Problem 6
Question
f(x)=2 x+\frac{1}{2 x}
Step-by-Step Solution
Verified Answer
The derivative of the function \( f(x) = 2x + \frac{1}{2x} \) is \( f'(x) = 2 - \frac{1}{2x^2} \).
1Step 1: Identify the Function
The function given is a combination of a linear term and a reciprocal term: \[ f(x) = 2x + \frac{1}{2x} \]
2Step 2: Find the Derivative
Use differentiation rules. The derivative of the linear term, \(2x\), is \(2\). The derivative of the reciprocal term, \( \frac{1}{2x} \), is \( \frac{-1}{2x^2} \): \[ f'(x) = 2 - \frac{1}{2x^2} \]
3Step 3: Simplify the Derivative
Combine the terms to get the simplified form of the derivative: \[ f'(x) = 2 - \frac{1}{2x^2} \]
Key Concepts
Derivative RulesFunction AnalysisReciprocal Function
Derivative Rules
Derivatives are a foundational concept in calculus. They help us understand how a function changes as its input changes. When dealing with derivatives, several rules are essential. The most used are the power rule, the sum rule, and the reciprocal rule.
The power rule states that the derivative of \(x^n\) is \(nx^{n-1}\). For example, the derivative of \(x^2\) is \(2x\). The sum rule indicates that the derivative of a sum of functions is the sum of their derivatives. If you have \(f(x) = g(x) + h(x)\), then \(f'(x) = g'(x) + h'(x)\). Lastly, the reciprocal rule is a bit more complicated; it states that the derivative of \((\frac{1}{x})\) is \(-\frac{1}{x^2}\).
Using these rules simplifies complex differentiation tasks. In our example, we deal with both a linear term and a reciprocal term. By using the sum rule, we split the function and apply the power and reciprocal rules individually.
The power rule states that the derivative of \(x^n\) is \(nx^{n-1}\). For example, the derivative of \(x^2\) is \(2x\). The sum rule indicates that the derivative of a sum of functions is the sum of their derivatives. If you have \(f(x) = g(x) + h(x)\), then \(f'(x) = g'(x) + h'(x)\). Lastly, the reciprocal rule is a bit more complicated; it states that the derivative of \((\frac{1}{x})\) is \(-\frac{1}{x^2}\).
Using these rules simplifies complex differentiation tasks. In our example, we deal with both a linear term and a reciprocal term. By using the sum rule, we split the function and apply the power and reciprocal rules individually.
Function Analysis
Function analysis involves understanding the behavior and properties of functions. This can include identifying key features like domain, range, intercepts, and asymptotes.
For our function, \(f(x) = 2x + \frac{1}{2x}\), we can break it down:
For our function, \(f(x) = 2x + \frac{1}{2x}\), we can break it down:
- The domain is all real numbers excluding \(x = 0\), as you cannot divide by zero.
- The linear term, \(2x\), grows indefinitely as \(x\) increases or decreases.
- The reciprocal term, \(\frac{1}{2x}\), approaches zero as \(x\) moves away from zero, but spikes towards infinity as \(x\) gets closer to zero.
Reciprocal Function
A reciprocal function is one where the variable is in the denominator, like \(\frac{1}{x}\). Reciprocal functions have unique characteristics:
Understanding reciprocal functions is essential in analyzing overall functions, especially when they appear with other terms in composite functions.
- They are undefined at \x = 0\.
- As \x\ gets very large (positive or negative), the reciprocal gets very small, approaching zero but never actually reaching it.
- As \x\ approaches zero, the function's value grows towards infinity.
Understanding reciprocal functions is essential in analyzing overall functions, especially when they appear with other terms in composite functions.
Other exercises in this chapter
Problem 4
The number of dollars in the total cost of producing \(x\) units of a certain commodity is \(C(x)=40+3 x+9 \sqrt{2 x}\). Find (a) the marginal cost when 50 unit
View solution Problem 5
\(f(x)=(x-4)^{2}\)
View solution Problem 6
\(G(x)=(x-5)^{2 / 3} ;(-\infty,+\infty)\)
View solution Problem 6
\(G(x)=\frac{2 x}{\left(x^{2}+4\right)^{3 / 2}}\)
View solution