Problem 6
Question
In Exercises \(5-18\), solve each system by the substitution method. $$ \begin{aligned} &x+y=6\\\ &y=2 x \end{aligned} $$
Step-by-Step Solution
Verified Answer
The solution for the system of equations \(x+y=6\) and \(y=2x\) is \(x=2\) and \(y=4\).
1Step 1: Substitute y in First Equation
The second equation is \(y=2x\). Substitute this into the first equation, i.e., replace \(y\) in \(x+y=6\), we get: \(x + 2x = 6\)
2Step 2: Solve the Equation after Substitution
Now, solve the equation after substitution. Add the \(x\) terms together we get \(3x=6\). Solve for \(x\) and the value of \(x\) is \(x=2\).
3Step 3: Substitute x in Second Equation
Having obtained the value of \(x\), we substitute \(x=2\) into the second equation \(y=2x\) to determine the value of \(y\). It gives us that \(y=2*2\), so \(y=4\)
Key Concepts
Substitution MethodAlgebraic EquationsLinear Systems
Substitution Method
The substitution method is an algebraic technique commonly used to solve systems of equations. This method involves replacing one variable with an expression involving the other variable, making it possible to solve for one unknown at a time.
Here's how to apply the substitution method step by step:
Here's how to apply the substitution method step by step:
- First, isolate one of the variables in one of the equations.
- Next, substitute the expression for this variable into the other equation.
- Solve the resulting equation for the remaining variable.
- Finally, replace the found value into one of the original equations to solve for the other variable.
Algebraic Equations
Algebraic equations are mathematical statements that express the equality between two algebraic expressions. These equations have variables which are unknown quantities and can take various forms such as linear, quadratic, or polynomial.
The key to solving algebraic equations is to isolate the variable on one side of the equation. This can be achieved through operations such as addition, subtraction, multiplication, and division, applied to both sides of the equation. It's crucial to maintain the balance of the equation, meaning whatever you do to one side, you must do to the other side.
The key to solving algebraic equations is to isolate the variable on one side of the equation. This can be achieved through operations such as addition, subtraction, multiplication, and division, applied to both sides of the equation. It's crucial to maintain the balance of the equation, meaning whatever you do to one side, you must do to the other side.
Importance of Order of Operations
Remembering the order of operations is essential when manipulating equations. The acronym PEMDAS (Parentheses, Exponents, Multiplication and Division, Addition and Subtraction) can help you remember the correct sequence.Linear Systems
Linear systems consist of two or more linear equations involving the same set of variables. A solution to a linear system is an assignment of values to the variables that makes all the equations hold true simultaneously.
These systems can have:
These systems can have:
- A single solution (where lines intersect at a point).
- No solution (where lines are parallel and never intersect).
- Infinitely many solutions (where lines coincide).
Other exercises in this chapter
Problem 5
Solve each system. $$\begin{aligned}&x+y+2 z=11\\\&x+y+3 z=14\\\&x+2 y-z=5\end{aligned}$$
View solution Problem 5
Solve each system by the substitution method. $$\begin{aligned} &y=x^{2}-4 x-10\\\ &y=-x^{2}-2 x+14 \end{aligned}$$
View solution Problem 6
Write the form of the partial fraction decomposition of the rational expression. It is not necessary to solve for the constants. $$\frac{5 x^{2}-9 x+19}{(x-4)\l
View solution Problem 6
Graph each inequality. $$ y \leq \frac{1}{4} x $$
View solution