Problem 6
Question
Graph each inequality. $$y \geq x-2$$
Step-by-Step Solution
Verified Answer
Graph it with a solid line for \(y = x - 2\) and shade above.
1Step 1: Recognize the Standard Line Equation
The inequality given is \(y \geq x - 2\). This can be interpreted as the line equation \(y = x - 2\), with a boundary to consider since it is an inequality.
2Step 2: Identify the Boundary Line
The line \(y = x - 2\) is the boundary of the inequality. This line has a slope of 1 and a y-intercept of -2. Start by plotting the y-intercept; at point \((0, -2)\) on the Cartesian plane.
3Step 3: Plot the Line
Using the slope of 1, from the intercept \((0, -2)\), move up 1 unit and right 1 unit to another point \((1, -1)\). Continue this pattern to draw the straight line accurately. Since the inequality symbol is \(\geq\), the line will be solid, indicating that points on the line satisfy the inequality.
4Step 4: Determine the Shaded Region
For \(y \geq x - 2\), shade the area above the line (including the line itself) because \(y\) values greater than \(x-2\) satisfy the inequality. Test a point not on the line, for example, \((0,0)\). Substitute it back: \(0 \geq 0 - 2\), or \(0 \geq -2\) which is true, confirming the shade is correct.
Key Concepts
Cartesian PlaneLinear EquationsSlope-Intercept Form
Cartesian Plane
The Cartesian plane, also known as the coordinate plane, is a two-dimensional surface where we can graph mathematical equations and inequalities. It consists of two perpendicular number lines, one horizontal (x-axis) and one vertical (y-axis), which intersect at a point called the origin, denoted as
(0,0). This plane allows mathematicians and students alike to visually interpret algebraic expressions and relationships.
Points on this plane are described using a pair of numbers called coordinates, written as (x, y). The first number represents the position on the horizontal axis, while the second number represents the position on the vertical axis.
Points on this plane are described using a pair of numbers called coordinates, written as (x, y). The first number represents the position on the horizontal axis, while the second number represents the position on the vertical axis.
- Quadrants: The plane is divided into four sections, referred to as quadrants, each with a distinct combination of positive and negative values for x and y.
- Plotting Points: To plot a point, locate the x-coordinate on the x-axis, then find the y-coordinate on the y-axis, and mark where these intersect.
Linear Equations
Linear equations form straight lines when graphed on the Cartesian plane. They are fundamental in understanding graphing, as they represent a constant relationship between x and y. The general format of a linear equation is \(y = mx + b\), where m is the slope and b is the y-intercept.
To graph a linear equation, you need to identify:
To graph a linear equation, you need to identify:
- Slope: This tells us how steep the line is, or how much y changes for a change in x. In the equation \(y = x-2\), the slope m is 1, indicating a gentle slope rising diagonally across the plane.
- Y-intercept: This is the starting point on the y-axis. For our equation, it is -2, indicated by the point (0,-2).
Slope-Intercept Form
The slope-intercept form is a simple way of writing the equation of a line, making it easy to graph. It is given by the formula \(y = mx + b\), where m is the slope and b is the y-intercept.
This form is particularly useful because it provides direct insights into the graph's characteristics:
This form is particularly useful because it provides direct insights into the graph's characteristics:
- Slope (\(m\)): Indicates the direction and steepness of the line. A positive slope means the line goes upwards from left to right, while a negative slope means it goes downwards.
- Y-intercept (\(b\)): Tells us where the line crosses the y-axis. Using this point, you can start the line's graph before using the slope to extend it across the plane.
Other exercises in this chapter
Problem 5
Verify that the given ordered triple is a solution of the system. Do not use a calculator. $$\begin{aligned} (-2,-1,3) & \\ x-y+z &=2 \\ 3 x-2 y+z &=-1 \\ x+y &
View solution Problem 5
Solve each system by substitution $$\begin{aligned}6 x-y &=5 \\\y &=x\end{aligned}$$.
View solution Problem 6
Find each determinant. Do not use a calculator. $$\operatorname{det}\left[\begin{array}{ll}0 & 2 \\\1 & 5\end{array}\right]$$
View solution Problem 6
Determine whether A and B are imerses by calculating AB and BA. Do not use a calculator. $$A=\left[\begin{array}{lll} 1 & 2 & 0 \\ 0 & 1 & 0 \\ 0 & 1 & 0 \end{a
View solution