Problem 6
Question
For exercises 1-66, simplify. $$ \frac{80 w^{3} z^{7}}{48 w^{9} z^{5}} $$
Step-by-Step Solution
Verified Answer
\[ \frac{5 z^{2}}{3 w^{6}} \]
1Step 1: Factor out common terms in the numerator and the denominator
The given fraction is \ \ \ \ \ \ \ \ \[ \frac{80 w^{3} z^{7}}{48 w^{9} z^{5}} \] . \ \ \ \ Write the numerator and the denominator as products of primes and powers to identify common factors. This helps to cancel out the common terms.
2Step 2: Cancel out common factors
Divide both the numerator and the denominator by their greatest common divisor (GCD). Factor the coefficients: 80 and 48. \ \ \ \[ \frac{80}{48} = \frac{10}{6} = \frac{5}{3} \ (\because \text{GCD of 80 and 48 is 16}) \]. \ \ Now, simplify the variables: The exponents of \(w\) and \(z\) . \[ \frac{w^{3}}{w^{9}} = \frac{1}{w^{6}} \ (\because w^{3 - 9} = w^{-6}) \], and \[ \frac{z^{7}}{z^{5}} = z^{2} \ (\because z^{7 - 5} = z^{2}) \].
3Step 3: Write the simplified form
Now combine the simplified coefficients and variables: \[ \frac{5}{3} \times \frac{1}{w^{6}} \times z^{2} = \frac{5 z^{2}}{3 w^{6}} \]. \ So, the simplified expression is \[ \frac{5 z^{2}}{3 w^{6}} \].
Key Concepts
Greatest Common DivisorExponent RulesPrime Factorization
Greatest Common Divisor
When simplifying algebraic fractions, finding the greatest common divisor (GCD) is a crucial step. The GCD is the largest number that divides both the numerator and the denominator without leaving a remainder. For example, in the fraction \(\frac{80}{48}\), the GCD of 80 and 48 is 16. This is because 16 is the highest number that can divide both 80 and 48. To find the GCD:
- List the prime factors of each number
- Identify the common factors
- Multiply these common factors
Exponent Rules
Exponent rules are applied when simplifying expressions with variables that have exponents. These rules help in reducing complex expressions to simpler forms. Consider the exponents in the given problem. For the terms with \( w \) and \( z \), we divide their exponents:
- For \( w \), the exponents are 3 and 9. Using the rule \( w^{a} / w^{b} = w^{a-b} \), we obtain \( w^{3-9} = w^{-6} \), which simplifies to \( \frac{1}{w^{6}} \).
- For \( z \), the exponents are 7 and 5. Using the same rule, we get \( z^{7-5} = z^{2} \).
Prime Factorization
Prime factorization involves breaking down a number into its prime factors. Prime numbers are numbers that have only two distinct positive divisors: 1 and itself. In the given exercise, breaking down the coefficients (80 and 48) into their prime factors can make it easier to simplify the fraction. For example:
- Prime factors of 80 are 2, 2, 2, 2, and 5.
- Prime factors of 48 are 2, 2, 2, 2, and 3.
Other exercises in this chapter
Problem 6
For exercises \(5-48\), simplify. $$ \frac{3}{x+5}+\frac{5}{x+5} $$
View solution Problem 6
For exercises \(3-6\), evaluate or simplify. $$ \frac{3 x}{10} \cdot \frac{5}{24} $$
View solution Problem 7
The relationship of \(x\) and \(y\) is a direct variation. When \(x=1, y=6\). a. Find the constant of proportionality, \(k\). b. Write an equation that represen
View solution Problem 7
For exercises 1-10, (a) solve. (b) check. $$ \frac{2}{3} x+\frac{3}{2}=\frac{1}{3} x+\frac{1}{6} $$
View solution