Problem 6
Question
In qualitative analysis \(\mathrm{NH}_{4} \mathrm{Cl}\) is added before \(\mathrm{NH}_{4} \mathrm{OH}\) (a) to increase \(\left[\mathrm{OH}^{-}\right]\)conc (b) for making \(\mathrm{HCl}\) (c) to decrease \(\left[\mathrm{OH}^{-}\right]\)conc (d) statement is wrong
Step-by-Step Solution
Verified Answer
(c) to decrease \( \left[\mathrm{OH}^{-} \right] \) conc.
1Step 1: Interpretation of the Question
The question asks us why \( \mathrm{NH}_{4} \mathrm{Cl} \) is added before \( \mathrm{NH}_{4} \mathrm{OH} \) in qualitative analysis. We are given four statements and must determine which is true.
2Step 2: Understanding the Role of \( \mathrm{NH}_{4} \mathrm{Cl} \)
\( \mathrm{NH}_{4} \mathrm{Cl} \) dissociates into \( \mathrm{NH}_{4}^{+} \) and \( \mathrm{Cl}^{-} \) ions in solution. The presence of \( \mathrm{NH}_{4}^{+} \) ions can influence the concentration of \( \mathrm{OH}^{-} \) ions.
3Step 3: Analyzing the Reaction Environment
Adding \( \mathrm{NH}_{4} \mathrm{Cl} \) increases the \( \mathrm{NH}_{4}^{+} \) ion concentration. Since \( \mathrm{NH}_{4} \mathrm{OH} \) is a weak base, the addition of \( \mathrm{NH}_{4}^{+} \) from \( \mathrm{NH}_{4} \mathrm{Cl} \) will influence the equilibrium position of the \( \mathrm{NH}_{4} \mathrm{OH} \leftrightarrow \mathrm{NH}_{4}^{+} + \mathrm{OH}^{-} \) reaction, reducing the \( \mathrm{OH}^{-} \) concentration (common ion effect).
4Step 4: Conclusion
The addition of \( \mathrm{NH}_{4} \mathrm{Cl} \) is used to decrease the \( \left[ \mathrm{OH}^{-} \right] \) concentration in the solution due to the common ion effect of \( \mathrm{NH}_{4}^{+} \). Therefore, option (c) is the correct statement.
Key Concepts
Common Ion EffectAmmonium ChlorideHydroxide Ion Concentration
Common Ion Effect
The common ion effect is an important concept in chemistry that helps us understand how substances in a solution can influence each other. When a compound like ammonium chloride \( \mathrm{NH}_{4} \mathrm{Cl} \) is dissolved in water, it dissociates into its constituent ions, \( \mathrm{NH}_{4}^{+} \) and \( \mathrm{Cl}^{-} \). When these ions are present, they can affect the equilibrium of other related ions in the solution.
- The presence of \( \mathrm{NH}_{4}^{+} \) in solution is the key player in the common ion effect in this scenario.
- It works by shifting the equilibrium according to Le Chatelier's Principle.
- This principle states that if a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium shifts to counteract the change.
Ammonium Chloride
Ammonium chloride (\( \mathrm{NH}_{4} \mathrm{Cl} \)) is a common compound used in laboratories, particularly in qualitative analysis. It is a white crystalline salt that is highly soluble in water, meaning it breaks apart easily to form ammonium ions (\( \mathrm{NH}_{4}^{+} \)) and chloride ions (\( \mathrm{Cl}^{-} \)). This solubility is key to its role in the common ion effect.
- The introduction of ammonium chloride into a solution increases the \( \mathrm{NH}_{4}^{+} \) ions concentration.
- This, in turn, affects reactions involving \( \mathrm{OH}^{-} \) ions, especially when working with weak bases like \( \mathrm{NH}_{4} \mathrm{OH} \).
Hydroxide Ion Concentration
The hydroxide ion concentration (\( \left[ \mathrm{OH}^{-} \right] \)) in a solution is an important factor in determining its basicity. In many chemical reactions, it's crucial to control this concentration for desired outcomes.
- A common scenario is in the presence of a weak base like \( \mathrm{NH}_{4} \mathrm{OH} \), where the ability to maintain a low \( \mathrm{OH}^{-} \) concentration can be beneficial.
- Adding an abundant amount of \( \mathrm{NH}_{4}^{+} \) ions, through compounds like ammonium chloride, effectively lowers the \( \mathrm{OH}^{-} \) concentration.
- This decrease happens because the system adjusts to maintain equilibrium, favoring the formation of more \( \mathrm{NH}_{4}^{+} \) and less \( \mathrm{OH}^{-} \).
Other exercises in this chapter
Problem 4
A metal is burnt in air and the ash on moistening smells of ammonia. The metal is (a) \(\mathrm{Mg}\) (b) \(\mathrm{Al}\) (c) \(\mathrm{Fe}\) (d) \(\mathrm{Na}\
View solution Problem 5
Which of the following pair is not distinguished by passing \(\mathrm{H}_{2} \mathrm{~S} ?\) (a) As, Cd (b) \(\mathrm{Zn}, \mathrm{Mn}\) (c) \(\mathrm{Hg}, \mat
View solution Problem 7
\(\mathrm{CrO}_{3}\) dissolves in aqueous \(\mathrm{NaOH}\) to give (a) \(\mathrm{Cr}(\mathrm{OH})_{3}\) (b) \(\mathrm{Cr}(\mathrm{OH})_{2}\) (c) \(\mathrm{Cr}_
View solution Problem 8
Which of the following is not efflorescent? (a) \(\mathrm{NaOH}\) (b) hydrated \(\mathrm{CuSO}_{4}\) (c) hydrated \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) (d) all of
View solution