Problem 6
Question
Graph each pair of parametric equations by hand, using values of t in \([-2,2] .\) Make a table of \(t=x\) - and \(y\) -values, using \(t=-2,-1,0,1,\) and \(2 .\) Then plot the points and join them with a line or smooth curve for all values of \(t\) in \([-2,2] .\) Do not use a calculator. $$x=-t^{2}+2, \quad y=t+1$$
Step-by-Step Solution
Verified Answer
Plot the points from the table and connect them to form a curve.
1Step 1: Setup the Table
Create a table with columns for \(t\), \(x\), and \(y\). We will evaluate the parametric equations at \(t = -2, -1, 0, 1, 2\).
2Step 2: Evaluate for t = -2
Substitute \(t = -2\) into the equations. Calculate \(x = -(-2)^2 + 2 = -4 + 2 = -2\) and \(y = -2 + 1 = -1\). Add these values to the table.
3Step 3: Evaluate for t = -1
Substitute \(t = -1\) into the equations. Calculate \(x = -(-1)^2 + 2 = -1 + 2 = 1\) and \(y = -1 + 1 = 0\). Record these values in the table.
4Step 4: Evaluate for t = 0
Substitute \(t = 0\) into the equations. Calculate \(x = -(0)^2 + 2 = 2\) and \(y = 0 + 1 = 1\). Enter these values into the table.
5Step 5: Evaluate for t = 1
Substitute \(t = 1\) into the equations. Calculate \(x = -(1)^2 + 2 = -1 + 2 = 1\) and \(y = 1 + 1 = 2\). Record these values in the table.
6Step 6: Evaluate for t = 2
Substitute \(t = 2\) into the equations. Calculate \(x = -(2)^2 + 2 = -4 + 2 = -2\) and \(y = 2 + 1 = 3\). Add these values to the table.
7Step 7: Plot the Points
Plot each point from the table on a graph. \((-2, -1)\), \((1, 0)\), \((2, 1)\), \((1, 2)\), and \((-2, 3)\).
8Step 8: Join the Points
Draw lines or a smooth curve connecting the points in the order of the \(t\) values. This will help visualize the parametric curve for \(t\) in \([-2,2]\).
Key Concepts
Graphing Parametric Equations by HandUnderstanding Parametric CurvesUtilizing a Table of Values
Graphing Parametric Equations by Hand
Graphing parametric equations by hand may seem complex at first but can be straightforward with a little practice. The key lies in working step-by-step, using values of the parameter \( t \), and plotting them on a graph.
- Begin by understanding the equations: you have two equations, one for \( x \) and one for \( y \), both dependent on \( t \).
- Select a range for \( t \) to plot: In our case, \( t \) varies from -2 to 2.
- Make sure to use a uniform scale while plotting points for consistency.
Understanding Parametric Curves
Parametric curves are an interesting way to describe mathematical curves by using parameters instead of the usual \( y = f(x) \) form. The concept revolves around using a third variable, often \( t \), to define both \( x \) and \( y \) coordinates.
- Think of the parameter \( t \) as a sort of time variable, controlling the position of the point on the curve as it changes.
- Each value of \( t \) directly corresponds to a specific point \((x, y)\) on the graph.
Utilizing a Table of Values
Creating a table of values is crucial when working with parametric equations, particularly when graphing by hand. The table provides a structured way to calculate and organize the coordinates you need for plotting.
- Each row in the table represents a specific value of \( t \) along with the corresponding \( x \) and \( y \) values.
- This organization helps in visualizing the transition from one point to another as \( t \) changes.
Other exercises in this chapter
Problem 5
The equation of a conic section is given in a familiar form. Identify the type of graph (if any) that each equation has, without actually graphing. See the summ
View solution Problem 5
Match each equation in Column I with the appropriate description in Column II. Do not use a calculator. A. Hyperbola; center \((2,4)\) B. Ellipse; foci \((\pm 2
View solution Problem 6
The equation of a conic section is given in a familiar form. Identify the type of graph (if any) that each equation has, without actually graphing. See the summ
View solution Problem 6
Match each equation in Column I with the appropriate description in Column II. Do not use a calculator. A. Hyperbola; center \((2,4)\) B. Ellipse; foci \((\pm 2
View solution