Problem 6
Question
Find the value of each expression. $$ -x^{2}+3 x-5, \text { if } x=-2. $$
Step-by-Step Solution
Verified Answer
The value of the expression is -15.
1Step 1: Substitute the Value of x
Substitute \( x = -2 \) into the expression \( -x^2 + 3x - 5 \). This step involves replacing every instance of \( x \) in the expression with \(-2\). Thus, the expression becomes:\[ -(-2)^2 + 3(-2) - 5 \].
2Step 2: Simplify the Squared Term
Calculate \((-2)^2\). Squaring \(-2\) gives you:\[ (-2)^2 = 4 \].Substitute this back into the expression, which now becomes:\[ -4 + 3(-2) - 5 \].
3Step 3: Simplify the Multiplication
Calculate the term \(3(-2)\). Multiplying gives:\[ 3(-2) = -6 \].Substitute this into the expression, which now reads:\[ -4 - 6 - 5 \].
4Step 4: Perform Addition and Subtraction
Carefully perform the addition and subtraction from left to right:First, compute \(-4 - 6 = -10\).Then, subtract 5: \(-10 - 5 = -15\).Therefore, the expression evaluates to \(-15\).
Key Concepts
Substitution in AlgebraOrder of OperationsNegative Numbers in Algebra
Substitution in Algebra
Substitution in algebra is a fundamental skill. It's the process of replacing variables with given values. In this exercise, we had to substitute the value of \( x = -2 \) into the algebraic expression \( -x^2 + 3x - 5 \). To do this accurately, replace every occurrence of \( x \) in the expression with \(-2\). You should be careful to use parenthesis around the number being substituted, especially when dealing with negative numbers or powers. For instance, \( (-2)^2 \) ensures that the negative stays intact until the exponent is applied. Substituting helps transform complex expressions into simpler arithmetic operations, allowing you to solve algebraic problems with ease. Here, substitution turns the expression \( -x^2 + 3x - 5 \) into a series of calculations that are easier to tackle.
Order of Operations
To evaluate any algebraic expression correctly, you must follow the order of operations. This means adhering to the sequence of calculations prescribed by PEMDAS/BODMAS:
- P/B - Parentheses/Brackets first
- E/O - Exponents/Orders (i.e., powers and square roots, etc.)
- MD/DM - Multiplication and Division (left-to-right)
- AS - Addition and Subtraction (left-to-right)
Negative Numbers in Algebra
Negative numbers can introduce an additional level of complexity in algebraic expressions, but understanding them can simplify the process. When substituting and manipulating negative values, careful attention to signs is critical. In this exercise, substituting a negative value, \( x = -2 \), involves several steps where negative numbers affect both squaring and multiplication. For example, \((-2)^2\) results in \(4\) because the negative sign is squared along with the number. However, \(3(-2)\) multiplies the 3 and the \(-2\) directly, resulting in \(-6\). In subtraction, such as \(-4 - 6\), think of it as a progression deeper into the negatives on a number line, resulting in \(-10\). Always double-check signs through each step. A small mistake with a negative sign can lead to an incorrect answer. By understanding how negative numbers interact with different operations, you can navigate such expressions more confidently.
Other exercises in this chapter
Problem 6
For problems \(57-140\), solve each equation. $$ 5 x=25 $$
View solution Problem 6
What number decreased by nine is fifteen?
View solution Problem 6
Use the multiplication/division property of equality to solve each equation. Be sure to check each solution. $$ -k=-2 $$
View solution Problem 6
$$y+9=4$$
View solution