Problem 6
Question
Use a table of integrals to determine the following indefinite integrals. $$\int \sin 3 x \cos 2 x d x$$
Step-by-Step Solution
Verified Answer
Question: Evaluate the indefinite integral $\int \sin 3x \cos 2x d x$.
Solution: Using trigonometric identities, the indefinite integral simplifies to $\int \sin 3x \cos 2x d x = \frac{1}{2} \left[ \frac{-1}{5} \cos(5x) - \cos(x) \right] + C$
1Step 1: Simplify the integrand using trigonometric identities
Recall the Product-to-Sum identity for trigonometric functions:
$$\sin A \cos B = \frac{1}{2}(\sin(A + B) + \sin(A - B))$$
Using this identity, we can simplify the given integral:
$$\int \sin 3x \cos 2x d x = \int \frac{1}{2}(\sin(3x + 2x) + \sin(3x - 2x)) d x$$
2Step 2: Perform the integration
Now that the integrand is simplified, we can use the table of integrals to find the antiderivative. In this case, we refer to the integral of sin(ax) and cos(ax), which are respectively:
$$\int \sin(ax) d x = \frac{-1}{a} \cos(ax) + C$$
Using this formula, integrate each term inside the integral:
$$\int \frac{1}{2}(\sin(5x) + \sin(x)) d x = \frac{1}{2} \left[ \int \sin(5x) d x + \int \sin(x) d x \right]$$
3Step 3: Apply the integral formulas and simplify
Apply the integral formulas for sin(ax) and sin(x):
$$\frac{1}{2} \left[ \int \sin(5x) d x + \int \sin(x) d x \right] = \frac{1}{2} \left[ \frac{-1}{5} \cos(5x) + \int_{-\frac{1}{1}} \cos(x) d x \right]$$
$$= \frac{1}{2} \left[ \frac{-1}{5} \cos(5x) - \cos(x) \right] + C$$
The final indefinite integral is:
$$\int \sin 3 x \cos 2 x d x = \frac{1}{2} \left[ \frac{-1}{5} \cos(5x) - \cos(x) \right] + C$$
Key Concepts
Trigonometric IdentityProduct-to-Sum IdentityAntiderivativeTable of Integrals
Trigonometric Identity
Trigonometric identities are mathematical tools that express relationships between trigonometric functions. These identities are useful in simplifying expressions and solving equations involving
- sines,
- cosines,
- and other trigonometric functions.
Product-to-Sum Identity
The Product-to-Sum identity is a specific trigonometric identity that allows us to convert a product of sine and cosine into a simpler sum of terms. This is particularly beneficial for integration, since sums are generally easier to handle than products.For this exercise, we applied the identity:\[ \sin 3x \cos 2x = \frac{1}{2}(\sin(5x) + \sin(x)) \]Breaking down a product into a sum like this is key when solving integrals involving products of trigonometric functions. It transforms a complex multiplication into an addition, which can often be directly integrated using standard formulas like in our reference table.
Antiderivative
Antiderivatives, often called indefinite integrals, are the opposite of derivatives. They represent the family of functions whose derivative is the given function. In other words, integrating a function gives us its antiderivative.For example, in this exercise:
- We found the antiderivative of \(\sin(5x)\) using the formula: \(\int \sin(ax) \,dx = \frac{-1}{a} \cos(ax) + C \)
- Similarly, for \(\sin(x)\), the antiderivative is \(-\cos(x) + C \)
Table of Integrals
A table of integrals is a collection of formulas that provide the integral for common functions. These tables are invaluable tools for students and professionals alike since they offer shortcuts for calculating integrals without needing to perform lengthy integrations manually.When dealing with trigonometric functions, tables typically include:
- integrals of \(\sin(ax)\)
- integrals of \(\cos(ax)\)
- and other basic integrals
Other exercises in this chapter
Problem 6
Evaluate the following integrals or state that they diverge. $$\int_{0}^{\infty} \frac{d x}{(x+1)^{3}}$$
View solution Problem 6
State how to compute the Simpson's Rule approximation \(S(2 n)\) if the Trapezoid Rule approximations \(T(2 n)\) and \(T(n)\) are known.
View solution Problem 6
If \(x=8 \sec \theta,\) express tan \(\theta\) in terms of \(x\)
View solution Problem 6
Give the partial fraction decomposition for the following functions. $$\frac{x-9}{x^{2}-3 x-18}$$
View solution