Problem 6
Question
Determine whether the given point lies on the graph of the equation, as in Example \(1 .\) Note: You are not asked to draw the graph. $$(a-1, a+1) ; y=x+2$$
Step-by-Step Solution
Verified Answer
Yes, the point lies on the line.
1Step 1: Understand the Problem
We need to check if the point \((a - 1, a + 1)\) lies on the line described by the equation \(y = x + 2\). To do this, substitute \(x = a - 1\) and \(y = a + 1\) into the equation.
2Step 2: Substitute the x-value
Substitute \(x = a - 1\) into the equation \(y = x + 2\). This gives us an expression for \(y\): \[ y = (a - 1) + 2. \]
3Step 3: Simplify the y-expression
Simplify the expression \(y = (a - 1) + 2\) to find the value of \(y\). \[ y = a - 1 + 2 = a + 1. \]
4Step 4: Substitute and Verify y-value
Now check if the simplified value \(y = a + 1\) matches the y-coordinate of the point \((a - 1, a + 1)\). Since both values are \(a + 1\), the point satisfies the equation.
5Step 5: Conclusion
Since substituting \(x = a - 1\) into the equation yielded \(y = a + 1\), the point \((a - 1, a + 1)\) indeed lies on the line \(y = x + 2\).
Key Concepts
Coordinate GeometrySubstitution MethodVerification of Points
Coordinate Geometry
Coordinate geometry, also known as analytic geometry, is a branch of mathematics that uses algebraic equations to represent geometric shapes. It's a fascinating way to describe the spatial relationships between points, lines, and figures on a plane. In coordinate geometry, every point is defined by a pair of numbers: its coordinates. These coordinates tell you exactly where a point lies on the two-dimensional plane.
In a simple coordinate plane, the horizontal and vertical axes are called the x-axis and y-axis, respectively. The point where they intersect is the origin, labeled as \(0, 0\). The position of any point is told by its coordinates, specifically \(x, y\). Lines in this system can be described with equations, where y often depends on changes in x.
In a simple coordinate plane, the horizontal and vertical axes are called the x-axis and y-axis, respectively. The point where they intersect is the origin, labeled as \(0, 0\). The position of any point is told by its coordinates, specifically \(x, y\). Lines in this system can be described with equations, where y often depends on changes in x.
- The equation of a line is often written in the form \(y = mx + b\), where \m\ is the slope and \b\ is the y-intercept.
- This slope-intercept form helps us to understand how the line moves across the plane and where it crosses the y-axis.
Substitution Method
The substitution method is a straightforward yet effective technique for solving equations, particularly those that involve checking points on a line. Here, we apply it to determine whether a certain point lies on a given line by substituting the point's coordinates into the line's equation.
First, identify the given point's coordinates. For example, with the point \(a - 1, a + 1\), \a - 1\ is your x-value and \a + 1\ is your y-value. Your task is to substitute these values into the line's equation, which is \(y = x + 2\) in this exercise.
First, identify the given point's coordinates. For example, with the point \(a - 1, a + 1\), \a - 1\ is your x-value and \a + 1\ is your y-value. Your task is to substitute these values into the line's equation, which is \(y = x + 2\) in this exercise.
- Substitute the x-coordinate into the equation: Replace \(x\) with \(a - 1\). This becomes \(y = (a - 1) + 2\).
- Simplify the result: In this example, simplifying gives \(y = a + 1\).
Verification of Points
Verification of points on a geometric line involves confirming that the coordinates of a given point satisfy the equation of that line. This process helps ensure that any point you claim is on the line, indeed, fulfills the line's properties.
The process starts by using the substitution method, as explained earlier. After substituting the point's x-coordinate into the equation and simplifying, compare the resulting y-value to the y-coordinate of the point in question.
The process starts by using the substitution method, as explained earlier. After substituting the point's x-coordinate into the equation and simplifying, compare the resulting y-value to the y-coordinate of the point in question.
- If both y-values match, the point lies on the line.
- If they don't match, the point is not on the line.
Other exercises in this chapter
Problem 5
Evaluate each expression. $$|-1+3|$$
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Determine whether the given value is a solution of the equation. Verify that the numbers \(1+\sqrt{5}\) and \(1-\sqrt{5}\) both satisfy the equation \(x^{2}-2 x
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