Problem 6
Question
In Exercises \(1-8\), evaluate the given limit. $$ \lim _{x \rightarrow 3} \frac{x^{2}-4 x+3}{x-3} $$
Step-by-Step Solution
Verified Answer
The limit is 2.
1Step 1: Substitution Check
First, substitute the value of 3 into the limit expression to check if it results in an indeterminate form or a numeric value. Substitute: \( \frac{3^2 - 4 \times 3 + 3}{3 - 3} \). This simplifies to \( \frac{9 - 12 + 3}{0} = \frac{0}{0} \), which is an indeterminate form. This confirms that we need to manipulate the expression further to find the limit.
2Step 2: Factor the Numerator
To resolve the indeterminate form, factor the quadratic expression in the numerator. The expression \( x^2 - 4x + 3 \) can be factored as \( (x - 1)(x - 3) \). This gives us the new expression: \( \frac{(x - 1)(x - 3)}{x - 3} \).
3Step 3: Simplify the Expression
Now simplify by canceling the \((x - 3)\) terms in the numerator and denominator, as long as \(x eq 3\). This leaves us with the simplified expression \( x - 1 \).
4Step 4: Evaluate the Limit
Substitute \(x = 3\) into the simplified expression \(x - 1\). This yields \(3 - 1 = 2\). Thus, the limit is 2.
Key Concepts
Limit EvaluationFactoring QuadraticsIndeterminate Forms
Limit Evaluation
When we discuss limit evaluation in calculus, we are asking what value a function approaches as the input approaches a certain number. It's like trying to predict where a running train is heading once it reaches a bend on the tracks. In essence, knowing limits helps us understand the behavior of functions near specific points.
For instance, consider the limit provided in the exercise, \( \lim_{x \rightarrow 3} \frac{x^{2}-4x+3}{x-3} \). Initially, you might try simple substitution by plugging the number 3 directly into the equation. This step helps check whether the function returns a specific value or an undefined form like \( \frac{0}{0} \). In this example, inserting \( x = 3 \) directly leads to an indeterminate form, so further steps are necessary.
Evaluating limits is crucial when dealing with functions that are not easy to approach directly, ensuring we fully understand the function's behavior around a given point. It's like a detective solving a mystery, finding clues to discover how a function behaves as it nears our number of interest.
For instance, consider the limit provided in the exercise, \( \lim_{x \rightarrow 3} \frac{x^{2}-4x+3}{x-3} \). Initially, you might try simple substitution by plugging the number 3 directly into the equation. This step helps check whether the function returns a specific value or an undefined form like \( \frac{0}{0} \). In this example, inserting \( x = 3 \) directly leads to an indeterminate form, so further steps are necessary.
Evaluating limits is crucial when dealing with functions that are not easy to approach directly, ensuring we fully understand the function's behavior around a given point. It's like a detective solving a mystery, finding clues to discover how a function behaves as it nears our number of interest.
Factoring Quadratics
Factoring quadratics is an algebraic process useful in solving equations, especially when evaluating limits. When you have a function with a quadratic in the numerator, like \( x^2 - 4x + 3 \), factoring can simplify the expression to remove troublesome terms.
In the exercise, the quadratic \( x^2 - 4x + 3 \) is factored to \((x - 1)(x - 3)\). Factoring seeks numbers (or expressions) whose product equates to the quadratic, much like how you can split 6 into 2 and 3 because 2 multiplied by 3 gives 6.
This strategic breakdown allows you to simplify the fraction by canceling common terms in the numerator and denominator. After cancellation, we are left with a simpler expression that is easier to handle. This is especially helpful if initial substitution into the limit results in an indeterminate form like we saw before. The goal is always to clean up the expression so that it can be evaluated directly.
In the exercise, the quadratic \( x^2 - 4x + 3 \) is factored to \((x - 1)(x - 3)\). Factoring seeks numbers (or expressions) whose product equates to the quadratic, much like how you can split 6 into 2 and 3 because 2 multiplied by 3 gives 6.
This strategic breakdown allows you to simplify the fraction by canceling common terms in the numerator and denominator. After cancellation, we are left with a simpler expression that is easier to handle. This is especially helpful if initial substitution into the limit results in an indeterminate form like we saw before. The goal is always to clean up the expression so that it can be evaluated directly.
Indeterminate Forms
In calculus, encountering an indeterminate form signifies that an expression is initially undefined with standard arithmetic rules. The \( \frac{0}{0} \) form is a classic and common case that requires additional steps to resolve. It's similar to trying to answer 'zero divided by zero apples'—it doesn't make logical sense without more manipulation.
When the limit \( \lim_{x \rightarrow 3} \frac{x^{2}-4x+3}{x-3} \) produces the indeterminate form \( \frac{0}{0} \), further algebraic manipulation, like factoring, is necessary. This manipulation uncovers the true path of the limit.
Indeterminate forms signal hidden information within the mathematical expression demanding a deeper dive. By simplifying these forms, we can hone in on the actual behavior of the function, often revealing finite and meaningful outputs that weren't initially apparent. It’s like clearing the fog to see the path clearly.
When the limit \( \lim_{x \rightarrow 3} \frac{x^{2}-4x+3}{x-3} \) produces the indeterminate form \( \frac{0}{0} \), further algebraic manipulation, like factoring, is necessary. This manipulation uncovers the true path of the limit.
Indeterminate forms signal hidden information within the mathematical expression demanding a deeper dive. By simplifying these forms, we can hone in on the actual behavior of the function, often revealing finite and meaningful outputs that weren't initially apparent. It’s like clearing the fog to see the path clearly.
Other exercises in this chapter
Problem 6
Decide whether the indicated limit exists. If the limit does exist, compute it. $$ \lim _{x \rightarrow-3} \frac{x-3}{x^{2}-9} $$
View solution Problem 6
Determine the values at which the given function \(f\) is continuous. Remember that if \(c\) is not in the domain of \(f,\) then \(f\) cannot be continuous at \
View solution Problem 6
In Exercises \(1-20\), determine whether the given limit exists. If it does exist, then compute it. $$ \lim _{x \rightarrow \pi} \frac{3}{\sin (x)} $$
View solution Problem 6
Simplify the given expression. $$ \left(\sqrt{e}^{\sqrt{2}}\right)^{2} $$
View solution