Problem 6
Question
Rolling coin \(^{*}\) A coin of radius \(b\) and mass \(M\) rolls on a horizontal surface at speed \(V .\) If the plane of the coin is vertical the coin rolls in a straight line. If the plane is tilted, the path of the coin is a circle of radius \(R\). Find an expression for the tilt angle of the coin \(\alpha\) in terms of the given quantities. (Because of the tilt of the coin the circle traced by its center of mass is slightly smaller than \(R\) but you can ignore the difference.)
Step-by-Step Solution
Verified Answer
The tilt angle \( \alpha \) is given by \( \alpha = \arcsin\left(\frac{V^2}{gR}\right) \).
1Step 1: Understand the Problem
We are asked to find the tilt angle \( \alpha \) of a rolling coin on a horizontal surface. The coin rolls in a circle when the plane is tilted, and we need to express \( \alpha \) in terms of the given quantities: radius \( b \), mass \( M \), speed \( V \), and circle radius \( R \).
2Step 2: Identify Forces and Dynamics
When the coin is tilted, its center of mass moves in a circular path of radius \( R \). The centripetal force required for this movement is provided by the component of gravitational force. Tilt of the coin also generates a normal force from the surface of the circle, contributing to the centripetal force.
3Step 3: Analyze the Physics of Motion
The tilt angle \( \alpha \) causes the gravitational force \( Mg \) to have a component \( Mg\sin \alpha \) which acts centripetally. The normal force \( N \) also has a horizontal component \( N\sin \alpha \) that contributes to centripetal force. Thus, \( N\sin\alpha + Mg\sin\alpha = \frac{MV^2}{R} \).
4Step 4: Express the Tilt Angle
Using the expressions for forces contributing to the centripetal force, we know that \( N = Mg\cos\alpha \), and substituting this into the equilibrium equation we get: \[ Mg\sin\alpha = \frac{MV^2}{R} \]From this, \( \sin\alpha = \frac{V^2}{gR} \), giving us \( \alpha = \arcsin\left(\frac{V^2}{gR}\right) \).
5Step 5: Verify Conditions
To verify, ensure that \( V^2 \leq gR \) for the \( \sin\alpha \) to be valid in the range of \(-1\) to \(1\), which satisfies the requirement for the inverse-sine function. This confirms our equation for the valid physical solutions.
Key Concepts
Centripetal ForceTilt Angle CalculationCircular Motion Dynamics
Centripetal Force
Centripetal force is essential for any object moving in a circle. It acts towards the center of the circle and is responsible for changing the direction of the object's velocity, keeping it in circular motion. For a rolling coin experiencing circular motion, centripetal force is required to maintain its path.
- This force does not increase the speed of the object; rather, it constantly changes the direction of the velocity.
- Centripetal force can originate from different sources depending on the context, such as tension, gravity, or friction.
Tilt Angle Calculation
The tilt angle is a critical factor when determining the path of a rolling object. In our scenario, the tilt angle, denoted as \(\alpha\), defines how much the plane of the coin is inclined from the vertical. This inclination causes a portion of the gravitational force to act as a centripetal force.
- The coin's tilt results in a gravity component equation: \(Mg\sin \alpha\).
- Similarly, the normal force also tilts, giving a horizontal component: \(N\sin \alpha\).
- These components must equal the centripetal force needed to maintain the circular trajectory: \(\frac{MV^2}{R}\).
Circular Motion Dynamics
Circular motion dynamics involve the study of forces that maintain an object in a circular path. In this exercise, the coin's circular motion is influenced heavily by dynamics that are simplified using key principles of classical mechanics.
- As the coin rolls, the centripetal force ensures the object stays in a circular trajectory, as opposing forces try to act against it.
- This dynamics involves components of gravitational force and the tilt angle, which result in a net inward force necessary for circular motion.
- One must consider the limitations imposed by friction, as it affects how easily the object maintains its circular course.
Other exercises in this chapter
Problem 4
Grain mill \(^{*}\) In an old-fashioned rolling mill, grain is ground by a disk- shaped millstone that rolls in a circle on a flat surface, driven by a vertical
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Automobile on a curve When an automobile rounds a curve at high speed, the loading (weight distribution) on the wheels is markedly changed. For sufficiently hig
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Suspended hoop A thin hoop of mass \(M\) and radius \(R\) is suspended from a string through a point on the rim of the hoop. If the support is turned with high
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Deflected hoop A child's hoop of mass \(M\) and radius \(b\) rolls in a straight line with velocity \(V\). The top of the hoop is given a light tap with a stick
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