Problem 6
Question
Determine whether the given ordered pair is a solution to the system of equations. $$ \begin{array}{l} 5 x-y=4 \\ x+6 y=2 \text { and }(4,0) \end{array} $$
Step-by-Step Solution
Verified Answer
The ordered pair \((4, 0)\) is not a solution to the system of equations.
1Step 1: Identify the variables in the ordered pair
The ordered pair given is \((4, 0)\). Here, \(x = 4\) and \(y = 0\). We will substitute these values into both equations of the system.
2Step 2: Substitute into the first equation
Substitute \(x = 4\) and \(y = 0\) into the first equation \(5x - y = 4\). This gives us \(5(4) - 0 = 20\). Since \(20 eq 4\), the ordered pair \((4, 0)\) does not satisfy the first equation.
3Step 3: Substitute into the second equation
Now, substitute \(x = 4\) and \(y = 0\) into the second equation \(x + 6y = 2\). This results in \(4 + 6(0) = 4\). Since \(4 eq 2\), the ordered pair \((4, 0)\) also does not satisfy the second equation.
4Step 4: Conclusion on whether it is a solution
Since the ordered pair \((4, 0)\) does not satisfy either equation in the system, it is not a solution to the system of equations.
Key Concepts
Understanding Ordered PairsExploring the Substitution MethodDetermining the Solution to Equations
Understanding Ordered Pairs
In mathematics, an *ordered pair* is a way to represent two elements that are related, typically in a two-dimensional space. It is written in the form \((x, y)\), where 'x' is the first element and 'y' is the second. Ordered pairs are often used in relation to graphs, where they indicate a point's position on the Cartesian plane.
In our exercise, the ordered pair given is \((4, 0)\), which specifies thex value as 4 and they value as 0. By substituting these values into each equation in the system, we determine if the pair is a solution to the equations.
- The first number (x-coordinate) shows the position along the horizontal axis (left-right).
- The second number (y-coordinate) shows the position along the vertical axis (up-down).
In our exercise, the ordered pair given is \((4, 0)\), which specifies thex value as 4 and they value as 0. By substituting these values into each equation in the system, we determine if the pair is a solution to the equations.
Exploring the Substitution Method
The *substitution method* is one of the techniques used to solve systems of equations. This method involves solving one of the equations for one variable in terms of another and then substituting this expression into the other equation.
Here's how it typically works:
Here's how it typically works:
- First, solve one of the equations for one variable.
- Then, substitute that expression into the other equation.
- Solve the resulting equation for the other variable.
- Finally, substitute back to find the first variable.
Determining the Solution to Equations
A *solution to a system of equations* is any set of values for the variables that make all equations in the system true simultaneously. In the case of two-variable systems like the one in our exercise, solutions are represented as ordered pairs.
To check if an ordered pair is a solution:
To check if an ordered pair is a solution:
- Substitute the values from the ordered pair into each equation of the system.
- If the substituted values make both equations true (the left and right side equal), then the ordered pair is a solution.
- If even one equation is false after substitution, the pair is not a solution to the system.
Other exercises in this chapter
Problem 6
For the following exercises, use the matrices below and perform the matrix addition or subtraction. Indicate if the operation is undefined. $$ A=\left[\begin{ar
View solution Problem 6
Find the decomposition of the partial fraction for the nonrepeating linear factors. \(\frac{5 x+16}{x^{2}+10 x+24}\)
View solution Problem 6
For the following exercises, find the decomposition of the partial fraction for the nonrepeating linear factors. $$\frac{5 x+16}{x^{2}+10 x+24}$$
View solution Problem 6
For the following exercises, solve the system of nonlinear equations using substitution. $$\begin{aligned} x+y &=4 \\ x^{2}+y^{2} &=9 \end{aligned}$$
View solution