Problem 6
Question
Find the domain of each rational function. $$h(x)=\frac{x+8}{x^{2}-64}$$
Step-by-Step Solution
Verified Answer
The domain of the function \(h(x)=\frac{x+8}{x^{2}-64}\) is \(x \in (-\infty,-8) \cup (-8,8) \cup (8,\infty)\).
1Step 1: Identify the Denominator
In the function \(h(x)=\frac{x+8}{x^{2}-64}\), the denominator is \(x^{2}-64\).
2Step 2: Solve the Denominator for Zero
Set the denominator equal to zero and solve for x. This gives the equation \(x^{2}-64 = 0\). Solving this equation yields \(x = 8\) and \(x = -8\).
3Step 3: Exclude these Values from the Domain
The domain of a function is all possible x-values, excluding any values that would result in the function being undefined. In this case, since \(x=8\) and \(x=-8\) would cause the denominator of the function to be zero, these values are excluded from the domain. Therefore, the domain is \(x \in (-\infty,-8) \cup (-8,8) \cup (8,\infty) \).
Other exercises in this chapter
Problem 5
Divide using long division. State the quotient, \(q(x),\) and the remainder, \(r(x)\). $$ \left(6 x^{3}+7 x^{2}+12 x-5\right) \div(3 x-1) $$
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Solve each polynomial inequality in Exercises \(1-42\) and graph the solution set on a real number line. Express each solution set in interval notation. $$ x^{2
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In Exercises \(1-8,\) use the Rational Zero Theorem to list all possible rational zeros for each given function. $$ f(x)-3 x^{4}-11 x^{3}-3 x^{2}-6 x+8 $$
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Divide using long division. State the quotient, \(q(x),\) and the remainder, \(r(x)\). $$ \left(6 x^{3}+17 x^{2}+27 x+20\right) \div(3 x+4) $$
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