Problem 6
Question
The buyer of a lottery ticket chooses four numbers from the numbers 1 to \(32 .\) Repetition is not allowed. a. How many combinations of four numbers are possible? b. What is the probability of choosing all four of the winning numbers?
Step-by-Step Solution
Verified Answer
a. 35,960 combinations are possible. b. Probability is \( \frac{1}{35960} \).
1Step 1: Understand the problem
We are choosing 4 different numbers from a set of 32 numbers, without repetition. We need to calculate how many combinations of these 4 numbers are possible and the probability of choosing the winning set of numbers.
2Step 2: Calculate the number of combinations
Since repetition is not allowed, and the order does not matter, we use the combination formula \[ C(n, r) = \frac{n!}{r!(n-r)!} \]where \( n = 32 \) and \( r = 4 \). Plugging in the values, we have:\[ C(32, 4) = \frac{32!}{4!(32-4)!} = \frac{32 \times 31 \times 30 \times 29}{4 \times 3 \times 2 \times 1} = 35960 \]
3Step 3: Calculate probability of winning
To win, you must pick exactly the 4 winning numbers. There is only one set of these numbers. The probability \( P \) is calculated as:\[ P = \frac{\text{Number of winning combinations}}{\text{Total number of combinations}} = \frac{1}{35960} \]
4Step 4: Conclusion
There are 35,960 possible combinations of choosing 4 numbers out of 32. The probability of choosing all four winning numbers is very small, specifically \( \frac{1}{35960} \).
Key Concepts
Understanding ProbabilityIntroduction to the Combination FormulaCalculating Lottery Probability
Understanding Probability
Probability is a fundamental concept in mathematics that measures how likely an event is to occur. It's basically a way to quantify uncertainty, measuring how often different events happen compared to all possible events.
A probability ranges between 0 and 1, where 0 means an event will not happen, and 1 means it will definitely happen. In the context of our lottery problem, the event is choosing the winning set of numbers.
A probability ranges between 0 and 1, where 0 means an event will not happen, and 1 means it will definitely happen. In the context of our lottery problem, the event is choosing the winning set of numbers.
- A probability of 0 indicates an impossible event.
- A probability of 1 indicates a certain event.
- The probability of all possible outcomes is equal to 1.
Introduction to the Combination Formula
The combination formula is used when you are choosing a set number of items from a larger pool, and the order of selection does not matter. It calculates the number of potential groups (or combinations) that can be made.
The formula is given by:\[ C(n, r) = \frac{n!}{r!(n-r)!} \]
The formula is given by:\[ C(n, r) = \frac{n!}{r!(n-r)!} \]
- Here, \( n \) is the total number of items to choose from.
- \( r \) is the number of items to choose.
- The exclamation mark (!) denotes a factorial, which is the product of an integer and all the integers below it.
Calculating Lottery Probability
Calculating lottery probability means determining the likelihood of picking the correct combination from a set of possible combinations. This involves two key steps: finding the total number of combinations first and then determining the probability of winning.
Using the lottery scenario from our exercise:
Using the lottery scenario from our exercise:
- We calculated that there are 35,960 possible combinations of choosing 4 numbers from 32.
- Since there is only one winning combination, the probability is \( \frac{1}{35960} \).
Other exercises in this chapter
Problem 6
In \(3-6,\) find exact probabilities showing all required computation. A multiple-choice test of 10 questions has 4 choices for each question. Only one choice i
View solution Problem 6
In \(6-9,\) write an expression using sigma notation that can be used to find each probability. At least 10 heads when 15 coins are tossed
View solution Problem 6
In \(3-22,\) evaluate each expression. $$ 9 ! \div 8 ! $$
View solution Problem 6
For the given values of \(r\) and \(n,\) find the number of ordered selections of \(r\) objects from a collection of \(n\) objects without replacement. \(r=2, n
View solution