Problem 6
Question
Find the distance between each pair of points. If necessary, round answers to two decimals places. $$ (0,0) \text { and }(3,-4) $$
Step-by-Step Solution
Verified Answer
The distance between the points (0,0) and (3,-4) is 5 units.
1Step 1: Identify the given points
The two points given are \((0,0)\) and \((3,-4)\). The coordinates for the first point, \((0,0)\), are \(x_1 = 0\) and \(y_1 = 0\). The coordinates for the second point, \((3,-4)\), are \(x_2 = 3\) and \(y_2 = -4\).
2Step 2: Substitute into the Distance formula
Next substitute the identified coordinates into the distance formula \(d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\). This gives \(d = \sqrt{(3-0)^2 + (-4-0)^2} = \sqrt{(3)^2 + (-4)^2}\).
3Step 3: Simplify and Compute
Now square the differences, and then add the squares: \(d = \sqrt{3^2 + -4^2} = \sqrt{9 + 16} = \sqrt{25}\). The last step is to take the square root of 25, which gives \(d = 5\).
Key Concepts
Cartesian CoordinatesDistance CalculationMathematical Computation
Cartesian Coordinates
In mathematics, the Cartesian coordinate system is a two-dimensional plane where each point is determined by an ordered pair of numbers. These numbers are known as the coordinates, written as \((x, y)\). The first number, \(x\), represents the horizontal position, while the second number, \(y\), indicates the vertical position. The origin of the system is the point \((0, 0)\), where the horizontal and vertical axes intersect.
Understanding this system is essential for locating points on the plane. For instance, the first point \((0, 0)\) stays at the origin, and the second point \((3, -4)\) is three units to the right and four units down.
Understanding this system is essential for locating points on the plane. For instance, the first point \((0, 0)\) stays at the origin, and the second point \((3, -4)\) is three units to the right and four units down.
- The Cartesian plane consists of two axes: the x-axis (horizontal) and the y-axis (vertical).
- Coordinates are written as \((x, y)\), with \(x\) determining the position along the x-axis and \(y\) determining the position along the y-axis.
- Points can have positive or negative values based on their position relative to the origin.
Distance Calculation
The distance formula is a handy tool for finding the distance between two points on the Cartesian plane. It stems from the Pythagorean theorem, which relates the sides of a right triangle: \(a^2 + b^2 = c^2\).
To find the distance between two points \((x_1, y_1)\) and \((x_2, y_2)\), we use the formula \(d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\).
To find the distance between two points \((x_1, y_1)\) and \((x_2, y_2)\), we use the formula \(d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\).
- First, calculate the difference between the x-coordinates: \(x_2 - x_1\).
- Next, calculate the difference between the y-coordinates: \(y_2 - y_1\).
- Square these differences to ensure they are non-negative.
- Add the squared values together and take the square root of the sum.
Mathematical Computation
To effectively use mathematical formulas like the distance formula, it's important to break down each computation into manageable steps. Let's walk through the procedure again, using our points \((0, 0)\) and \((3, -4)\):
- Identify the points, knowing \(x_1 = 0\), \(y_1 = 0\) and \(x_2 = 3\), \(y_2 = -4\).
- Plug these values into the formula: \(d = \sqrt{(3-0)^2 + (-4-0)^2}\).
- Calculate: \((3-0)^2 = 9\) and \((-4-0)^2 = 16\).
- Add these results: \(\sqrt{9 + 16} = \sqrt{25}\).
- Finally, compute the square root: \(d = 5\).
Other exercises in this chapter
Problem 6
Find \(f(g(x))\) and \(g(f(x))\) and determine whether each pair of functions \(f\) and \(g\) are inverses of each other. $$f(x)=3 x-7 \text { and } g(x)=\frac{
View solution Problem 6
In Exercises \(1-8,\) determine whether each relation is a function. Give the domain and range for each relation. $$\\{(-7,-7),(-5,-5),(-3,-3),(0,0)\\}$$
View solution Problem 7
Begin by graphing the standard quadratic function, \(f(x)=x^{2} .\) Then use transformations of this graph to graph the given function. $$ h(x)=(x-2)^{2}+1 $$
View solution Problem 7
Find the slope of the line passing through each pair of points or state that the slope is undefined. Then indicate whether the line through the points rises, fa
View solution