Problem 6
Question
Graph each equation. Identify the conic section and describe the graph and its lines of symmetry. Then find the domain and range. $$ x^{2}+y^{2}=49 $$
Step-by-Step Solution
Verified Answer
The given equation represents a circle with a center at the origin (0,0) and a radius of 7 units. It has lines of symmetry along both x-axis and y-axis. Domain and Range of this function are both \[-7,7\].
1Step 1: Graphing the Equation
Here, the equation given is \(x^{2} + y^{2} = 49\). This is the standard form of a circle centered at the origin (0,0). The radius of the circle can be found by taking the square root of 49 which gives 7. Thus it's a circle with radius 7 centered at the origin. Now, plot the circle using these values.
2Step 2: Identifying the Conic Section
The equation given is of the form \(x^{2} + y^{2} = r^{2}\), which represents a circle in the Cartesian coordinate system.
3Step 3: Describing the Graph and its Lines of Symmetry
The graph of \(x^{2} + y^{2} = 49\) is a circle centered at the origin (0,0) with a radius of 7 units. It has two lines of symmetry: one is the y-axis and the other is the x-axis.
4Step 4: Finding the Domain and Range
Since the graph is a circle centered at the origin with radius 7, the domain (set of all x values) and the range (set of all y values) are both \[-7,7\].
Key Concepts
Circle EquationGraphing CirclesLines of SymmetryDomain and Range
Circle Equation
A circle equation describes a geometric shape known as a circle on a coordinate plane. The standard form of a circle equation is \( x^2 + y^2 = r^2 \), where \( r \) represents the radius of the circle. This equation tells us that the circle is centered at the origin, which is the point \((0, 0)\). The radius \( r \) is the distance from the center to any point on the circle. To find the radius, you can take the square root of the number on the right side of the equation. In the equation \( x^2 + y^2 = 49 \), the number 49 is \( r^2 \), so the radius \( r \) is \( \sqrt{49} = 7 \). Understanding this basic circle equation helps us easily identify and graph circles.
Graphing Circles
Graphing circles involves plotting the circle on the coordinate plane based on its equation. To graph \( x^2 + y^2 = 49 \), follow these steps:
- Identify the center of the circle. For this equation, the center is the origin \((0, 0)\).
- Determine the radius, which in this case is 7, as calculated from \( r = \sqrt{49} \).
- From the center, mark points 7 units away in all directions: up, down, left, and right.
- Draw a smooth curve connecting these points to form a circle.
Lines of Symmetry
A circle is known for its perfect symmetry in the coordinate plane. It has an infinite number of lines of symmetry, but two primary axes stand out: the x-axis and the y-axis. These axes are special because they divide the circle into two identical halves:
- The x-axis is a horizontal line that mirrors the top half of the circle to the bottom half.
- The y-axis is a vertical line that reflects the left half to the right half.
Domain and Range
The domain and range of a circle's graph dictate where the circle exists on the coordinate plane. For the equation \( x^2 + y^2 = 49 \), both values are limited by the circle's size and position:
- The **domain**, representing all possible x-values, is the interval from -7 to 7. This range is the horizontal spread of the circle, as it stretches 7 units left and 7 units right from the origin.
- The **range**, which represents all possible y-values, similarly spans from -7 to 7. This is the vertical spread, going 7 units above and 7 units below the center.
Other exercises in this chapter
Problem 6
Graph each equation. $$ 25 x^{2}-16 y^{2}=400 $$
View solution Problem 6
Write an equation for a graph that is the set of all points in the plane that are equidistant from the given point and the given line. $$ F\left(\frac{1}{2}, 0\
View solution Problem 6
Write an equation of a circle with the given center and radius. Check your answers. $$ (-5,-1), 6 $$
View solution Problem 7
Write an equation of an ellipse in standard form with center at the origin and with the given vertex and co-vertex. $$ (-9,0),(0,-2) $$
View solution