Problem 6
Question
Show that arg \(z_{1}=\arg z_{2}\) iff \(\mathrm{z}_{2}=c z_{1}\), where \(c\) is a positive real constant.
Step-by-Step Solution
Verified Answer
\(\arg(z_1) = \arg(z_2)\) if and only if \(z_2 = cz_1\), where \(c\) is positive.
1Step 1: Understanding the Argument of a Complex Number
For any complex number \(z = x + yi\), the argument, \(\arg z\), is the angle \(\theta\) such that \(\tan(\theta) = \frac{y}{x}\). This angle can also be obtained using \(\theta = \text{atan2}(y, x)\), which accurately gives the angle in the correct quadrant.
2Step 2: Define the Equality of Arguments
The exercise states that \(\arg(z_1) = \arg(z_2)\). We have \(z_1 = x_1 + y_1i\) and \(z_2 = x_2 + y_2i\). This means that both complex numbers have the same angle with the positive real axis.
3Step 3: Relate \(z_2\) to \(z_1\) with a Positive Constant
If \(\arg(z_1) = \arg(z_2)\), it implies that \(z_1\) and \(z_2\) lie on the same line in the complex plane passing through the origin. Hence, \(z_2\) can be expressed as \(z_2 = cz_1\) where \(c\) is a positive real constant. This is because only a scaling factor that is positive (keeping the angle unchanged) can map one vector to another along the same line.
4Step 4: Proof of the "if and only if" Condition
For the reverse direction, if \(z_2 = cz_1\) where \(c > 0\), then the magnitude of \(z_2\) is scaled by \(c\) but the argument remains the same since multiplying by a positive real number does not change the angle. Hence, \(\arg(z_1) = \arg(z_2)\) still holds. Therefore, we have shown that "if and only if" condition holds. $$
Key Concepts
Argument of a Complex NumberComplex PlaneScaling in Complex Numbers
Argument of a Complex Number
Understanding the argument of a complex number is important when exploring how complex numbers interact geometrically. Each complex number can be expressed as \(z = x + yi\), where \(x\) and \(y\) are real numbers and \(i\) is the imaginary unit satisfying \(i^2 = -1\). The argument \(\arg z\) is essentially the angle \(\theta\) between the positive real axis and the line joining the origin to the point \((x, y)\) on the complex plane. This can be calculated using the arctangent function: \(\theta = \arctan\left(\frac{y}{x}\right)\).
- Remember that \(\arg z\) is typically measured in radians.
- Functions like \(\text{atan2}(y, x)\) help identify the angle in the correct quadrant.
Complex Plane
The complex plane is a graphical representation where complex numbers are visualized as points. The plane itself has two axes, with the horizontal axis representing the real part and the vertical axis representing the imaginary part of a complex number.
- Each point or vector \((x, y)\) on this plane corresponds to the complex number \(z = x + yi\).
- The distance of a point from the origin, known as the modulus \(|z|\), is given by \(|z| = \sqrt{x^2 + y^2}\).
- Complex addition, subtraction, and multiplication can be visualized via basic geometric operations on this plane.
Scaling in Complex Numbers
Scaling is an operation that involves changing a complex number's size while maintaining its direction. In the context of complex numbers, scaling involves multiplying the number by a real constant. If you have a complex number \(z_1 = x_1 + y_1i\) and you want to obtain another complex number \(z_2\) with the same argument, you would express \(z_2\) as \(z_2 = cz_1\), where \(c\) is a positive real number.
- This operation does not alter the argument because multiplying by a positive real number scales the magnitude but not the angle.
- Graphically, both points \(z_1\) and \(z_2\) will lie on the same line originating from the origin, in the complex plane.
Other exercises in this chapter
Problem 6
Let \(z_{1}=\left(x_{1}, y_{1}\right)\) and \(z_{2}=\left(x_{2}, y_{2}\right)\) be arbitrary complex numbers. Prove or disprove the following. (a) \(\operatorna
View solution Problem 6
Sketch the sets of points determined by the following relations. (a) \(|z+1-2 i|=2\). (b) \(\operatorname{Re}(z+1)=0\) (c) \(|z+2 i| \leq 1\) (d) \(\operatornam
View solution Problem 7
Prove that the complex number \((1,0)\) (which we identify with the real number 1 ) is the multiplicative identity for complex numbers.
View solution Problem 7
Prove that \(\sqrt{2}|z| \geq|\operatorname{Re}(z)|+|\operatorname{Lm}(z)|\).
View solution