Problem 6
Question
Express the given quantity in terms of the indicated variable. The total rent paid for an apartment if the rent is \(\$ 795\) a month; \(n=\) number of months
Step-by-Step Solution
Verified Answer
The total rent is \( 795n \).
1Step 1: Understanding the Problem
We need to find an expression that represents the total rent paid over a period of months. The monthly rent is given as \( \$795 \) per month, and the number of months is represented by \( n \).
2Step 2: Identifying Known and Unknown Variables
The known variable is the rent per month, which is \( 795 \). The unknown is the total rent paid, and the variable \( n \) represents the number of months.
3Step 3: Applying the Multiplication Concept
The total rent paid is calculated by multiplying the monthly rent by the number of months the rent is paid. Thus, the total rent is \( 795 \times n \).
4Step 4: Expressing the Quantity
Finally, the total rent paid, expressed in terms of \( n \), is given by the expression \( 795n \).
Key Concepts
Variables and ConstantsMultiplication in AlgebraSolving Problems with Equations
Variables and Constants
In algebra, it's important to understand the difference between variables and constants. A variable is a symbol, like \( n \), that represents numbers that can change or vary. In our exercise, \( n \) is the variable, standing for the number of months. This is because the number of months can differ depending on the situation.
On the other hand, a constant is a fixed value that does not change. In our example, \( 795 \) is a constant because the rent per month is always $795. Constants are often used to represent quantities that remain the same across different scenarios. To put it simply:
On the other hand, a constant is a fixed value that does not change. In our example, \( 795 \) is a constant because the rent per month is always $795. Constants are often used to represent quantities that remain the same across different scenarios. To put it simply:
- Variables: Changeable parts of an expression (e.g., the number of months \( n \)).
- Constants: Unchanging parts of an expression (e.g., the monthly rent \( 795 \)).
Multiplication in Algebra
When you tackle algebraic problems, multiplying variables and constants is a common task. This exercise asked us to find the total rent by multiplying the rent per month by the number of months, which means using multiplication. We calculate the total rent by multiplying the constant \( 795 \) and the variable \( n \). The result is the expression \( 795n \).
This demonstrates that simple arithmetic operations, like multiplication, are integrated into algebraic expressions. Notably, when multiplying a number by a variable, it's common to just write them side by side—no need for the multiplication sign. Thus, 795 times \( n \) is written as \( 795n \). This makes the expression neat and compact and is a standard practice in algebraic notation.
This demonstrates that simple arithmetic operations, like multiplication, are integrated into algebraic expressions. Notably, when multiplying a number by a variable, it's common to just write them side by side—no need for the multiplication sign. Thus, 795 times \( n \) is written as \( 795n \). This makes the expression neat and compact and is a standard practice in algebraic notation.
Solving Problems with Equations
Solving problems using equations is all about creating connections between known and unknown quantities. In the given problem, we created an algebraic expression \( 795n \) to represent the total rent over \( n \) months. This equation allows us to solve for the total cost if \( n \) is specified.
Having an equation or expression like \( 795n \) makes it easy to quickly calculate the total rent for any number of months by substituting the variable \( n \) with a specific number. For example:
Having an equation or expression like \( 795n \) makes it easy to quickly calculate the total rent for any number of months by substituting the variable \( n \) with a specific number. For example:
- If \( n = 2 \), then the total rent equals \( 795 \times 2 = 1590 \).
- If \( n = 6 \), then the total rent equals \( 795 \times 6 = 4770 \).
Other exercises in this chapter
Problem 5
\(1-8\) Determine whether the given value is a solution of the equation. $$ \begin{array}{l}{2 x^{1 / 3}-3=1} \\ {\begin{array}{ll}{\text { (a) } x=-1} & {\text
View solution Problem 6
Solve the equation. $$ |2 x-3|=7 $$
View solution Problem 6
\(1-8=\) Let \(S=\left\\{-2,-1,0, \frac{1}{2}, 1, \sqrt{2}, 2,4\right\\} .\) Determine which elements of \(S\) satisfy the inequality. $$ -2 \leq 3-x
View solution Problem 6
Find the real and imaginary parts of the complex number. $$ -\frac{1}{2} $$
View solution