Problem 6
Question
Solve. $$ \sqrt{5 x}=-5 $$
Step-by-Step Solution
Verified Answer
No solution exists because \( \sqrt{5x} \) cannot be negative.
1Step 1: Understand the Equation
The equation at hand is \( \sqrt{5x} = -5 \). We need to find \( x \) such that this equation holds true.
2Step 2: Review the Properties of Square Roots
Recall that the square root function \( \sqrt{} \) only returns non-negative values, meaning \( \sqrt{5x} \) cannot be negative. This implies that there is a contradiction in the equation because it equates a non-negative number to -5.
3Step 3: Identify the Impossibility
Since no real number can be squared to yield a negative result, and since the equation requires the square root to equal -5, it is clear that no solution exists.
Key Concepts
Properties of Square RootsNo Solution in Real NumbersAlgebraic Contradictions
Properties of Square Roots
Square roots are fundamental in mathematics and understanding their properties is essential when solving equations like \( \sqrt{5x} = -5 \). A key property of square roots is that they always produce non-negative outputs. This means:
- The square root of any positive number is positive.
- The square root of zero is zero.
- Simplifying further, square roots yield non-negative results, making it impossible for \( \sqrt{5x} \) to be negative.
No Solution in Real Numbers
When analyzing equations involving square roots, especially those resulting in negative values like \( \sqrt{5x} = -5 \), notice how crucial it is to acknowledge that no real number can satisfy such conditions. Here’s why:
- Since the square root function only outputs non-negative values, and \(-5\) is a negative number, it is impossible for the equation to hold true within the set of real numbers.
- This rule holds regardless of the value of \( 5x \), because even if \( 5x \) is a positive number, the result cannot be negative.
Algebraic Contradictions
In mathematics, an algebraic contradiction occurs when an equation presents an inherent logical conflict. Equations like \( \sqrt{5x} = -5 \) are prime examples. Let's examine why:
- Algebraic contradictions arise when the algebraic expression and its expected output are fundamentally irreconcilable under given properties, such as with square roots.
- In this specific case, the contradiction is between a mathematically impossible task: making a naturally non-negative square root equal a negative number.
Other exercises in this chapter
Problem 5
Use the product rule to multiply. Assume that all variables represent positive real numbers. $$ \sqrt[3]{4} \cdot \sqrt[3]{9} $$
View solution Problem 5
Write using i notation. $$ 8 \sqrt{-63} $$
View solution Problem 6
Rationalize each denominator. Assume that all variables represent positive real numbers. \(\frac{6}{\sqrt[3]{9}}\)
View solution Problem 6
Find the real square roots of each number. $$ 64 $$
View solution