Problem 6
Question
If \((X, d)\) is a metric space where d is the discrete metric. Suppose \(\left\\{x_{n}\right\\}\) is a convergent sequence in \(X .\) Show that there exists \(a K \in \mathbb{N}\) such that for all \(n \geq K\) we have \(x_{n}=x_{K}\).
Step-by-Step Solution
Verified Answer
The sequence becomes constant after a certain point, equal to its limit.
1Step 1: Understand the Discrete Metric
In a metric space \(X, d\), where \(d\) is the discrete metric, the distance \(d(x, y) = 0\) if \(x = y\) and \(d(x, y) = 1\) if \(x eq y\). This means every distinct point in \(X\) is separated by a distance of 1.
2Step 2: Define Sequence Convergence
A sequence \left\{x_{n}\right\}\ converges to a limit \(x\) in a metric space \(X\) if for every \( \epsilon > 0\)\, there exists a natural number \(N\) such that for all \(n \geq N\), \(d(x_n, x) < \epsilon\).
3Step 3: Apply Convergence to Discrete Metric
In terms of the discrete metric, suppose a sequence \left\{x_{n}\right\}\ is converging to a limit \(x\). For \(\epsilon = 0.5\), by the definition of convergence, there should exist a natural number \(K\) such that for all \(n \geq K\), \(d(x_n, x) < 0.5\), which implies \(x_n = x\) because the only way the discrete distance is less than 1 is if \(x_n = x\).
4Step 4: Conclusion
Hence, after a certain point, all terms in the sequence are equal to the limit \(x\). This implies there exists a natural number \(K\) such that for all \(n \geq K\), \(x_n = x_K = x\).
Key Concepts
Discrete MetricSequence ConvergenceReal AnalysisConvergent Sequence
Discrete Metric
The discrete metric is a way to measure distance between points in a metric space. In this metric, any two distinct points are always a distance 1 apart. Specifically, for a metric space \((X, d)\) using the discrete metric, we say the distance \(d(x, y) = 0\) if the points \(x\) and \(y\) are the same, and \(d(x, y) = 1\) if they are different. This characteristic makes it unique because:
- It essentially acts like a digital or binary distinction between points - either points are the same and thus have a distance of 0, or they are different and therefore 1 unit apart.
- The discrete metric ensures that every point is isolated from every other distinct point in the metric space.
Sequence Convergence
Understanding sequence convergence is vital in metric spaces. A sequence \(\{x_n\}\) in a metric space converges to a limit \(x\) if, for every chosen positive distance \(\epsilon\), there exists a point from which onward all terms of the sequence are within that distance \(\epsilon\) of \(x\). This means:
- For any degree of closeness set by \(\epsilon\), you can find a point in the sequence beyond which every subsequent term is close to \(x\) within that \(\epsilon\).
- The point in the sequence where this property holds is often denoted by the natural number \(N\).
Real Analysis
Real analysis is a branch of mathematics dealing with real numbers and sequences and functions of real numbers. It lays the foundation for understanding limits, continuity, derivatives, and integrals. Primarily concerned with:
- The behavior and theory of real-valued sequences and series.
- The convergence of functions and the development of these concepts rigorously.
Convergent Sequence
A convergent sequence in any metric space, including those defined with a discrete metric, is one where the sequence's terms get arbitrarily close to a specific point called the limit as the sequence progresses.
In the context of a discrete metric:
- Once a sequence is said to "converge" within a discrete metric, it requires the sequence terms, after a certain point, to be constant, essentially becoming equal to the limit of the sequence.
- This is because, under the discrete metric, the only way for the distance between a sequence term and the limit to be zero (or less than any given number less than 1) is if they are identical.
Other exercises in this chapter
Problem 6
a) Find an example of a contraction \(f: X \rightarrow X\) of a non-complete metric space \(X\) with no fixed point. b) Find a 1-Lipschitz map \(f: X \rightarro
View solution Problem 6
Show that a compact set \(K\) is a complete metric space (using the subspace metric).
View solution Problem 6
Let \(\left(X, d_{X}\right)\) and \(\left(Y, d_{Y}\right)\) be metric spaces. a) Show that \((X \times Y, d)\) with \(d\left(\left(x_{1}, y_{1}\right),\left(x_{
View solution Problem 7
In any metric space, prove: a) \(E\) is closed if and only if \(\partial E \subset E\). b) \(U\) is open if and only if \(\partial U \cap U=\emptyset\).
View solution