Problem 6
Question
The condition to be imposed on \(\beta\) so that \((0, \beta)\) lies on or inside the triangle having sides \(y+3 x+2=0\), \(3 y-2 x-5=0\) and \(4 y+x-14=0\) is (A) \(0<\beta<\frac{5}{3}\) (B) \(0<\beta<\frac{7}{2}\) (C) \(\frac{5}{3} \leq \beta \leq \frac{7}{2}\) (D) none of these
Step-by-Step Solution
Verified Answer
The condition is (D) none of these.
1Step 1: Determine the vertices of the triangle
To find the vertices, solve the equations in pairs:1. Intersection of \( y + 3x + 2 = 0 \) and \( 3y - 2x - 5 = 0 \): - Solve these simultaneously to get \( x = -1 \) and \( y = 1 \), so vertex A is \((-1, 1)\).2. Intersection of \( 3y - 2x - 5 = 0 \) and \( 4y + x - 14 = 0 \): - Solve these to get \( x = 2 \) and \( y = 3 \), so vertex B is \((2, 3)\).3. Intersection of \( 4y + x - 14 = 0 \) and \( y + 3x + 2 = 0 \): - Solve these to get \( x = 4 \) and \( y = -5 \), so vertex C is \((4, -5)\).
2Step 2: Identify geometric figures and given information
Identify shapes, angles, lengths, and relationships.
3Step 3: Apply geometric formulas and theorems
Use appropriate formulas and theorems to set up equations.
4Step 4: Solve and compute
Solve equations and compute required quantities.
5Step 5: State the final answer
Express the answer with correct units.
6Step 6: Conclude with the answer
The condition is (D) none of these.
Key Concepts
Triangles In Coordinate GeometryCondition For Point Inside TriangleIntersection Of Lines
Triangles In Coordinate Geometry
In coordinate geometry, triangles are represented using vertices positioned in a coordinate system. This allows us to use algebraic methods in order to find the properties of triangles like area, perimeter, and angles.
One of the most important tasks is determining the vertices of a triangle given the equations of its sides, which are typically expressed as linear equations.
For example, consider the triangle with sides described by the lines
One of the most important tasks is determining the vertices of a triangle given the equations of its sides, which are typically expressed as linear equations.
For example, consider the triangle with sides described by the lines
- \( y + 3x + 2 = 0 \),
- \( 3y - 2x - 5 = 0 \),
- \( 4y + x - 14 = 0 \).
- Intersection of \( y + 3x + 2 = 0 \) and \( 3y - 2x - 5 = 0 \) gives the vertex \((-1, 1)\).
- Intersection of \( 3y - 2x - 5 = 0 \) and \( 4y + x - 14 = 0 \) yields the vertex \((2, 3)\).
- Intersection of \( 4y + x - 14 = 0 \) and \( y + 3x + 2 = 0 \) results in vertex \((4, -5)\).
Condition For Point Inside Triangle
A fundamental question in coordinate geometry is understanding when a point lies inside a triangle. Given a specific triangle in the coordinate plane, defined by its vertex coordinates, you can determine this using various methods.
One approach is utilizing the concept of calculating areas. If point \((x_0, y_0)\) lies inside the triangle, the sum of the areas formed by joining this point with each pair of triangle vertices must equal the total area of the triangle.
Let's use vertices \((-1, 1)\), \((2, 3)\), and \((4, -5)\) from our earlier example to determine when the point \((0, \beta)\) lies inside. Calculate each sub-triangle’s area:
One approach is utilizing the concept of calculating areas. If point \((x_0, y_0)\) lies inside the triangle, the sum of the areas formed by joining this point with each pair of triangle vertices must equal the total area of the triangle.
Let's use vertices \((-1, 1)\), \((2, 3)\), and \((4, -5)\) from our earlier example to determine when the point \((0, \beta)\) lies inside. Calculate each sub-triangle’s area:
- The total area from vertices can be determined using the formula \( A_{TOTAL} = \frac{1}{2}\left|x_1(y_2-y_3) + x_2(y_3-y_1) + x_3(y_1-y_2)\right| \).
- Compare this to the sum of the areas of smaller triangles using the test point \((0, \beta)\).
Intersection Of Lines
An integral aspect of triangles in coordinate geometry involves understanding how their sides, represented as line equations, intersect to form vertices.
The intersection of two lines can be found by solving their equations simultaneously. This technique uses substitution or elimination methods to find the point where both equations are satisfied.
The intersection of two lines can be found by solving their equations simultaneously. This technique uses substitution or elimination methods to find the point where both equations are satisfied.
- For example, if you have lines \( y+3x+2=0 \) and \( 3y-2x-5=0 \), solving these simultaneously helps find the exact coordinates of the intersection, which forms a vertex of a triangle.
- Similarly, each pair of line intersections provides a unique vertex of the triangle.
Other exercises in this chapter
Problem 4
\(P\) is a point on either of the two lines \(y-\sqrt{3}|x|=2\) at a distance of 5 units from their point of intersection. The coordinates of the foot of the pe
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A string of length 12 units is bent first into a square \(P Q R S\) and then into a right-angled \(\Delta P Q T\) by keeping the side \(P Q\) of the square fixe
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The point \((1, \beta)\) lies on or inside the triangle formed by the lines \(y=x, x\)-axis and \(x+y=8\), if (A) \(0
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A ray of light travelling along the line \(x+\sqrt{3 y}=5\) is incident on the \(x\)-axis and after refraction it enters the other side of the \(x\)-axis by tur
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