Problem 6
Question
Suppose $$\$ 1000$$ is invested in an account paying interest at a rate of \(5.5 \%\) per year. How much is in the account after 8 years if the interest is compounded (a) Annually? (b) Continuously?
Step-by-Step Solution
Verified Answer
(a) \$1518.10; (b) \$1553.60.
1Step 1: Understand the Formula for Annually Compounded Interest
When interest is compounded annually, the formula to calculate the total amount is given by: \[ A = P(1 + r)^n \] where \( A \) is the amount of money accumulated after \( n \) years, including interest, \( P \) is the principal amount (initial investment), \( r \) is the annual interest rate (decimal), and \( n \) is the number of years.
2Step 2: Calculate the Annual Compound Interest
Given \( P = 1000 \), \( r = 0.055 \), and \( n = 8 \), substitute these values into the formula: \[ A = 1000(1 + 0.055)^8 \] From this, calculate: \[ A = 1000(1.055)^8 \] \[ A \approx 1000 imes 1.5181 \] \[ A \approx 1518.10 \] Therefore, there will be approximately \( \$ 1518.10 \) in the account after 8 years.
3Step 3: Understand the Formula for Continuously Compounded Interest
When interest is compounded continuously, the formula to calculate the total amount is given by: \[ A = Pe^{rt} \] where \( e \) is the base of the natural logarithm (approximately 2.71828), \( A \) is the amount of money accumulated after \( t \) years, \( P \) is the principal amount, \( r \) is the annual interest rate, and \( t \) is the number of years.
4Step 4: Calculate the Continuous Compound Interest
Given \( P = 1000 \), \( r = 0.055 \), and \( t = 8 \), substitute these values into the formula: \[ A = 1000 \times e^{0.055 \times 8} \] Calculate the exponent: \[ 0.055 \times 8 = 0.44 \] Therefore, \[ A = 1000 \times e^{0.44} \] Using a calculator to find \( e^{0.44} \): \[ e^{0.44} \approx 1.5536 \] Thus, \[ A \approx 1000 \times 1.5536 \] \[ A \approx 1553.60 \] Therefore, there will be approximately \( \$ 1553.60 \) in the account after 8 years if compounded continuously.
Key Concepts
Understanding Continuously Compounded InterestAnnually Compounded Interest ExplainedCalculating Interest Rates Made Easy
Understanding Continuously Compounded Interest
Continuously compounded interest is a concept where interest is calculated and added to the principal balance at every possible instant. This method uses the formula \( A = Pe^{rt} \), where:
In scenarios where banks or investors want to compound interest as frequently as possible, they use this continuous method, making use of modern computational capabilities.
For example, if you were to invest $1000 at an annual interest rate of 5.5% for 8 years, using continuous compounding, you can calculate \( A = 1000 \times e^{0.055 \times 8} \). This results in roughly \( 1553.60 \), showing the power of continuously letting your investment grow.
- \( A \) is the amount of money accumulated after time \( t \),
- \( P \) is the principal amount,
- \( r \) is the annual interest rate expressed in decimal form,
- \( t \) is the time the money is invested for, in years.
In scenarios where banks or investors want to compound interest as frequently as possible, they use this continuous method, making use of modern computational capabilities.
For example, if you were to invest $1000 at an annual interest rate of 5.5% for 8 years, using continuous compounding, you can calculate \( A = 1000 \times e^{0.055 \times 8} \). This results in roughly \( 1553.60 \), showing the power of continuously letting your investment grow.
Annually Compounded Interest Explained
When interest is compounded annually, it means that the interest is added to the principal once a year. This conventional method is easier to calculate and understand. The formula used here is \( A = P(1 + r)^n \), where:
This exponentiation means you multiply the factor \( 1.055 \) by itself 8 times. Using this annually compounded method, the total accumulated amount would be approximately \( 1518.10 \).
This traditional method illustrates how compound interest grows over time, though less rapidly than continuous compounding.
- \( A \) is the accumulated amount after \( n \) years,
- \( P \) is the initial principal invested,
- \( r \) is the annual interest rate expressed as a decimal,
- \( n \) is the number of years the money is invested for.
This exponentiation means you multiply the factor \( 1.055 \) by itself 8 times. Using this annually compounded method, the total accumulated amount would be approximately \( 1518.10 \).
This traditional method illustrates how compound interest grows over time, though less rapidly than continuous compounding.
Calculating Interest Rates Made Easy
Calculating interest rates effectively requires understanding the role they play in financial growth. To convert a percentage to a decimal, you need to divide by 100. So for an interest rate of 5.5%, the decimal form is \( 0.055 \).
Recognizing the decimal form is crucial when inserting rates into compounding formulas. For instance, in both continuously and annually compounded scenarios, the consistent use of the decimal form simplifies calculations.
Understanding the importance of accurate rate calculation will help you predict investment growth accurately. This skill ensures that you can compare different compounding techniques or evaluate potential return on various financial opportunities.
Recognizing the decimal form is crucial when inserting rates into compounding formulas. For instance, in both continuously and annually compounded scenarios, the consistent use of the decimal form simplifies calculations.
Understanding the importance of accurate rate calculation will help you predict investment growth accurately. This skill ensures that you can compare different compounding techniques or evaluate potential return on various financial opportunities.
Other exercises in this chapter
Problem 6
Determine whether or not the function is a power function. If it is a power function, write it in the form \(y=k x^{p}\) and give the values of \(k\) and \(p\).
View solution Problem 6
For the functions \(f\) and \(g\), find (a) \(f(g(1))\) (b) \(g(f(1))\) (c) \(f(g(x))\) (d) \(g(f(x))\) (e) \(f(t) g(t)\) $$f(x)=1 / x, g(x)=3 x+4$$
View solution Problem 6
Solve for \(t\) using natural logarithms. $$100=25(1.5)^{t}$$
View solution Problem 6
The demand curve for a quantity \(q\) of a product is \(q=\) \(5500-100 p\) where \(p\) is price in dollars. Interpret the 5500 and the 100 in terms of demand.
View solution