Problem 6
Question
Find a polynomial \(f(x)\) of degree 3 that has the indicated zeros and satisfies the given condition. $$-3 i, 3 i, 4 ; \quad f(-1)=50$$
Step-by-Step Solution
Verified Answer
The polynomial is \(f(x) = -x^3 + 4x^2 - 9x + 36\).
1Step 1: Identify Roots and Form the Base Polynomial
The given roots are \(-3i, 3i,\) and \(4\). Since \(-3i\) and \(3i\) are complex conjugates, they ensure the coefficients remain real. The polynomial can be written as \[ f(x) = (x + 3i)(x - 3i)(x - 4) \]The roots of the polynomial provide the factors: \(x + 3i\), \(x - 3i\), and \(x - 4\).
2Step 2: Simplify the Complex Roots Product
First, simplify the product of the complex conjugate roots:\( (x + 3i)(x - 3i) = x^2 + (3i)x - (3i)x - (3i)^2 = x^2 + 9 \).Thus, the product of the complex conjugates is a real quadratic term.
3Step 3: Expand to Form the Polynomial
Now, substitute the simplified quadratic back to form the polynomial:\[ f(x) = (x^2 + 9)(x - 4) \]Multiply these binomials to get:\[ f(x) = (x^2 + 9)x - (x^2 + 9)4 = x^3 + 9x - 4x^2 - 36 \]Which simplifies to:\[ f(x) = x^3 - 4x^2 + 9x - 36 \].
4Step 4: Adjust Polynomial for Given Condition
Substitute \(x = -1\) into the polynomial \(f(x) = x^3 - 4x^2 + 9x - 36\) and equate it to 50:\[ (-1)^3 - 4(-1)^2 + 9(-1) - 36 = 50 \]Calculate the left side:\[ -1 - 4 - 9 - 36 = -50 \]The equation becomes \(-50 = a \times 50\). Hence, \(a = -1\).
5Step 5: Finalize the Polynomial
Multiply the polynomial by \(-1\) to satisfy the condition:\[ f(x) = -1(x^3 - 4x^2 + 9x - 36) = -x^3 + 4x^2 - 9x + 36 \]. Thus, the polynomial that satisfies all the conditions is \[ f(x) = -x^3 + 4x^2 - 9x + 36 \].
Key Concepts
Complex Conjugate RootsDegree of a PolynomialReal Coefficients
Complex Conjugate Roots
When dealing with polynomial functions, especially with real coefficients, complex conjugate roots become an important aspect. A complex conjugate pair consists of two roots that are mirror images of each other over the real number line.
For example, the numbers \(3i\) and \(-3i\) are complex conjugates.
Here is why they matter:
For example, the numbers \(3i\) and \(-3i\) are complex conjugates.
Here is why they matter:
- Conjugate pairs help maintain real coefficients in the polynomial.
- Their product results in a quadratic expression with real coefficients.
- In our context, when multiplying conjugates \((x + 3i)(x - 3i)\), the result simplifies to \(x^2 + 9\), showcasing the significance of complex conjugates in simplifying polynomial equations.
Degree of a Polynomial
The degree of a polynomial is a key feature in understanding its behavior and properties. It’s defined as the highest exponent of the variable in the polynomial expression.
A polynomial of degree \(n\) means it can have up to \(n\) roots (some of which may be complex), and it can closely represent curves through \(n\) points.
A polynomial of degree \(n\) means it can have up to \(n\) roots (some of which may be complex), and it can closely represent curves through \(n\) points.
- For instance, in the exercise, the polynomial degree is 3, demonstrating it can potentially have up to 3 roots.
- This degree indicates the curve's overall shape and direction.
- Higher degree polynomials are more flexible in their shape, allowing for curves, bends, and changes in direction.
Real Coefficients
Real coefficients in a polynomial mean all the numerical factors multiplying powers of \(x\) are real numbers, as opposed to being complex. This is crucial for simplifying computations and understanding the polynomial's behavior on a real graph.
- With real coefficients, the graph of the polynomial will have symmetry properties that make it easier to visualize and analyze.
- Given that complex roots must appear in conjugate pairs, only polynomials with real coefficients ensure complex roots don't appear as standalone roots.
- In the exercise above, starting with real coefficients and maintaining them through various steps confirms consistency and readability of the polynomial.
Other exercises in this chapter
Problem 6
A polynomial \(f(x)\) with real coefficients and leading coefficient 1 has the given zero(s) and degree. Express \(f(x)\) as a product of linear and quadratic p
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Exer. 1-12: Express the statement as a formula that involves the given variables and a constant of proportionallty \(k,\) and then determine the value of \(k\)
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Use the Intermediate value theorem to show that \(f\) has a zero between \(a\) and \(b\) $$f(x)=2 x^{3}+5 x^{2}-3 ; \quad a=-3, \quad b=-2$$
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Find the quotient and remainder if \(f(x)\) is divided by \(p(x)\). $$f(x)=-5 x^{2}+3 ; \quad p(x)=x^{3}-3 x+9$$
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