Problem 6
Question
Show that it is not necessarily the case that if \(f: D \rightarrow \mathbb{R}\) and \(g: D \rightarrow \mathbb{R}\) are each uniformly continuous, then so is the product \(f g: D \rightarrow \mathbb{R}\)
Step-by-Step Solution
Verified Answer
By choosing f(x) = g(x) = x, which are uniformly continuous, their product f(x)g(x) = x^2 is not uniformly continuous on \(\mathbb{R}\) as the difference \(|x^2 - y^2|\) can be made arbitrarily large for any chosen \(\delta\), by choosing sufficiently large values of y.
1Step 1: Understanding Uniform Continuity
Firstly, recall the definition of uniform continuity for a function f defined on a domain D. A function f is uniformly continuous if, for every positive number \(\epsilon\), there exists a \(\delta\) such that for all x and y in D, if \(|x - y| < \delta\), then \(|f(x) - f(y)| < \epsilon\).
2Step 2: Understanding the Problem
The task is to show that even though functions f and g are each uniformly continuous individually, their product fg may not be uniformly continuous. To do this, we'll provide a counterexample.
3Step 3: Selecting a Counterexample
Let's choose two functions where D is the set of all real numbers \(\mathbb{R}\), so let \(f(x) = g(x) = x\), which are uniformly continuous on \(\mathbb{R}\).
4Step 4: Analyzing the Product Function
The product function \((fg)(x) = f(x)g(x) = x^2\), we will examine whether this function is uniformly continuous on \(\mathbb{R}\).
5Step 5: Attempting to Find a Uniform \(\delta\)
Assuming that \(f(x)g(x) = x^2\) is uniformly continuous, for every \(\epsilon > 0\), there would be a \(\delta > 0\) such that for all x and y in \(\mathbb{R}\), if \(|x - y| < \delta\), it would imply \(|x^2 - y^2| < \epsilon\).
6Step 6: Finding a Contradiction
Consider the points x and y such that \(x = y + \delta/2\). Now consider \(|x^2 - y^2| = |x-y||x+y| = \delta/2|2y + \delta/2| = \delta|y + \delta/4|\), which can be made arbitrarily large by choosing a sufficiently large y, for any fixed delta. This does not satisfy the uniform continuity condition where \(|x^2 - y^2|\) needs to be less than any \(\epsilon\) we choose.
Key Concepts
CounterexampleUniformly Continuous FunctionsContinuity in CalculusProduct of Functions
Counterexample
When studying concepts in mathematics, it's often as essential to know when a rule does not apply as when it does. This is where a counterexample comes into play. A counterexample is a specific case that shows a general statement to be false. In the context of uniform continuity, if you are told that the product of two uniformly continuous functions is also uniformly continuous, providing a counterexample can effectively disprove this claim.
Approaching this task begins with understanding the definitions perfectly and then crafting a scenario where those definitions break down. Here, by considering two simple uniformly continuous functions, namely f(x) = x and g(x) = x, and demonstrating that their product f(x)g(x) = x^2 fails the test for uniform continuity, we find such a counterexample.
Approaching this task begins with understanding the definitions perfectly and then crafting a scenario where those definitions break down. Here, by considering two simple uniformly continuous functions, namely f(x) = x and g(x) = x, and demonstrating that their product f(x)g(x) = x^2 fails the test for uniform continuity, we find such a counterexample.
Uniformly Continuous Functions
The idea of uniform continuity is a tightened version of the basic concept of continuity. While a continuous function guarantees that small changes in input produce small changes in output, uniform continuity ensures this phenomenon is consistent throughout the function's entire domain. Formally, for a function f defined on a domain D, it is uniformly continuous if, given any ε > 0, there exists a δ > 0 such that for all x, y ∈ D, whenever |x - y| < δ, it follows that |f(x) - f(y)| < ε.
The importance of uniform continuity comes from its power in analysis, especially regarding integration and limits, as it ensures controlled behavior on potentially wild domains like the set of all real numbers.
The importance of uniform continuity comes from its power in analysis, especially regarding integration and limits, as it ensures controlled behavior on potentially wild domains like the set of all real numbers.
Continuity in Calculus
Continuity in calculus is a fundamental concept that is required for the understanding of limits, derivatives, and integrals. A function is considered continuous at a point if a tiny movement in the input value results in a predictably small change in the output value. This leads to the classic definition: a function f is continuous at a point a if the limit of f(x) as x approaches a equals f(a).
To extend this concept throughout an entire domain, the notion of uniform continuity emerges. It's this extension that ensures functions behave nicely everywhere, not just at isolated points, making them more predictable and easier to work with in advanced mathematical discussions.
To extend this concept throughout an entire domain, the notion of uniform continuity emerges. It's this extension that ensures functions behave nicely everywhere, not just at isolated points, making them more predictable and easier to work with in advanced mathematical discussions.
Product of Functions
Considering the product of functions is another vital operation in calculus. When two functions, say f and g, are multiplied together, the resulting function h(x) = f(x)g(x) represents their product. The behavior of the product function can be more complicated than its individual factors.
Even if f and g are each uniformly continuous, their product is not automatically granted the same property. It's crucial to analyze the resulting function specifically. The product might preserve uniform continuity under certain conditions but not others. This is not just a theoretical exercise—it has practical implications, such as integration and optimization within calculus, making it a core concept to comprehend fully in advanced mathematics.
Even if f and g are each uniformly continuous, their product is not automatically granted the same property. It's crucial to analyze the resulting function specifically. The product might preserve uniform continuity under certain conditions but not others. This is not just a theoretical exercise—it has practical implications, such as integration and optimization within calculus, making it a core concept to comprehend fully in advanced mathematics.
Other exercises in this chapter
Problem 5
Suppose that the functions \(h:[a, b] \rightarrow \mathbb{R}\) and \(g:[a, b] \rightarrow \mathbb{R}\) are continuous. Observe that a solution of the equation $
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If a set \(S\) contains an unbounded sequence, show that the function \(f: S \rightarrow \mathbb{R}\) defined by \(f(x)=x\) for all \(x\) in \(S,\) is continuou
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Define the function \(g: \mathbb{R} \rightarrow \mathbb{R}\) by $$ g(x)=\left\\{\begin{array}{ll} x^{2} & \text { if } x \text { is rational } \\ -x^{2} & \text
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Suppose that the functions \(f: D \rightarrow \mathbb{R}\) and \(g: D \rightarrow \mathbb{R}\) are uniformly continuous and bounded. Prove that the product \(f
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