}^{1} e^{-x} dx &\approx \frac{1}{18} \left[e^{-0} + 4(e^{-\frac{1}{6}} + e^{-\frac{3}{6}} + e^{-\frac{5}{6}}) + 2(e^{-\frac{2}{6}} + e^{-\frac{4}{6}}) + e^{-1}\right] \\
&\approx 0.632120
\end{aligned}
\]
4Step 4: Find the exact value of the integral
Integrate the function exactly:
$$
\int_{0}^{1} e^{-x} dx = \left[-e^{-x}\right]_{0}^{1} = -(e^{-1} - e^0) = 1 - e^{-1}
$$
The exact value of the integral is approximately 0.632121.
5Step 5: Compare the results
Comparing the approximations with the exact value:
- Trapezoidal Rule approximation: 0.631102
- Simpson's Rule approximation: 0.632120
- Exact value of the integral: 0.632121
Simpson's Rule provides a closer approximation to the exact value of the integral than the Trapezoidal Rule in this case.
Key Concepts
Trapezoidal RuleSimpson's RuleDefinite IntegrationApproximation Methods
Trapezoidal Rule
The Trapezoidal Rule is a numerical method used to estimate the definite integral of a function. When you don't have the luxury of solving an integral analytically, this method comes in handy. Essentially, the Trapezoidal Rule approximates the region under the curve by dividing it into a series of trapezoids, hence the name.
- Each trapezoid is formed by using the function values at the endpoints of the subintervals as the heights.
- The formula used for approximation is: \[ \int_{a}^{b} f(x) dx \approx \frac{\Delta x}{2} \left[f(x_0) + 2 \sum_{i=1}^{n-1} f(x_i) + f(x_n)\right] \]
- To apply this method, you need to calculate the width of each subinterval, \(\Delta x\).
Simpson's Rule
Simpson's Rule is another powerful numerical technique to approximate definite integrals. It is often more accurate than the Trapezoidal Rule due to its use of parabolic arcs instead of straight lines to approximate the function's curve.
- Simpson's Rule assumes that over each pair of subintervals, the graph of the function can be fit by a parabola.
- The formula for Simpson’s Rule is given by: \[ \int_{a}^{b} f(x) dx \approx \frac{\Delta x}{3} \left[f(x_0) + 4\sum_{i=1}^{n/2} f(x_{2i-1}) + 2\sum_{i=1}^{n/2-1} f(x_{2i}) + f(x_n)\right] \]
Definite Integration
Definite integration seeks to compute the exact area under the curve of a given function over a specified interval. This is represented mathematically by the integral symbol with lower and upper bounds, \([a, b]\), indicating the start and end points of the interval.
- The purpose of definite integration is to determine the accumulation of quantities, such as area, volume, and other quantifiable aspects.
- In the context of our problem, we are working to integrate \(\int_{0}^{1} e^{-x} dx\).
Approximation Methods
Approximation methods are central in scenarios where calculating the exact value of an integral is either inconvenient or impossible. These techniques bridge the gap between calculus' theoretical world and their practical applications in science and engineering.
- They provide a pragmatic means to estimate values, particularly useful when dealing with empirical data where functions may not be explicitly known.
- Common methods include the Trapezoidal Rule and Simpson’s Rule—each employed based on the requirements for speed, simplicity, or accuracy.
- These methods work by discretizing the interval and making intelligent guesses about the shape of the integrand between known points.
Other exercises in this chapter
Problem 5
You are given a function \(f\), an interval \([a, b]\), the number \(n\) of subintervals into which \([a, b]\) is divided \((\) each of length \(\Delta x=(b-a)
View solution Problem 5
Find the indefinite integral, and check your answer by differentiation. $$ \int\left(2 x^{9}+3 e^{x}+4\right) d x $$
View solution Problem 6
Find the derivative of the function. $$ h(x)=\int_{x}^{3} \frac{t}{\sqrt{t+1}} d t $$
View solution Problem 6
You are given a function \(f\) defined on an interval \([a, b]\), the number \(n\) of subintervals of equal length \(\Delta x=(b-a) / n\), and the evaluation po
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