Problem 6
Question
The \(n\) th term of a sequence is given. (a) Find the first five terms of the sequence. (b) What is the common ratio \(r ?\) (c) Graph the terms you found in (a). $$ a_{n}=3(-4)^{n-1} $$
Step-by-Step Solution
Verified Answer
The terms are 3, -12, 48, -192, 768; common ratio \(r\) is -4.
1Step 1: Understanding the Formula
The formula for the sequence is given by \( a_{n} = 3(-4)^{n-1} \). This is a geometric sequence with an initial term multiplied by a power of the base number -4. The exponent is \( n-1 \), which starts at 0 for the first term.
2Step 2: Calculate the First Term \(a_1\)
For the first term, substitute \( n = 1\) into the formula:\[a_1 = 3(-4)^{1-1} = 3(-4)^0 = 3 \times 1 = 3\]
3Step 3: Calculate the Second Term \(a_2\)
Substitute \( n = 2 \) into the formula:\[a_2 = 3(-4)^{2-1} = 3(-4)^1 = 3 \times (-4) = -12\]
4Step 4: Calculate the Third Term \(a_3\)
Substitute \( n = 3 \) into the formula:\[a_3 = 3(-4)^{3-1} = 3(-4)^2 = 3 \times 16 = 48\]
5Step 5: Calculate the Fourth Term \(a_4\)
Substitute \( n = 4 \) into the formula:\[a_4 = 3(-4)^{4-1} = 3(-4)^3 = 3 \times (-64) = -192\]
6Step 6: Calculate the Fifth Term \(a_5\)
Substitute \( n = 5 \) into the formula:\[a_5 = 3(-4)^{5-1} = 3(-4)^4 = 3 \times 256 = 768\]
7Step 7: Listing the First Five Terms
The first five terms of the sequence based on our calculations are:1. \(a_1 = 3\)2. \(a_2 = -12\)3. \(a_3 = 48\)4. \(a_4 = -192\)5. \(a_5 = 768\)
8Step 8: Determine the Common Ratio \(r\)
The common ratio \( r \) is found by dividing any term by the previous term. Using \( a_2 \) and \( a_1 \): \[r = \frac{a_2}{a_1} = \frac{-12}{3} = -4\]
9Step 9: Graphing the Terms
To graph the first five terms, position them on a coordinate system with the term number \( n \) on the x-axis and the value of \( a_n \) on the y-axis. The points will be: \((1, 3), (2, -12), (3, 48), (4, -192), (5, 768)\). Plot and connect these points to visually represent the sequence.
Key Concepts
Common RatioSequence TermsGraphing Sequences
Common Ratio
The concept of a common ratio is key in understanding geometric sequences. In our sequence, the common ratio \( r \) is the number we multiply each term by to get to the next term. To find \( r \), you can take any term in the sequence and divide it by the preceding term.
For example, looking at the first two terms we calculated:
This constant factor \( r \) remains the same for any two consecutive terms, showing the consistent multiplying effect throughout the sequence.
For example, looking at the first two terms we calculated:
- The first term \( a_1 = 3 \)
- The second term \( a_2 = -12 \)
This constant factor \( r \) remains the same for any two consecutive terms, showing the consistent multiplying effect throughout the sequence.
Sequence Terms
In a geometric sequence, each term is derived from the previous one by multiplying by the common ratio. The term formula for our sequence is given by \[ a_{n} = 3(-4)^{n-1} \]. To find the sequence terms, you'd plug in different values of \( n \).
Let's review the process:
Let's review the process:
- First term \( a_1 = 3 \)
- Second term \( a_2 = -12 \)
- Third term \( a_3 = 48 \)
- Fourth term \( a_4 = -192 \)
- Fifth term \( a_5 = 768 \)
Graphing Sequences
Graphing a sequence can help visualize how it behaves and changes over the term numbers. To graph the sequence, you plot term number \( n \) on the x-axis and the term value \( a_n \) on the y-axis.
For the sequence terms we calculated, the points are:
The graph will not only illustrate the alternating positive and negative growth but also highlight how quickly these values escalate or decline. This visualization confirms the unique exponential nature of geometric sequences.
For the sequence terms we calculated, the points are:
- (1, 3)
- (2, -12)
- (3, 48)
- (4, -192)
- (5, 768)
The graph will not only illustrate the alternating positive and negative growth but also highlight how quickly these values escalate or decline. This visualization confirms the unique exponential nature of geometric sequences.
Other exercises in this chapter
Problem 6
Use Pascal’s triangle to expand the expression. $$ (2 x+1)^{4} $$
View solution Problem 6
Use mathematical induction to prove that the formula is true for all natural numbers \(n\). $$ 1^{2}+2^{2}+3^{2}+\cdots+n^{2}=\frac{n(n+1)(2 n+1)}{6} $$
View solution Problem 6
Annuity Find the amount of an annuity that consists of 20 semiannual payments of \(\$ 500\) each into an account that pays 6\(\%\) interest per year, compounded
View solution Problem 7
\(5-8=\) A sequence is given. (a) Find the first five terms of the sequence. (b) What is the common difference \(d ?\) (c) Graph the terms you found in (a). $$
View solution