Problem 6
Question
Suppose that \(\triangle A B C\) is a right triangle with \(\angle C=90^{\circ}\) If \(A C=6\) and \(B C=2,\) find the following quantities. (a) \(\cos A, \sin A, \tan A\) (b) \(\sec B, \csc B, \cot B\)
Step-by-Step Solution
Verified Answer
(a) \(\cos A = \frac{\sqrt{10}}{10}, \sin A = \frac{3\sqrt{10}}{10}, \tan A = 3\); (b) \(\sec B = \sqrt{10}, \csc B = \frac{\sqrt{10}}{3}, \cot B = \frac{1}{3}\).
1Step 1: Identify the Triangle Sides
In triangle ABC, angle C is the right angle. AC is the opposite side to angle B, and BC is the adjacent side to angle A. The hypotenuse (AB) needs to be calculated.
2Step 2: Use the Pythagorean Theorem
Apply the Pythagorean theorem to find the hypotenuse: \[ AB = \sqrt{AC^2 + BC^2} = \sqrt{6^2 + 2^2} = \sqrt{36 + 4} = \sqrt{40} = 2\sqrt{10} \]
3Step 3: Calculate Trigonometric Ratios for Angle A
Calculate \(\cos A, \sin A, \tan A\) using known sides:1. \(\cos A = \frac{BC}{AB} = \frac{2}{2\sqrt{10}} = \frac{1}{\sqrt{10}} = \frac{\sqrt{10}}{10}\)2. \(\sin A = \frac{AC}{AB} = \frac{6}{2\sqrt{10}} = \frac{3}{\sqrt{10}} = \frac{3\sqrt{10}}{10}\)3. \(\tan A = \frac{AC}{BC} = \frac{6}{2} = 3\)
4Step 4: Calculate Trigonometric Ratios for Angle B
Calculate \(\sec B, \csc B, \cot B\) using known sides:1. \(\sec B = \frac{AB}{BC} = \frac{2\sqrt{10}}{2} = \sqrt{10}\)2. \(\csc B = \frac{AB}{AC} = \frac{2\sqrt{10}}{6} = \frac{\sqrt{10}}{3}\)3. \(\cot B = \frac{BC}{AC} = \frac{2}{6} = \frac{1}{3}\)
Key Concepts
Pythagorean theoremtrigonometric ratioshypotenuse calculation
Pythagorean theorem
Understanding the Pythagorean theorem is key when working with right triangles. This classic theorem relates the lengths of the sides of a right triangle. In any right triangle, the sum of the squares of the two shorter sides (legs) is equal to the square of the longest side, known as the hypotenuse.
The formula is expressed as:
The formula is expressed as:
- \[ a^2 + b^2 = c^2 \]
- \(a\) and \(b\) are the lengths of the legs.
- \(c\) is the hypotenuse.
trigonometric ratios
Trigonometric ratios provide a way to relate the angles and sides of a right triangle. These ratios are often used in problems involving right triangles and are fundamental in trigonometry.
The primary trigonometric ratios are:
The primary trigonometric ratios are:
- Cosine (\(\cos\)): the ratio of the adjacent side to the hypotenuse.
- Sine (\(\sin\)): the ratio of the opposite side to the hypotenuse.
- Tangent (\(\tan\)): the ratio of the opposite side to the adjacent side.
- \(\cos A\) was calculated as \(\frac{BC}{AB}\).
- \(\sin A\) was \(\frac{AC}{AB}\).
- \(\tan A\) was \(\frac{AC}{BC}\).
hypotenuse calculation
Calculating the hypotenuse is a common task in many right triangle problems and can be quite straightforward with the right tools, like the Pythagorean theorem. The hypotenuse is always the side opposite the right angle and is the longest side in a right triangle.
In the original exercise, we used the Pythagorean theorem to find the hypotenuse, where we first squared the other two sides and then took the square root of their sum. This process gives you the length of the hypotenuse directly once other sides are known.
In the original exercise, we used the Pythagorean theorem to find the hypotenuse, where we first squared the other two sides and then took the square root of their sum. This process gives you the length of the hypotenuse directly once other sides are known.
- Use the formula \[ AB = \sqrt{AC^2 + BC^2} \]
Other exercises in this chapter
Problem 5
Convert to radian measure. Express your answers both in terms of \(\pi\)and as decimal approximations rounded to two decimal places. (a) \(45^{\circ}\) (b) \(90
View solution Problem 6
Carry out the indicated operations. (a) \((3-2 T)^{2}\) (b) \((3-2 \tan \theta)^{2}\)
View solution Problem 6
Sketch each angle in standard position. (a) \(45^{\circ}\) (b) \(-225^{\circ}\) (c) \(315^{\circ}\)
View solution Problem 6
Convert to radian measure. Express your answers both in terms of \(\pi\)and as decimal approximations rounded to two decimal places. (a) \(30^{\circ}\) (b) \(15
View solution