Problem 6
Question
The steady-state temperatare in a hemisphere of radius \(c\) is detrimined from
$$
\begin{gathered}
\frac{\partial^{2} u}{\partial r^{2}}+\frac{2}{r} \frac{\partial u}{\partial
r}+\frac{1}{r^{2}} \frac{\partial^{2} u}{\partial \theta^{2}}+\frac{\cot
\theta}{r^{2}} \frac{\partial u}{\partial \theta}=0,0
Step-by-Step Solution
Verified Answer
Use separation of variables and boundary conditions to solve the PDE.
1Step 1: Understanding the Problem
The given problem is a partial differential equation (PDE) defined in a hemisphere with boundary conditions specified. The PDE describes the steady-state temperature distribution, \[\frac{\partial^{2} u}{\partial r^{2}} + \frac{2}{r} \frac{\partial u}{\partial r} + \frac{1}{r^{2}} \frac{\partial^{2} u}{\partial \theta^{2}} + \frac{\cot \theta}{r^{2}} \frac{\partial u}{\partial \theta} = 0,\]for \(0 < r < c\) and \(0 < \theta < \pi/2\). The boundary conditions are \(u(r, \pi/2) = 0\) and \(u(c, \theta) = f(\theta)\).
Key Concepts
Steady-State Temperature DistributionBoundary ConditionsSpherical Coordinates
Steady-State Temperature Distribution
In the realm of partial differential equations, a steady-state temperature distribution refers to a condition where the temperature at any point in a region does not change with time. This means that heat is balanced within the system, with incoming and outgoing heat being equal. When dealing with steady-state problems, the focus is on solving the equations that describe the temperature variation across space, without involving a time variable.
In this context, the partial differential equation (PDE) provided governs the temperature distribution across a hemispherical region. It doesn't account for changes over time but rather describes how temperature varies spatially within that hemisphere. Solving this equation helps determine how heat spreads within the sphere until it achieves equilibrium. Such problems are crucial in understanding how materials respond to thermal conditions over long periods, such as in engineering or environmental studies.
Understanding this concept helps in solving practical problems where maintaining a specific temperature is critical, like ensuring machinery doesn't overheat or optimizing energy use.
In this context, the partial differential equation (PDE) provided governs the temperature distribution across a hemispherical region. It doesn't account for changes over time but rather describes how temperature varies spatially within that hemisphere. Solving this equation helps determine how heat spreads within the sphere until it achieves equilibrium. Such problems are crucial in understanding how materials respond to thermal conditions over long periods, such as in engineering or environmental studies.
Understanding this concept helps in solving practical problems where maintaining a specific temperature is critical, like ensuring machinery doesn't overheat or optimizing energy use.
Boundary Conditions
Boundary conditions are an essential part of solving partial differential equations in physical systems. They specify the values that a solution must adhere to at the boundaries of the domain. In the given exercise, two boundary conditions are provided:
- The first is \(u(r, \pi/2) = 0\), meaning that along the boundary where \(\theta\) equals \(\pi/2\), the temperature is zero. This might represent a perfectly insulated boundary where no heat is transferred through the surface.
- The second boundary condition is \(u(c, \theta) = f(\theta)\), dictating that at the surface of the hemisphere (where \(r = c\)), the temperature is determined by a function \(f(\theta)\). This condition accounts for an external temperature source or sink applied at this boundary.
Spherical Coordinates
Spherical coordinates are a system of curvilinear coordinates that are natural for describing positions on a sphere or spheroid. They are especially useful in problems involving symmetric 3D objects. The main variables in spherical coordinates are:
Understanding how to represent problems in spherical coordinates is crucial as it simplifies many problems involving spherical domains, such as those encountered in physics and engineering. It allows complex geometric configurations to be expressed more conveniently, thus making the mathematical operations more straightforward.
- \(r\): The radial distance from the origin to the point in space.
- \(\theta\): The polar angle measured from the positive z-axis.
- \(\phi \: \text{(not used in this problem)}\): The azimuthal angle in the xy-plane from the x-axis.
Understanding how to represent problems in spherical coordinates is crucial as it simplifies many problems involving spherical domains, such as those encountered in physics and engineering. It allows complex geometric configurations to be expressed more conveniently, thus making the mathematical operations more straightforward.
Other exercises in this chapter
Problem 6
Find the steady-state temperature \(u(r, \theta)\) in a semicircular plate of radius 1 if the boundary-conditions are $$ \begin{aligned} &u(1, \theta)=u_{0}, \q
View solution Problem 6
In Problems \(5-8\), find the steady-state temperature \(u(r, z)\) in a finite cylinder defined by \(0 \leq r \leq 1,0 \leq z \leq 1\) if the boundary condition
View solution Problem 7
In Problems 5-8, find the steady-state temperature \(u(r, z)\) in a finite cylinder defined by \(0 \leq r \leq 1,0 \leq z \leq 1\) if the boundary conditions ar
View solution Problem 8
In Problems \(5-8\), find the steady-state temperature \(u(r, z)\) in a finite cylinder defined by \(0 \leq r \leq 1,0 \leq z \leq 1\) if the boundary condition
View solution