Problem 6
Question
Determine whether each ordered triple is a solution to the system of linear equations. $$ \begin{array}{l} (5,2,2),(2,-1,1) \\ 2 x-3 y+3 z=10 \\ x-2 y-3 z=1 \\ 4 x-y+z=10 \end{array} $$
Step-by-Step Solution
Verified Answer
The ordered triple \((5, 2, 2)\) is not a solution; \((2, -1, 1)\) is a solution.
1Step 1: Introduce the Problem
We need to determine if the ordered triples \((5,2,2)\) and \((2,-1,1)\) are solutions to the system of linear equations given by: \(2x-3y+3z=10\), \(x-2y-3z=1\), and \(4x-y+z=10\). This means we need to substitute each of the triples into the equations and verify if they satisfy all the equations simultaneously.
2Step 2: Check Ordered Triple (5, 2, 2)
Substitute \(x=5\), \(y=2\), \(z=2\) into each equation:- First equation: \(2(5) - 3(2) + 3(2) = 10\). Simplifying gives: \(10 - 6 + 6 = 10\), which is true.- Second equation: \(5 - 2(2) - 3(2) = 1\). Simplifying gives: \(5 - 4 - 6 = -5\), which is false.- Third equation: \(4(5) - 2 + 2 = 10\). Simplifying gives: \(20 - 2 + 2 = 20\), which is false.
3Step 3: Conclude on Triple (5, 2, 2)
Since the ordered triple \((5, 2, 2)\) does not satisfy all of the equations (it fails the second and third equations), it is not a solution to the system of equations.
4Step 4: Check Ordered Triple (2, -1, 1)
Substitute \(x=2\), \(y=-1\), \(z=1\) into each equation:- First equation: \(2(2) - 3(-1) + 3(1) = 10\). Simplifying gives: \(4 + 3 + 3 = 10\), which is true.- Second equation: \(2 - 2(-1) - 3(1) = 1\). Simplifying gives: \(2 + 2 - 3 = 1\), which is true.- Third equation: \(4(2) - (-1) + 1 = 10\). Simplifying gives: \(8 + 1 + 1 = 10\), which is true.
5Step 5: Conclude on Triple (2, -1, 1)
Since the ordered triple \((2, -1, 1)\) satisfies all of the equations, it is a solution to the system of equations.
Key Concepts
Ordered TriplesSubstitution MethodSolution Verification
Ordered Triples
An ordered triple is a group of three numbers, usually written in parentheses, that represent coordinates in three-dimensional space. For instance, an ordered triple like \(5, 2, 2\) identifies a point in space where \(x = 5\), \(y = 2\), and \(z = 2\). In the context of solving systems of linear equations, each ordered triple is a potential solution that needs to satisfy all of the equations in the system.
- They serve as possible candidates to test against the equations.
- If an ordered triple makes each equation true when the values are substituted, it is a solution of the system.
Substitution Method
The substitution method is a technique used to check if potential solutions satisfy a set of equations. It involves replacing the variables in the equations with the proposed values from the ordered triple:
- Begin by substituting each individual value into each equation where those variables appear.
- Simplicity can help determine whether the equation holds true or false.
Solution Verification
Solution verification is the process of confirming if a set of values meets the requirements of each equation in the system. After we have substituted the values, we need to:
- Check each result to ensure it satisfies all the equations.
- Hence, confirm whether or not the values form a legitimate solution.
Other exercises in this chapter
Problem 6
Determine if \(B\) is the inverse matrix of \(A\) by calculating \(A B\) and \(B A\) $$ A=\left[\begin{array}{rrr} 1 & -1 & 1 \\ 0 & 1 & 0 \\ 1 & 1 & 2 \end{arr
View solution Problem 6
Represent the linear system by an augmented matrix, and state the dimension of the matrix. $$ \begin{array}{rr} x+2 y-z= & 2 \\ -2 x+y-2 z= & -3 \\ 7 x+y-z= & 7
View solution Problem 6
Evaluate the expression for the given \(f(x, y)\). $$ f(5,-2) \text { if } f(x, y)=6 y-\frac{1}{2} x $$
View solution Problem 7
Graph the solution set to the inequality. $$ 2 x+y>4 $$
View solution