Problem 6
Question
Simplify the expression. If not possible, write already in simplest form. $$ \frac{12 x^{2}}{6 x} $$
Step-by-Step Solution
Verified Answer
The simplified expression of \(\frac{12x^{2}}{6x}\) is \(2x\).
1Step 1: Identify common factors
In this case, \(12x^{2}\) and \(6x\), it is evident that both expressions are divisible by \(6x\). Therefore, \(6x\) is the common term.
2Step 2: Simplify the expression
To simplify the expression, divide both the numerator and denominator by the common term: \(\frac{12x^{2}}{6x} = \frac{12x^{2}/6x}{6x/6x} = \frac{2x}{1}\)
3Step 3: Final Simplified Expression
Since we can't divide any further, the expression is in its simplest form. Writing the final expression without the denominator 1, we get \(2x\).
Key Concepts
Common FactorsNumerator and DenominatorSimplest Form
Common Factors
Simplifying algebraic expressions often involves identifying common factors. A common factor is a number or expression that divides two or more numbers or expressions without leaving a remainder. In our exercise, the expressions in the numerator and denominator are \(12x^2\) and \(6x\), respectively.
Finding a common factor is just like sharing something evenly among a group. You want to find what can evenly divide both the top (numerator) and the bottom (denominator) of your fraction.
Finding a common factor is just like sharing something evenly among a group. You want to find what can evenly divide both the top (numerator) and the bottom (denominator) of your fraction.
- Look at the numbers: 12 and 6. Both can be divided by 6 evenly.
- Look at the variables: \(x^2\) and \(x\). Both share \(x\) as a factor.
Numerator and Denominator
In fractions, the numerator is the top part, and the denominator is the bottom part. These elements tell us how many parts we are looking at (numerator) out of how many total parts (denominator).
More specifically, examining the expression \(\frac{12x^2}{6x}\), the numerator is \(12x^2\), meaning we have 12 times the square of \(x\). The denominator is \(6x\), which gives context as six parts of an \(x\). To simplify, understanding how the numerator and denominator relate helps establish what can "cancel out" by dividing both parts by their greatest common factor.
Remember:
More specifically, examining the expression \(\frac{12x^2}{6x}\), the numerator is \(12x^2\), meaning we have 12 times the square of \(x\). The denominator is \(6x\), which gives context as six parts of an \(x\). To simplify, understanding how the numerator and denominator relate helps establish what can "cancel out" by dividing both parts by their greatest common factor.
Remember:
- The denominator cannot be zero, as division by zero is undefined.
- The process focuses on dividing both parts by exactly the same factor to keep the expression's value unchanged.
Simplest Form
Achieving the simplest form of an algebraic expression means reducing it as much as possible while keeping its value. When an expression is simplified, it is easier to understand and use for further calculations.
In our example, once you divide both the numerator \(12x^2\) and the denominator \(6x\) by the common factor \(6x\), you are left with \(\frac{2x}{1}\). This simplifies further to just \(2x\), eliminating the unnecessary "1" in the denominator.
Understanding this process is empowering for tackling more advanced algebraic problems, as it is a fundamental building block for resolving equations efficiently.
In our example, once you divide both the numerator \(12x^2\) and the denominator \(6x\) by the common factor \(6x\), you are left with \(\frac{2x}{1}\). This simplifies further to just \(2x\), eliminating the unnecessary "1" in the denominator.
- Simplification ensures there are no common factors left in the expression.
- This step reduces complexity in solving equations or inequalities involving the expression.
- It also provides clarity in communication. A simpler expression is straightforward, aiding comprehension and minimizing errors.
Understanding this process is empowering for tackling more advanced algebraic problems, as it is a fundamental building block for resolving equations efficiently.
Other exercises in this chapter
Problem 6
Solve the proportion. Check your solution. $$ \frac{2}{2 x+1}=\frac{1}{5} $$
View solution Problem 6
Simplify the expression. $$\frac{3 x}{x^{2}-2 x-15} \cdot(x+3)$$
View solution Problem 7
Does the equation model direct variation, inverse variation, or neither? $$ y=7 x-2 $$
View solution Problem 7
Subtract. Simplify your answer. $$ \frac{c+1}{c^{2}-4}-\frac{c+6}{c^{2}-4} $$
View solution