Problem 6
Question
Find the quotient in each case by replacing the divisor by its reciprocal and multiplying. $$8 \div\left(-\frac{3}{4}\right)$$
Step-by-Step Solution
Verified Answer
The quotient is \( -\frac{32}{3} \).
1Step 1: Identify the Dividend and Divisor
In the expression \( 8 \div \left(-\frac{3}{4}\right) \), the number 8 is the dividend and \( -\frac{3}{4} \) is the divisor.
2Step 2: Find the Reciprocal of the Divisor
The reciprocal of a number is found by exchanging the numerator and the denominator. Therefore, the reciprocal of \( -\frac{3}{4} \) is \( -\frac{4}{3} \).
3Step 3: Replace Division with Multiplication
Change the division operation to multiplication by replacing the divisor with its reciprocal. So, the expression \( 8 \div \left(-\frac{3}{4}\right) \) becomes \( 8 \times \left(-\frac{4}{3}\right) \).
4Step 4: Multiply the Numbers Together
Multiply 8 by \( -\frac{4}{3} \). First multiply the numerators: \( 8 \times -4 = -32 \). Then divide by the denominator: \( \frac{-32}{3} \).
5Step 5: Simplify the Result
The fraction \( \frac{-32}{3} \) is already in its simplest form, as the numerator 32 and the denominator 3 have no common factors other than 1.
Key Concepts
ReciprocalMultiplication of FractionsSimplifying Fractions
Reciprocal
When we talk about the reciprocal of a number, we mean a particular version of the number where you flip its numerator and denominator. Imagine you have a fraction like \( \frac{a}{b} \). The reciprocal would be \( \frac{b}{a} \). For whole numbers like 5, you can think of them as \( \frac{5}{1} \), making the reciprocal \( \frac{1}{5} \).
Reciprocals play a crucial role in division, especially with fractions. Here is why:
Reciprocals play a crucial role in division, especially with fractions. Here is why:
- When you divide by a fraction, you're actually multiplying by its reciprocal.
- Finding reciprocals allows you to transform a division problem into a multiplication problem, which is often easier to handle.
Multiplication of Fractions
Multiplication of fractions might sound tricky at first, but it’s quite systematic. When you multiply two fractions like \( \frac{a}{b} \times \frac{c}{d} \), you follow a simple rule: multiply the numerators together and the denominators together.
Here’s a step-by-step guide on how to do it:
Here’s a step-by-step guide on how to do it:
- Multiply the Numerators: Simply multiply the top numbers (numerators) of the fractions. For example, in our exercise, 8 was multiplied by -4 to get -32.
- Multiply the Denominators: For whole numbers like 8, consider them as fractions like \( \frac{8}{1} \). Hence, multiply the denominator of the fraction (in this case, 1) by the other denominator (3), resulting in 3.
Simplifying Fractions
Simplifying fractions involves making a fraction as simple as possible. A fraction is simplified when the numerator and denominator have no other common factors except 1.
Here's how you can simplify fractions when necessary:
Here's how you can simplify fractions when necessary:
- Find the Greatest Common Factor (GCF): Check for the highest number that can divide both the numerator and denominator without leaving a remainder.
- Divide Both Terms: Use the GCF to divide both the numerator and denominator to reduce the fraction.
- Simplifications in Extreme Cases: Sometimes, such as in our exercise with \( \frac{-32}{3} \), a fraction is already in its simplest form. Here, the GCF of 32 and 3 is 1.
Other exercises in this chapter
Problem 6
Write your answers as proper fractions or mixed numbers, not as improper fractions. Find the following products. (Multiply.) $$4 \frac{7}{10} \cdot 3 \frac{1}{1
View solution Problem 6
Find each of the following products. (Multiply.) $$-\frac{4}{7} \cdot \frac{7}{4}$$
View solution Problem 6
Find the following sums and differences, and reduce to lowest terms. (Add or subtract as indicated.) $$-\frac{4}{9}+\frac{7}{9}$$$
View solution Problem 6
Identify each of the numbers below as either a prime number or a composite number. For those that are composite, give at least one divisor (factor) other than t
View solution