Problem 6
Question
Provide a short answer to each question. Do not use a calculator. What is the equation of the vertical asymptote of the graph of \(y=\frac{1}{(x+2)^{2}}-4 ? \quad\) of the horizontal asymptote?
Step-by-Step Solution
Verified Answer
Vertical asymptote: \( x = -2 \); Horizontal asymptote: \( y = -4 \).
1Step 1: Identify the vertical asymptote
A vertical asymptote exists where the function is undefined. For the given function \( y = \frac{1}{(x+2)^2} - 4 \), the denominator \( (x+2)^2 \) cannot be zero. Set \( (x+2)^2 = 0 \) to find the undefined point. Solving this, we get \( x + 2 = 0 \), therefore \( x = -2 \). Thus, the equation of the vertical asymptote is \( x = -2 \).
2Step 2: Determine the horizontal asymptote
The horizontal asymptote of a rational function is determined by the behavior of the function as \( x \to \infty \) or \( x \to -fty \). Observe that as \( x \) becomes very large, the term \( \frac{1}{(x+2)^2} \) approaches zero, because the denominator grows much faster than the numerator. Therefore, the function approaches \( y = 0 - 4 \), which simplifies to \( y = -4 \). Thus, the horizontal asymptote is \( y = -4 \).
Key Concepts
AsymptotesRational FunctionsGraph Analysis
Asymptotes
Asymptotes are lines that a graph approaches but never actually touches. They provide essential insights into the behavior of a function as we delve into very large or small values of its variables.
There are two main types of asymptotes we generally discuss in algebra: **vertical asymptotes** and **horizontal asymptotes**.
There are two main types of asymptotes we generally discuss in algebra: **vertical asymptotes** and **horizontal asymptotes**.
- **Vertical Asymptotes** occur where the function is undefined. They are associated with the values of the variable that make the denominator zero. This can cause the function to grow indefinitely large (positive or negative). In our function, \(y = \frac{1}{(x+2)^2} - 4\), we set \((x+2)^2 = 0\). Solving gives \(x = -2\). Thus, the vertical asymptote is \(x = -2\).
- **Horizontal Asymptotes** illustrate the behavior of a function as the independent variable approaches infinity or negative infinity. In our function, as \(x\) becomes very large, \(\frac{1}{(x+2)^2}\) diminishes towards zero, letting \(y\) approach \(-4\). This gives a horizontal asymptote at \(y = -4\).
Rational Functions
Rational functions are expressed as the quotient of two polynomials. They have distinct properties that make them interesting to study, particularly in graphing.
For our provided example, \(y = \frac{1}{(x+2)^2} - 4\), it is highlighted that the function takes the form of a rational expression due to its polynomial structures in the numerator and denominator.
For our provided example, \(y = \frac{1}{(x+2)^2} - 4\), it is highlighted that the function takes the form of a rational expression due to its polynomial structures in the numerator and denominator.
- The numerator is \(1\), which is a constant polynomial. In rational functions, a constant like this means the function's behavior is highly influenced by the denominator.
- The denominator is \((x+2)^2\), influencing both the location of vertical asymptotes and the function's overall behavior.
Graph Analysis
Graph analysis involves understanding how the graph of a function behaves across the entire set of possible values for its variables.
When analyzing the graph of our function, \(y = \frac{1}{(x+2)^2} - 4\), several key features emerge:
When analyzing the graph of our function, \(y = \frac{1}{(x+2)^2} - 4\), several key features emerge:
- **Shape and Behavior**: The \(\frac{1}{(x+2)^2}\) term ensures the function is never negative because squares are non-negative. Subtracting 4 shifts the entire graph downward by 4 units.
- **Asymptotes and Limits**: The previously discussed asymptotes appear on the graph as guidelines, constraining the trajectory of the curve without it ever crossing these lines.
- **Intercepts**: By setting \(y\) to zero, students can find the exact points where the graph crosses the \(x\)-axis, though in this question finding the zeros wasn’t the primary focus.
Other exercises in this chapter
Problem 6
Use a hand-drawn graph to explain why \(\sqrt{x}=-x-5\) has no real solutions.
View solution Problem 6
Match the rational function in Column I with the appropriate description in Column II. Choices in Column II can be used only once. Do not use a calculator. (Col
View solution Problem 7
Evaluate each expression. Do not use a calculator. $$125^{-2 / 3}$$
View solution Problem 7
Match the rational function in Column I with the appropriate description in Column II. Choices in Column II can be used only once. Do not use a calculator. (Col
View solution