Problem 6
Question
The \(x\) and \(y\) components of a force are \(2 \mathrm{~N}\) and \(-3 \mathrm{~N}\). The force is (a) \(2 \hat{\mathrm{i}}-3 \hat{\mathrm{j}}\) (b) \(2 \hat{\mathrm{i}}+3 \hat{\mathrm{j}}\) (c) \(-2 \hat{i}-3 \hat{j}\) (d) \(3 \hat{\mathrm{i}}+2 \hat{\mathrm{j}}\)
Step-by-Step Solution
Verified Answer
The correct option is (a) \(2 \hat{\mathrm{i}} - 3 \hat{\mathrm{j}}\).
1Step 1: Interpret the Problem
In this task, we need to express a force vector using its components. The given components are in the x-direction and y-direction, where the x-component is \(2 \text{ N}\) and the y-component is \(-3 \text{ N}\).
2Step 2: Construct the Vector
To represent a force vector given its components, combine the unit vectors with their corresponding components. Therefore, the force vector will be expressed as \(2 \hat{\mathrm{i}} - 3 \hat{\mathrm{j}}\). The vector combines the contributions in both the x- and y-directions.
3Step 3: Match with Options
Look at the provided options to see which one matches our constructed vector. Our constructed vector is \(2 \hat{\mathrm{i}} - 3 \hat{\mathrm{j}}\). The option that corresponds to this vector is option (a) \(2 \hat{\mathrm{i}} - 3 \hat{\mathrm{j}}\).
4Step 4: Verify and Conclude
Double-check the components match the description provided in the problem. The x-component \(2 \text{ N}\) and y-component \(-3 \text{ N}\) match exactly with the vector \(2 \hat{\mathrm{i}} - 3 \hat{\mathrm{j}}\). This confirms that option (a) is the correct representation.
Key Concepts
Force VectorUnit Vector NotationX and Y Components
Force Vector
A force vector represents the magnitude and direction of a force in two-dimensional or three-dimensional space. It is an essential concept in physics and engineering, allowing us to analyze forces acting on an object in a structured way.
In two dimensions, a force vector is often expressed using the unit vectors \(\hat{i}\) and \(\hat{j}\), which represent the directions along the x-axis and y-axis respectively. This makes it easier to understand how much of the force is acting in each direction:
In two dimensions, a force vector is often expressed using the unit vectors \(\hat{i}\) and \(\hat{j}\), which represent the directions along the x-axis and y-axis respectively. This makes it easier to understand how much of the force is acting in each direction:
- \(\hat{i}\) represents the x-direction.
- \(\hat{j}\) represents the y-direction.
Unit Vector Notation
Unit vectors are essential in vector notation. A unit vector has a magnitude of 1 and indicates direction. By expressing a vector in terms of unit vectors, we can clearly express both direction and magnitude in a standardized form.
In two-dimensional space, unit vectors consist of \(\hat{i}\) and \(\hat{j}\):
This notation simplifies calculations by breaking up complex problems into manageable components. Each component is multiplied by its respective unit vector, allowing precise representation and calculation of forces in multiple directions.
In two-dimensional space, unit vectors consist of \(\hat{i}\) and \(\hat{j}\):
- \(\hat{i}\) has a value of 1 in the x-direction.
- \(\hat{j}\) has a value of 1 in the y-direction.
This notation simplifies calculations by breaking up complex problems into manageable components. Each component is multiplied by its respective unit vector, allowing precise representation and calculation of forces in multiple directions.
X and Y Components
The x and y components of a vector tell us how much of the vector's magnitude lies along each axis. These components are crucial for completely understanding the vector's impact or effect in each direction.
In the given problem, the force vector is initially broken into x and y components of \(2 \, \text{N}\) and \(-3 \, \text{N}\) respectively.
In the given problem, the force vector is initially broken into x and y components of \(2 \, \text{N}\) and \(-3 \, \text{N}\) respectively.
- The x-component is \(2 \, \text{N}\): this component acts along the positive x-axis.
- The y-component is \(-3 \, \text{N}\): this acts along the negative y-axis.
Other exercises in this chapter
Problem 4
A proton of velocity \((3 \hat{\mathbf{i}}+2 \hat{\mathbf{j}}) \times 10^{5} \mathrm{~ms}^{-1}\) enters a magnetic field \((2 \hat{\mathbf{i}}+3 \hat{\mathbf{k}
View solution Problem 5
Two forces \(\mathbf{F}_{1}\) and \(\mathbf{F}_{2}\) are acting at right angles to each other. Then their resultant is (a) \(F_{i}+F_{2}\) (b) \(\sqrt{F_{1}^{2}
View solution Problem 6
The sum of the magnitudes of two forces acting at a point is \(16 \mathrm{~N}\). The resultant of these forces is perpendicular to the smaller force has a magni
View solution Problem 7
Given \(\mathbf{R}=\mathbf{A}+\mathbf{B}\) and \(R=A=B .\) The angle between \(\mathbf{A}\) and \(\mathbf{B}\) is (a) \(60^{\circ}\) (b) \(90^{\circ}\) (c) \(12
View solution