Problem 6
Question
If \(x\) gram of gas is adsorbed by \(m\) gram of adsorbent at pressure \(P\), the plot of \(\log \frac{x}{m}\) versus \(\log P\) is linear. The slope of the plot is: (n and \(k\) are constants and \(\mathrm{n}>1\) )(a) \(\log \mathrm{k}\) (b) \(\frac{1}{n}\) (c) \(2 \mathrm{k}\) (d) \(\mathrm{n}\)
Step-by-Step Solution
Verified Answer
The slope is \(\frac{1}{n}\).
1Step 1: Understanding the problem
We are given that the plot of \( \log \frac{x}{m} \) versus \( \log P \) is linear. This implies a relationship between \( \frac{x}{m} \) and \( P \) that follows a power law. To find the slope, we'll first determine the equation representing the line.
2Step 2: Applying the Freundlich Isotherm
The problem describes a process known as adsorption, often modeled by the Freundlich isotherm: \( \frac{x}{m} = kP^{1/n} \). Here, \( k \) and \( n \) are constants, and \( n > 1 \) is given.
3Step 3: Taking the logarithm of the Freundlich equation
We take the logarithm of both sides of the Freundlich equation to transform it into a linear form: \[ \log \frac{x}{m} = \log (kP^{1/n}) \] This can be expanded to: \[ \log \frac{x}{m} = \log k + \frac{1}{n} \log P \]
4Step 4: Identifying the slope in the equation
The equation \( \log \frac{x}{m} = \log k + \frac{1}{n} \log P \) is in the form of \( y = c + mx \), which is a linear equation where \( m \) is the slope. By comparing, we identify that \( m = \frac{1}{n} \).
Key Concepts
AdsorptionLinear PlotPower Law Relationship
Adsorption
Adsorption is a fascinating natural process where a solid (often called the adsorbent) captures molecules of a gas or a liquid on its surface. Imagine tiny particles sticking to a surface, held there by attractive force. This is different from absorption, where substances are taken up into the interior of a material.
In the world of chemistry and physics, adsorption is crucial because it's essentially how substances cling onto surfaces, which can be helpful in various applications, like filtering pollutants. There are different types of adsorption, including physical and chemical. In this context, the focus is mostly on the equilibrium state, where the rate of adsorption equals the rate of desorption, providing a stable system for analysis.
The amount of gas adsorbed depends on several factors:
- The nature and surface properties of the adsorbent.
- The pressure of the gas above the surface.
- The temperature at which the process occurs.
Linear Plot
A linear plot is a graphical representation where you get a straight line, illustrating a direct proportional relationship between two variables. In mathematics, this means that as one variable increases, the other does, at a steady rate, so you can trace a straight path between them. In the context of adsorption, we use a linear plot to interpret the Freundlich Isotherm. By plotting \( \log \frac{x}{m} \) against \( \log P \), researchers can determine critical parameters about how adsorption behaves under different pressures. This method offers several benefits:
- It efficiently displays the relationship between variables with clarity.
- Identifies the behavior of adsorption as pressure changes.
- Helps in determining constants that describe the adsorption characteristics.
Power Law Relationship
The power law relationship is an important concept in understanding how various quantities relate to each other in a real-world context. It's a mathematical relationship where one quantity varies as a power of another. In its general form, it can be expressed as: \[ y = ax^b \]Where:
- \( y \) and \( x \) are the quantities of interest.
- \( a \) is a constant that scales the equation.
- \( b \) is the exponent that shows how one variable reacts to changes in another.
Other exercises in this chapter
Problem 4
Tyndall effect is observed when :(a) The diameter of dispersed particles is much larger than the wavelength of light used. (b) The diameter of dispersed particl
View solution Problem 5
Given gas critical temperature/ \(\mathrm{K}\) for\(\mathrm{H}_{2} \mathrm{CH}_{4} \mathrm{CO}_{2} \quad \mathrm{SO}_{2}\) is \(\begin{array}{llll}33 & 190 & 30
View solution Problem 6
Which of the following is used for the preparation of colloids?(a) Ostwald Process (b) Van Arkel Method (c) Bredig's Arc Method (d) Mond Process
View solution Problem 7
Adsorption of a gas on a surface follows Freundlich adsorption isotherm. Plot of \(\log \frac{x}{m}\) versus \(\log p\) gives a straight line with slope equal t
View solution