Problem 6
Question
Find the \(n\)th term of the geometric sequence with given first term \(a\) and common ratio \(r .\) What is the fourth term? $$ a=-6, \quad r=3 $$
Step-by-Step Solution
Verified Answer
The fourth term is -162.
1Step 1: Understand the formula for the nth term
For any geometric sequence, the formula for the nth term is given by \( a_n = a \cdot r^{(n-1)} \), where \( a \) is the first term and \( r \) is the common ratio.
2Step 2: Plug in the values for the nth term
We are asked to find the fourth term of the sequence, so we'll use \( n = 4 \). Plugging the values into the formula, we get \( a_4 = -6 \cdot 3^{(4-1)} \).
3Step 3: Simplify the exponent
Simplify the exponent by calculating \( 4-1 = 3 \). Then the expression becomes \( a_4 = -6 \cdot 3^3 \).
4Step 4: Calculate the common ratio raised to the power
Calculate \( 3^3 \), which is \( 27 \). So we can substitute this back into our expression: \( a_4 = -6 \cdot 27 \).
5Step 5: Calculate the nth term
Perform the multiplication: \( -6 \times 27 = -162 \). Therefore, the fourth term \( a_4 \) in the geometric sequence is \(-162\).
Key Concepts
Understanding the nth Term Formula in Geometric SequencesThe Importance of the Common RatioSteps in Sequence Calculation
Understanding the nth Term Formula in Geometric Sequences
In geometric sequences, each term is derived from the previous one by multiplying with a constant known as the "common ratio". To efficiently find any term in the sequence, we use the nth term formula. The formula is:
\[ a_n = a \cdot r^{(n-1)}\]
Here, \(a_n\) is the nth term we want to calculate, \(a\) is the first term, and \(r\) is the common ratio. The expression \((n-1)\) is used as the exponent of \(r\) because the first term is already \(a\), and the multiplication starts from the second term. Understanding this formula allows us to jump directly to any position within the sequence without listing all preceding terms. It is both a time-saver and a tool for unlocking the inherent structure of geometric sequences.
\[ a_n = a \cdot r^{(n-1)}\]
Here, \(a_n\) is the nth term we want to calculate, \(a\) is the first term, and \(r\) is the common ratio. The expression \((n-1)\) is used as the exponent of \(r\) because the first term is already \(a\), and the multiplication starts from the second term. Understanding this formula allows us to jump directly to any position within the sequence without listing all preceding terms. It is both a time-saver and a tool for unlocking the inherent structure of geometric sequences.
The Importance of the Common Ratio
The common ratio is a crucial element in any geometric sequence. Denoted as \(r\), it represents the factor by which each term is multiplied to yield the next term. If you know the first term and the common ratio, you can determine the entire sequence.
Imagine a sequence starts at \(-6\) and has a common ratio of \(3\). This means that each following term is three times the previous one:
Imagine a sequence starts at \(-6\) and has a common ratio of \(3\). This means that each following term is three times the previous one:
- First term \((a)\): \(-6\)
- Second term: \(-6 \cdot 3 = -18\)
- Third term: \(-18 \cdot 3 = -54\), and so on.
- If \(r > 1\), the sequence grows.
- If \(0 < r < 1\), the sequence diminishes.
- If \(r = 0\), all terms become zero.
- A negative \(r\) means the terms alternate in sign.
Steps in Sequence Calculation
Calculating terms in a geometric sequence involves several clear steps, which become straightforward once you understand the fundamentals:
- Identify Known Values: Start by finding the first term \(a\) and the common ratio \(r\).
- Apply the nth Term Formula: Use \( a_n = a \cdot r^{(n-1)} \) for the term you are interested in.
- Simplify the Exponent: Calculate \((n-1)\) and use the result as the exponent for \(r\).
- Evaluate the Power of the Common Ratio: Raise \(r\) to the power of \((n-1)\) to find how much larger or smaller it becomes.
- Compute the nth Term: Multiply the result from the previous step by the first term \(a\) to find \(a_n\).
Other exercises in this chapter
Problem 6
Saving How much money should be invested every quarter at 10\(\%\) per year, compounded quarterly, in order to have \(\$ 5000\) in 2 years?
View solution Problem 6
Use mathematical induction to prove that the formula is true for all natural numbers n. $$1 \cdot 3+2 \cdot 4+3 \cdot 5+\cdots+n(n+2) =\frac{n(n+1)(2 n+7)}{6}$$
View solution Problem 6
5-8 Find the \(n\)th term of the arithmetic sequence with given first term \(a\) and common difference \(d .\) What is the 10th term? $$a=-6, d=3$$
View solution Problem 6
Find the first four terms and the 100th term of the sequence. \(a_{n}=\frac{1}{n^{2}}\)
View solution