Problem 6
Question
In Problems 1-28, differentiate the functions with respect to the independent variable. $$ f(x)=\sqrt{2 x+7} $$
Step-by-Step Solution
Verified Answer
The derivative is \( f'(x) = \frac{1}{\sqrt{2x + 7}} \).
1Step 1: Rewrite the Function
The given function is \( f(x) = \sqrt{2x + 7} \). It is easier to differentiate if we rewrite it using a fractional exponent: \( f(x) = (2x + 7)^{1/2} \).
2Step 2: Apply the Chain Rule
To differentiate \( f(x) = (2x + 7)^{1/2} \), use the chain rule. The chain rule states that if you have a composite function \( f(g(x)) \), its derivative is \( f'(g(x)) \cdot g'(x) \).
3Step 3: Differentiate the Outer Function
The outer function for \( f(x) = (2x + 7)^{1/2} \) is \( u^{1/2} \) where \( u = 2x + 7 \). The derivative of \( u^{1/2} \) with respect to \( u \) is \( \frac{1}{2}u^{-1/2} \).
4Step 4: Differentiate the Inner Function
The inner function is \( u = 2x + 7 \). The derivative with respect to \( x \) is \( 2 \).
5Step 5: Apply the Chain Rule to Find the Derivative
Using the chain rule, multiply the derivative of the outer function by the derivative of the inner function: \( f'(x) = \frac{1}{2}(2x+7)^{-1/2} \times 2 = (2x+7)^{-1/2} \).
6Step 6: Rewrite the Derivative in Terms of a Radical
The derivative \( f'(x) = (2x+7)^{-1/2} \) can be rewritten using a radical: \( f'(x) = \frac{1}{\sqrt{2x + 7}} \).
Key Concepts
Chain RuleFractional ExponentsComposite Functions
Chain Rule
The Chain Rule is an essential tool in calculus for differentiating composite functions. It comes into play when you have a function inside another function. For instance, in the expression \((2x + 7)^{1/2}\), there is a clear inner function, \(2x + 7\), and an outer function, \(u^{1/2}\).
- The Chain Rule helps us manage these layers by stating: the derivative of a composite function \(f(g(x))\) can be found by multiplying the derivative of the outer function \(f'(u)\) with the derivative of the inner function \(g'(x)\).
- In practical terms, you first differentiate the outer function with respect to the inner function, then differentiate the inner function with respect to the original variable.
Fractional Exponents
Fractional exponents offer a convenient way to express roots and enhance the differentiation process. Let's take the example of \(\sqrt{2x + 7}\).
- Using fractional exponents, this expression becomes \((2x + 7)^{1/2}\). This conversion makes it easier to apply calculus operations such as differentiation.
- Fractional exponents follow the same rules as integer exponents: \(a^{m/n}\) denotes the \(n\)-th root of \(a\) raised to the \(m\)-th power.
- They also improve the process of finding derivatives using mechanisms like the Power Rule, which applies to any power of a variable.
Composite Functions
Composite functions are formed by inputting one function into another. This construction is symbolically written as \(f(g(x))\). For example, given \(f(x) = \sqrt{2x + 7}\), the composite nature is already evident.
- Understanding composite functions involves recognizing the role of both the inner \(g(x)\) and outer \(f(x)\) functions.
- These functions require careful application of differentiation techniques like the Chain Rule because changes in either part influence the whole.
- The outer function handles the overarching structure, while the inner function supplies the specific variable input details.
Other exercises in this chapter
Problem 6
Find the first and the second derivatives of each function. $$ f(x)=\frac{1}{x^{2}}+x-x^{3} $$
View solution Problem 6
In Problems \(1-8\), find \(\frac{d y}{d x}\) by implicit differentiation. $$ \frac{1}{2 x y}-y^{3}=4 $$
View solution Problem 7
Use the formula $$f(x) \approx f(a)+f^{\prime}(a)(x-a)$$ to approximate the value of the given function. Then compare your result with the value you get from a
View solution Problem 7
Find the derivative at the indicated point from the graph of \(y=f(x)\). \(f(x)=\cos x ; x=0\)
View solution