Problem 6
Question
For each of the following exercises, find the \(x\)-intercept and the \(y\)-intercept without graphing. Write the coordinates of each intercept. $$4 y=2 x-1$$
Step-by-Step Solution
Verified Answer
x-intercept: \(\left(\frac{1}{2}, 0\right)\), y-intercept: \(\left(0, -\frac{1}{4}\right)\).
1Step 1: Understanding Intercepts
The task asks for the \(x\)-intercept and the \(y\)-intercept. The \(x\)-intercept of a line is the point where the line crosses the x-axis. This occurs when \(y=0\). The \(y\)-intercept is the point where the line crosses the y-axis, which occurs when \(x=0\). We need to evaluate the given equation \(4y = 2x - 1\) under these conditions.
2Step 2: Finding the x-intercept
To find the x-intercept, we set \(y = 0\) in the equation \(4y = 2x - 1\). This gives us:\[4(0) = 2x - 1\]\[0 = 2x - 1\]Adding 1 to both sides, we get \(1 = 2x\). Solving for \(x\), we divide both sides by 2, yielding: \(x = \frac{1}{2}\). So, the x-intercept is \(\left(\frac{1}{2}, 0\right)\).
3Step 3: Finding the y-intercept
To find the y-intercept, we set \(x = 0\) in the equation \(4y = 2x - 1\). This gives us:\[4y = 2(0) - 1\]\[4y = -1\]Solving for \(y\), we divide both sides by 4, yielding: \(y = -\frac{1}{4}\). So, the y-intercept is \(\left(0, -\frac{1}{4}\right)\).
4Step 4: Verify Results
To verify our results, we substitute the intercept values back into the original equation:For the x-intercept: Substituting \((\frac{1}{2}, 0)\) into \(4y = 2x - 1\) results in \(0 = 2(\frac{1}{2}) - 1\), which simplifies to 0 = 0, confirming correctness.For the y-intercept: Substituting \((0, -\frac{1}{4})\) results in \(4(-\frac{1}{4}) = 2(0) - 1\), which simplifies to -1 = -1, confirming correctness.
Key Concepts
Finding x-interceptsFinding y-interceptsLinear equations
Finding x-intercepts
Finding the x-intercept of a linear equation involves discovering the point at which the line crosses the x-axis. To find this point, you need to set the value of y to zero and solve for x. This is because along the x-axis, the coordinate y is always zero.
In the exercise given, we start with the equation:
\[4y = 2x - 1\]
To find the x-intercept:
In the exercise given, we start with the equation:
\[4y = 2x - 1\]
To find the x-intercept:
- Set \( y = 0 \).
- Substitute it into the equation, resulting in \( 0 = 2x - 1 \).
- Solve for \( x \) by adding 1 to both sides: \( 1 = 2x \).
- Finally, divide by 2 to isolate x: \( x = \frac{1}{2} \).
Finding y-intercepts
The y-intercept is another critical component of understanding linear equations. It represents the point where a line crosses the y-axis. To determine this intercept, set the value of x to zero and solve the equation for y, since any point on the y-axis has an x-coordinate of zero.
Using the same equation: \[ 4y = 2x - 1 \]
To find the y-intercept:
Using the same equation: \[ 4y = 2x - 1 \]
To find the y-intercept:
- Set \( x = 0 \).
- This transforms the equation to \( 4y = -1 \).
- Now, divide each term by 4 to solve for \( y \): \( y = -\frac{1}{4} \).
Linear equations
Linear equations are fundamental in algebra and describe a straight line on a graph. They display relationships between two variables typically denoted as \( x \) and \( y \). A linear equation can be expressed in various forms, one of the most common being the slope-intercept form, \( y = mx + b \). Here, \( m \) is the slope, and \( b \) is the y-intercept.
In our exercise, the equation provided was:\[ 4y = 2x - 1 \]
Although not in the slope-intercept form initially, simple algebraic manipulation can rearrange it into \( y = \frac{1}{2}x - \frac{1}{4} \). From this form, we easily identify:
In our exercise, the equation provided was:\[ 4y = 2x - 1 \]
Although not in the slope-intercept form initially, simple algebraic manipulation can rearrange it into \( y = \frac{1}{2}x - \frac{1}{4} \). From this form, we easily identify:
- The slope is \( \frac{1}{2} \), showing how steep the line is.
- The y-intercept is \( -\frac{1}{4} \), the point where the line crosses the y-axis.
Other exercises in this chapter
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