Problem 6
Question
If \(G\) is abelian, prove that \(G / H\) must also be abelian.
Step-by-Step Solution
Verified Answer
Question: Prove that if a group \(G\) is abelian, then the quotient group \(G / H\) is also abelian.
Answer: To prove this, we first define the operation on cosets in the quotient group \(G / H\) as \((aH)(bH) = abH\). Then, because \(G\) is abelian, we have \(ab = ba\), so we can show that \((aH)(bH) = abH = baH = (bH)(aH)\), which means the quotient group \(G / H\) is also abelian.
1Step 1: Define the operation on cosets
Let G be an abelian group and H be a normal subgroup of G. The operation on the quotient group G / H is defined by the cosets multiplication:
\((aH)(bH) = abH\) for all \(a,b \in G\).
2Step 2: Check the commutative property
Now we need to check if the operation defined above satisfies the commutative property, that is, we need to prove that for any two cosets \((aH)(bH) = (bH)(aH)\).
Consider any two cosets \(aH\) and \(bH\) in \(G / H\). Then we have:
\((aH)(bH)= abH\) (by the definition of coset multiplication in Step 1)
Since \(G\) is abelian, we have \(ab = ba\). Thus, we can rewrite the above equation as:
\(abH = baH\)
Now, we have:
\((bH)(aH) = baH\)
Comparing the two equations, we get \((aH)(bH) = (bH)(aH)\).
Thus, the quotient group \(G / H\) is also abelian.
Key Concepts
Abelian GroupCosetsNormal SubgroupCommutative Property
Abelian Group
An Abelian group is a special type of group in abstract algebra where the group operation is commutative. This means that for any two elements, say \(a\) and \(b\), in an Abelian group \(G\), the equation \(a + b = b + a\) always holds true.
The notation \(a + b\) is obviously a placeholder for the actual operation in the group, which might be something other than addition (like multiplication or some other operation).
The notation \(a + b\) is obviously a placeholder for the actual operation in the group, which might be something other than addition (like multiplication or some other operation).
- The core property of an Abelian group is its commutativity.
- This makes computations within the group predictable and often simplifies many problems in algebra.
Cosets
Cosets are an important concept when dealing with groups and their subgroups. If you have a subgroup \(H\) of a group \(G\), and you pick an element \(a\) from \(G\), you can form a set called a coset.
The left coset, for instance, is denoted as \(aH = \{ah : h \in H\}\) which means every element of \(H\) gets multiplied by \(a\).
The left coset, for instance, is denoted as \(aH = \{ah : h \in H\}\) which means every element of \(H\) gets multiplied by \(a\).
- Cosets divide the group \(G\) into non-overlapping parts.
- They are crucial in forming quotient groups, since a quotient group \(G/H\) is essentially the set of all cosets of \(H\) in \(G\).
Normal Subgroup
A normal subgroup \(H\) of a group \(G\) is a subgroup where every left coset of \(H\) is the same as its right coset, meaning \(aH = Ha\) for every \(a\) in \(G\). This symmetry ensures our operations within the quotient group work the way we expect.
- Every coset looks the same from both sides.
- Normal subgroups allow the formation of quotient groups, which help to bridge the gap between simpler structures and more complex ones.
Commutative Property
The commutative property is a foundational concept in mathematics and specifically in the study of group theory. It states that the order in which two elements are combined does not affect the result. For a group, this means if you take any two elements \(a\) and \(b\) in the group, the equation \(a b = b a\) holds true.
- This is true for any two elements within an Abelian group, as Abelian groups are inherently commutative.
- In the context of quotient groups like \(G/H\), demonstrating the commutative property helps establish whether the quotient group itself is Abelian.
Other exercises in this chapter
Problem 4
Let \(T\) be the group of nonsingular upper triangular \(2 \times 2\) matrices with entries in \(\mathbb{R} ;\) that is, matrices of the form $$\left(\begin{arr
View solution Problem 5
Show that the intersection of two normal subgroups is a normal subgroup.
View solution Problem 7
Prove or disprove: If \(H\) is a normal subgroup of \(G\) such that \(H\) and \(G / H\) are abelian, then \(G\) is abelian.
View solution Problem 8
If \(G\) is cyclic, prove that \(G / H\) must also be cyclic.
View solution