Problem 6
Question
The purpose of this exercise is to give rigorous proofs (using induction) of the basic identities involved in the use of exponents or multiples. If \(A\) is a ring and \(a \in A\), we define \(\mathrm{n} \cdot a\) (where \(\mathrm{n}\) is any positive integer) by the pair of conditions: (i) \(1 \cdot a=a, \quad\) and (ii) \((\mathrm{n}+1) \cdot a=\mathrm{n} \cdot a+a\) Use mathematical induction (with the above definition) to prove that the following are true for all positive integers \(\mathrm{n}\) and all elements \(a, b \in A\) : $$ (\mathrm{n} \cdot a)(\mathrm{m} \cdot b)=(\mathrm{nm}) \cdot a b \quad \text { (Use parts } 3 \text { and 4.) } $$
Step-by-Step Solution
Verified Answer
Using induction, the identity \( (n \cdot a)(m \cdot b) = (nm) \cdot ab \) holds for all positive integers \( n \).
1Step 1: Base Case
To initiate induction, we verify the identity for the smallest positive integer value of \( n \). Let \( n = 1 \). Then the left-hand side (LHS) of the identity is \((1 \cdot a)(m \cdot b) = a \cdot (m \cdot b)\). According to the definition \((i)\), \( 1 \cdot a = a \), so the LHS becomes simply \((a)(m \cdot b)\). The right-hand side (RHS) is \((1m) \cdot ab = m \cdot ab \), which should match the LHS. Therefore, the base case holds: \((a)(m \cdot b) = m \cdot ab\).
2Step 2: Inductive Hypothesis
Assume that the statement is true for some positive integer \( k \), i.e., \((k \cdot a)(m \cdot b) = (km) \cdot ab\). This assumption will be used to prove that the statement holds for \( k+1 \).
3Step 3: Inductive Step
Show the identity is true for \( k+1 \). The LHS for \( k+1 \) becomes: \( ((k+1) \cdot a)(m \cdot b) = (k \cdot a + a)(m \cdot b) \). Distribute on the left side: \((k \cdot a + a)(m \cdot b) = (k \cdot a)(m \cdot b) + (a)(m \cdot b)\). By the inductive hypothesis, substitute for \((k \cdot a)(m \cdot b) = (km) \cdot ab\). Thus, \((km) \cdot ab + (a)(m \cdot b)\).
4Step 4: Simplifying with Distributive Law
Recognize that \((a)(m \cdot b) = m(ab)\), so the expression becomes \( (km) \cdot ab + m \cdot ab = (km + m) \cdot ab \). This simply equals to \(((k+1)m) \cdot ab\) because \( km + m = (k+1)m\).
5Step 5: Conclusion
The inductive step holds, completing the proof. We have shown that if the identity \((k \cdot a)(m \cdot b) = (km) \cdot ab\) is true for \( k \), then it is also true for \( k+1 \). Therefore, by the principle of mathematical induction, the original identity \((n \cdot a)(m \cdot b) = (nm) \cdot ab\) holds for all positive integers \( n \).
Key Concepts
Ring TheoryAlgebraic StructuresDistributive LawProof Techniques
Ring Theory
Ring theory is a branch of abstract algebra that focuses on the study of rings. A ring is a set equipped with two binary operations: addition and multiplication. Rings serve as a fundamental building block in many areas of mathematics, including number theory and geometry.
A ring must satisfy several properties:
A ring must satisfy several properties:
- It must be closed under addition and multiplication.
- It must have an additive identity (also called zero element).
- Each element must have an additive inverse.
- Addition must be associative and commutative.
- Multiplication must be associative.
- Multiplication by the zero element results in the zero element.
Algebraic Structures
In mathematics, algebraic structures are sets equipped with operations that follow specific rules. They are crucial in organizing mathematical elements and their relationships.
Some key kinds of algebraic structures include:
Some key kinds of algebraic structures include:
- Groups: Sets with a single operation, satisfying associativity, identity, and invertibility.
- Rings: Sets with two operations (addition and multiplication) that adhere to certain rules, as explained in ring theory.
- Fields: Similar to rings but every non-zero element has a multiplicative inverse.
Distributive Law
The distributive law is a fundamental property in algebra. It connects addition and multiplication in ring theory and other algebraic structures.
The distributive law states that for any elements, e.g., numbers, in a ring:
In the context of the original exercise, the distributive law allows users to expand and simplify expressions during the inductive step of the proof process, ensuring that terms can be rearranged and combined according to prescribed rules, thus demonstrating the equivalence of expressions for multiplying elements in a ring.
The distributive law states that for any elements, e.g., numbers, in a ring:
- \( a(b + c) = ab + ac \)
- \( (a + b)c = ac + bc \)
In the context of the original exercise, the distributive law allows users to expand and simplify expressions during the inductive step of the proof process, ensuring that terms can be rearranged and combined according to prescribed rules, thus demonstrating the equivalence of expressions for multiplying elements in a ring.
Proof Techniques
Proof techniques are systematic methods used to demonstrate the truth of mathematical statements. One prominent technique, as used in the original exercise, is mathematical induction.
Mathematical induction involves two main steps:
Induction is powerful because it leverages a small starting point to extrapolate to infinity. This is particularly effective in proofs that involve sequences or operations defined recursively, like the ones in the exercise involving rings, where multiplication across elements is defined through repeated addition.
Mathematical induction involves two main steps:
- Base case: Prove the statement for an initial value, often the smallest in the domain, like \( n = 1 \).
- Inductive step: Assume the statement holds for a generic value \( k \), then prove it holds for \( k + 1 \).
Induction is powerful because it leverages a small starting point to extrapolate to infinity. This is particularly effective in proofs that involve sequences or operations defined recursively, like the ones in the exercise involving rings, where multiplication across elements is defined through repeated addition.
Other exercises in this chapter
Problem 5
In any ordered integral domain, define \(|a|\) by $$ |a|=\left\\{\begin{array}{rll} a & \text { if } & a \geq 0 \\ -a & \text { if } & a
View solution Problem 5
Let \(A\) be an ordered integral domain. Prove the following, for all \(a, b\), and \(c\) in \(A\). $$ a^{2}+b^{2}+c^{2} \geq a b+b c+a c $$
View solution Problem 6
Prove the following, where \(\mathrm{k}, \mathrm{m}, \mathrm{n}, \mathrm{q}\), and \(\mathrm{r}\) designate integers. If \(\mathrm{r}\) is the remainder when \(
View solution Problem 6
In any ordered integral domain, define \(|a|\) by $$ |a|=\left\\{\begin{array}{rll} a & \text { if } & a \geq 0 \\ -a & \text { if } & a
View solution